C / C++ / MFC Discussion Boards

sweep1235-Aug-04 6:39

5-Aug-04 6:39

No problem with the float;

Just do

extern float flt1;

in any units you want to use it.

My problem is with the union, how do I reference it in another unit?

extern <type=????> test_26_tt1;

I have lots of bit fields which I form into a buffer via the union (same memory, but two names).

Re: make this variable global

Jaime Stuardo5-Aug-04 9:21

Jaime Stuardo

5-Aug-04 9:21

the question I did was not for the float, but for the test_26_tt1. What problem did you have with it? Variable isn'r recognize? did you receive a compilation error?

Jaime

Re: make this variable global

sweep1235-Aug-04 22:19

sweep123

5-Aug-04 22:19

When you form a union you can now use the data. i.e. two variables have been declared.

// Form a union between the message structure and a buffer<br />
union<br />
{<br />
TEST_26_TT1 message_data;<br />
unsigned short buffer[32];<br />
}test_26_tt1;

in the code you can do the following:-

test_26_tt1.buffer[3] = 0xFF;

My question was how do you refer to this data in another unit using the extern

If I use the statement

extern test_26_tt1;
and refer to it as

unsigned short x = test_26_tt1.buffer[2]; in another unit I get the error:-

c:\Example\Database.cpp(101): error C2228: left of '.buffer' must have class/struct/union type.

Its a question of type, as I said with float

extern float flt1;
extern ???? test_26_tt1;

Re: make this variable global

Henry miller5-Aug-04 7:48

Henry miller

5-Aug-04 7:48

You haven't created a variable yet, just a type

extern TEST_26_tt1 my_global_variable;

The extern is sometimes optional, but the same rules apply as for float.

Re: make this variable global

Grahamfff6-Aug-04 11:07

Grahamfff

6-Aug-04 11:07

When you form a union you have declared a variable; i.e.
// Form a union between the message structure and a buffer

union<br />
{<br />
TEST_26_TT1 message_data;<br />
unsigned short buffer[32];<br />
}test_26_tt1;

in the code you can do the following:-

test_26_tt1.buffer[3] = 0xFF;

But how do you use the variable test_26_tt1 in another unit.

With a float you can use:

extern float flt;
But how do you do the same with test_26_tt1.

<br />
extern ???? test_26_tt1;

What type do you use.

grahamfff

Re: make this variable global

Henry miller6-Aug-04 11:30

Henry miller

6-Aug-04 11:30

I had to look up union again...

I think

extern union
{
TEST_26_TT1 message_data;
unsigned short buffer[32];
} test_26_tt1;

will work. Or make your union a full type like this:

union test_26_union
{
TEST_26_TT1 message_data;
unsigned short buffer[32];
}

extern test_26_union test_26_tt1;

Depending on if you want to use this union elsewhere.

Let me know what works, I've never used unions in C++, but I can think of a few times where it might be useful.

Re: make this variable global

sweep1238-Aug-04 22:12

sweep123

8-Aug-04 22:12

Its Monday morning here in the UK, just tried out your suggestion:-

extern union <br />
{<br />
TEST_26_TT1 message_data;<br />
unsigned short buffer[32];<br />
} test_26_tt1;

It worked OK.

I did try the other method you suggested:-

union test_26_union <br />
{<br />
TEST_26_TT1 message_data;<br />
unsigned short buffer[32];<br />
};<br />
<br />
extern test_26_union test_26_tt1;

But I kept getting the following error:-

My_Example error LNK2005: "union test_26_union test_26_tt1" (?test_26_tt1@@test_26_union@@A) already defined in Database2.obj

But thanks for your post.

How to convert a function into main() instead of wmain() ?

Anonymous5-Aug-04 0:48

Anonymous

5-Aug-04 0:48

Hey
In MSDN there is one function called "NetShareEnum", They have also provided example for it. I want to write same exapmle usign main() instead of wmain(). Plz any one can help...? I am also writing whole code here. Plz you also write whole code changin it to mian()...Thanking you....
--------------------------------------------------------------
#define UNICODE
#include <windows.h>
#include <stdio.h>
#include <lm.h>

void wmain( int argc, TCHAR *lpszArgv[ ])
{
PSHARE_INFO_502 BufPtr,p;
NET_API_STATUS res;
LPTSTR lpszServer = NULL;
DWORD er=0,tr=0,resume=0, i;

