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muktoham wrote: It does not resond to any of its functions like SetFileName, SetEnabled,Play.
Where are you getting these "functions" from?
Mark
Mark Salsbery
Microsoft MVP - Visual C++
"Go that way, really fast. If something gets in your way, turn."
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muktoham wrote: SetFileName
I think there is another function called SetURL(). call that function instead of the SetFileName().
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I got my answer through another forum, My approach and functions where right,my control seems to be not installed correctly because same code worked fine on another machine.
|| Lust Causes Sorrow ||
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Can i use and redistrubute GDI+ v1.1 with my application???
From Where can i download GDI+ V1.1?? Microsoft site still has old version for GDI+.
-- modified at 8:14 Tuesday 3rd July, 2007
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It's available on Vista+.
I thought I heard something about it being with .NET 3.x as well but I could have dreamed it
No, you can't redistribute it.
Mark
Mark Salsbery
Microsoft MVP - Visual C++
"Go that way, really fast. If something gets in your way, turn."
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I am porting a COM object from VC6.0 to Visual Studo 2005 and I get the following error:
error C2011: 'spcADO::CursorTypeEnum' : 'enum' type redefinition
The reason for this is that the file msado15.tlh gets generated in the DebugU directory AND the project directory.
Any idea how I can solve this?
Thanks,
Jerome
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Strange, #import doesn't generally do this. Have you tried quitting VS, removing the tlh/tli files, and doing a clean and build?
Steve S
Developer for hire
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Yes it was weird - I tried that indeed but it did not work.
I think it was caused by the fact that two cpp files had the same name. For some unknown reason, the obj files were generated incorrectly. I removed them from the project and re-added and it now works. Touch wood!
Thanks for your help anyway!
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My requirement is
If i select an item in a tree Control that Selected item's color of text should be changed.(or i want to recognize whether it is selected or not--some way to identify)So can you please tell me how to do it.
bhw
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Handle the NM_CUTOME draw message and put the following code inside it.
void TreeCtrlEx::OnCustomDraw( NMHDR* pNMHDR_i, LRESULT* pResult_o )
{
NMTVCUSTOMDRAW* pLVCD = reinterpret_cast<nmtvcustomdraw *="">( pNMHDR_i );
NMCUSTOMDRAW &nMcd = pLVCD->nmcd;
*pResult_o = CDRF_DODEFAULT;
switch( nMcd.dwDrawStage )
{
case CDDS_PREPAINT:
// Item prepaint notification.
*pResult_o = CDRF_NOTIFYITEMDRAW;
break;
case CDDS_ITEMPREPAINT:
{
// Set the color of the text according to its state.
HTREEITEM nRow = reinterpret_cast< HTREEITEM >( nMcd.dwItemSpec );
if( CDIS_SELECTED == ( nMcd.uItemState & CDIS_SELECTED ))
{
pLVCD->clrText = clrSelText;// Selected text color
pLVCD->clrTextBk = clrSelBk;// Selceted backgroung
}
else
{
pLVCD->clrText = clrNormal;// text color in normal state
pLVCD->clrTextBk = clrBk// bakck ground color in normal state
}
// Allow it to do the default painting.
*pResult_o = CDRF_DODEFAULT;
break;
}
default:
*pResult_o = CDRF_DODEFAULT;
break;
}
}
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Hi,
I have assigned a huge string of about 32800 chars to CString object, but i am getting this "error C2026: string too big, trailing characters truncated", does any one know how can i resolve it, or is there any work around?
Best Regards,
Mushq
Mushtaque Ahmed Nizamani
Software Engineer
Ultimus Pakistan
"English is my second language, so please don't mind if i do some grammatical or spelling mistakes in my messages."
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Can you tell me why you want to have this string? and what is it?
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There is a compiler limit on string literals of 2048 characters, so this has nothing to do with CString .
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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How do you create this string in the First Place. You hardly typed it by hand!
Anyways:
Try CString MyString;
MyString.GetBuffer(32000);
The problem occurs with items such as strings which are zero terminated. If the compiler does not find a 0 after a reasonable number of chars, ( and 2048 is a reasonable limit in most cases)the compiler decides that there must be a syntax error (forgotten a terminating ") etc.
LateNightsInNewry
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I have done an application in which i need to interact with 2 other systems using RS 232 cables.
Individually i am able to communicate with either systems but facing problems when executed and trying to interact with 2 systems simultaneously. The main reason for this is the I am using a Pentium 3 processor which is a must for me.Can anyone help me out to overcome this problem in pentium 3 processor.
NAVEEN
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naveen27gupta wrote: The main reason for this is the I am using a Pentium 3 processor
Why the above is the main reason?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Your not trying to just connect the PCs together like this are you?
PC 1 <---\
PC 2 <---|
PC 3 <---/
Just connect all 3 ports together... RxD to RxD to RxD etc.
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A simple question.
I define an array.How to calculate its length?
int[] arInt = { 1, 2, 3 ,4, 5 };
Thanks in advance.
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Peter, Chan wrote: int[] arInt = { 1, 2, 3 ,4, 5 };
The correct syntax should be:
int arInt[] = {....
int nSize = sizeof(arInt) / sizeof(int);
this is this.
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Then if it is a array of string.Should I write like this.
char * arLang[] = {"english", "chinese"};
int nSize = sizeof(arLang) / sizeof(char);
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Nope
Then you get the number of char's in the array, not the number of strings
You can't count it this way, because each string has a different lenght.
You can determine the length of arLang, then loop on it and count the occurence of \0 (End of a String)
So you get the number of strings in the array, if i tell no mistakes
Good luck
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No, it can't be done with multi-dimensional arrays.
You can only do it with single-dimensional arrays like:
char arLang[] = {"english"};
And the length will be 8 bytes.
And whenever you get the operator * anywhere, you just can't be sure of the size.
But you can write:
int nSize1 = strlen(arLang[0]) + 1;<br />
int nSize2 = strlen(arLang[1]) + 1;
etc.
this is this.
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Peter, Chan wrote: int nSize = sizeof(arLang) / sizeof(char);
Mistake!
change as follows:
int nSize = sizeof(arLang) / sizeof(char *);
or (better):
int nSize = sizeof(arLang) / sizeof(arLang[0]);
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Peter, Chan wrote: I define an array.How to calculate its length
Did you have a look at the sizeof()
Somethings seem HARD to do, until we know how to do them.
_AnShUmAn_
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