switch(argc)
{
case 2:
lpszServer = lpszArgv[1];
break;
default:
printf("Usage: NetShareEnum <servername>\n");
return;
}
//
// Print a report header.
//
printf("Share: Local Path: Uses: Descriptor:\n");
printf("---------------------------------------------------------------------\n");
//
// Call the NetShareEnum function; specify level 502.
//
do // begin do
{
res = NetShareEnum (lpszServer, 502, (LPBYTE *) &BufPtr, -1, &er, &tr, &resume);
//
// If the call succeeds,
//
if(res == ERROR_SUCCESS || res == ERROR_MORE_DATA)
{
p=BufPtr;
//
// Loop through the entries;
// print retrieved data.
//
for(i=1;i<=er;i++)
{
printf("%-20S%-30S%-8u",p->shi502_netname, p->shi502_path, p->shi502_current_uses);
//
// Validate the value of the
// shi502_security_descriptor member.
//
if (IsValidSecurityDescriptor(p->shi502_security_descriptor))
printf("Yes\n");
else
printf("No\n");
p++;
}
//
// Free the allocated buffer.
//
NetApiBufferFree(BufPtr);
}
else
printf("Error: %ld\n",res);
}
// Continue to call NetShareEnum while
// there are more entries.
//
while (res==ERROR_MORE_DATA); // end do
return;
}
----------------------------------------------------------------
Thank You
Mahesh

Re: How to convert a function into main() instead of wmain() ?

David Crow5-Aug-04 2:29

David Crow

5-Aug-04 2:29

Did you even try renaming wmain to main? At least that would have shown you put forth some effort.

"When I was born I was so surprised that I didn't talk for a year and a half." - Gracie Allen

IDE Error/Problem I Think

sweep1235-Aug-04 0:04

sweep123

5-Aug-04 0:04

The following error appeared when I was adding a new function to one of my dialogs.

c:\SSIC_Example\GenericGuiDlg.h(18): error C2065: 'IDD_GENERIC_GUI' : undeclared identifier

I have checked and the 'IDD_GENERIC_GUI' is present in the reource.h file and used correctly in the .rc file.

I have seen this before and usually abandoned the project.

But this project is too big for that.

Any suggestions

Re: IDE Error/Problem I Think

Cedric Moonen5-Aug-04 1:33

Cedric Moonen

5-Aug-04 1:33

Make sure you include resource.h in GenericGuiDlg.h.

Re: IDE Error/Problem I Think

V.5-Aug-04 2:23

5-Aug-04 2:23

Do you have IntelliSense? Does it recognize the identifier? (if the IntelliSense works, 'cause that's not always the case)

if it doesn't, try rebuilding the complete solution...?
Did you add the resource manually? (in that case did you set up the counter by 1 and did you give a unique id?)

If all else fails maybe you can create your resource dynamically in code?

good luck.

"If I don't see you in this world, I'll see you in the next one... and don't be late." ~ Jimi Hendrix

Re: IDE Error/Problem I Think

David Crow5-Aug-04 2:36

David Crow

5-Aug-04 2:36

sweep123 wrote:
c:\SSIC_Example\GenericGuiDlg.h(18): error C2065: 'IDD_GENERIC_GUI' : undeclared identifier

Right above this line should be the .cpp file that the compiler was operating on. I'll assume it was GenericGuiDlg.cpp. At the top of that .cpp file, right below the #include <stdafx.h> statement, should be the inclusion of the app's .h file. Inside of that file is where resource.h file gets included.

"When I was born I was so surprised that I didn't talk for a year and a half." - Gracie Allen

Re: IDE Error/Problem I Think

sweep1235-Aug-04 2:40

sweep123

5-Aug-04 2:40

Thanks, panic over.

CVS dir comparer algo.

Anthony_Yio5-Aug-04 0:02

Anthony_Yio

5-Aug-04 0:02

Hello, does anyone know how the CVS algorithm on comparing directory structure. For file comparing, I think it is using checksum. But how about the directory structure?

thanks.

Sonork 100.41263:Anthony_Yio

SDL1009 error while using Java Webservice from .NET 2003

arun14054-Aug-04 23:58

arun1405

4-Aug-04 23:58

Hi Folks,

I am trying to use a Java webservice from Visual C++ 7.1 (VS.NET 2003). This webservice exposes one function that returns an OBJECT (java.lang.Object). When I try to add web reference to this webservice in VC++7.1, it generates following error while creating webservice proxy.

-----------------------------------------------------------------------
Creating web service proxy file for MyJavaService ...
sproxy : error SDL1009 : could not resolve element, with
[
namespace = "http://www.w3.org/2001/XMLSchema"
name = "anyType"
]
sproxy : error SDL1002 : failure in generating output file: "MyJavaService.h"
-----------------------------------------------------------------------

I do not know why Visual C++ is not able to recognize "anyType" in WSDL file generated by Java. Does anyone has any idea? or is there any workaround possible ?

Thanks & Regards,
Arun Gupta

i can disable menu item but cannot gray it!!!!!!!!

caykahve4-Aug-04 23:06

caykahve

4-Aug-04 23:06

Hi,

I have a dialog based app, want to disable and gray a sub menu item and I cannot gray it. I tried to find a solution to this problem but could not. Neither of the following work. Mad | :mad:

What happens is I see Item 3 in black, press it, and nothing happens. I could have done it by modifying the code that is called when Item 3 is pressed. Why would I bother with OnUpdate? What's the use of it? I got no idea! Confused | :confused:

I will be very happy if someone can help me.

Thanks...

// The menu looks like:<br />
// File  Settings<br />
// Item1 Item2<br />
//       Item3

void CMyDlg::OnUpdateSettingsItem3(CCmdUI* pCmdUI) 
{
 if (pCmdUI->m_nID==ID_SETTINGS_ITEM3)
 {
    UINT fGray = Item3Enable ? 0 : MF_GRAYED|MF_DISABLED;
    if(pCmdUI->m_pMenu!=NULL)
       pCmdUI->m_pMenu->EnableMenuItem(pCmdUI->m_nIndex /*ID_SETTINGS_ITEM3*/, MF_BYPOSITION|fGray);	
 }
 pCmdUI->Enable(Item3Enable);
}

void CMyDlg::OnUpdateSettingsItem3(CCmdUI* pCmdUI) 
{
 if (pCmdUI->m_nID==ID_SETTINGS_ITEM3)
 {
    UINT fGray = Item3Enable ? 0 : MF_GRAYED|MF_DISABLED;

    CMenu *hMenu;
    hMenu = AfxGetMainWnd()->GetMenu();		
    CMenu *sub;
    sub = hMenu->GetSubMenu(1);
    sub->EnableMenuItem(ID_SETTINGS_ITEM3, MF_BYPOSITION|fGray); }
 }
 pCmdUI->Enable(Item3Enable);
}

Re: i can disable menu item but cannot gray it!!!!!!!!

Brian Delahunty4-Aug-04 23:15

Brian Delahunty

4-Aug-04 23:15

what is Item3Enable??? I presume it's a bool that you've set somewhere else in the program.... and you're passing that into pCmdUI->Enable() at the end of each handler but you are not changing the true/false value of Item3Enable so you seem to be enabling the menu item at the end of each handler.

Regards,
Brian Dela Smile | :)

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Re: i can disable menu item but cannot gray it!!!!!!!!

caykahve4-Aug-04 23:27

caykahve

4-Aug-04 23:27

Yes, I set the bool variable Item3Enable to true somewhere else when I want to have ID_SETTINGS_ITEM3 enabled, and to false when I want to have ID_SETTINGS_ITEM3 disabled.

Re: i can disable menu item but cannot gray it!!!!!!!!

Jaime Stuardo5-Aug-04 3:39

Jaime Stuardo

5-Aug-04 3:39

Just do:

pCmdUI->Enable(FALSE);

when pCmdUI->m_nID is ID_SETTINGS_ITEM3

that is, simply you can do:

pCmdUI->Enable(pCmdUI->m_nID != ID_SETTINGS_ITEM3);

Jaime

Re: i can disable menu item but cannot gray it!!!!!!!!

caykahve5-Aug-04 4:35

caykahve

5-Aug-04 4:35

I have already set it to false, item 3 becomes disabled, but not gray!! besides I do not want to have it always disabled, therefore I have put the variable Item3Enable, which I set to true or false in another function outside.

I must be able to point to item 3 somehow and disable it but pCmdUI->m_pMenu is always NULL. I cannot manage to disable item 3 with GetMenu() and GetSubMenu() either, although I know it is possible to check and uncheck a menu item on a COMMAND message mapped to it using GetMenu() and GetsubMenu().

Does not anyone know why this doesn't work?

Re: i can disable menu item but cannot gray it!!!!!!!!

Jaime Stuardo5-Aug-04 5:03

Jaime Stuardo

5-Aug-04 5:03

Have you tried to put pCmdUI->Enable(FALSE) as the only instruction in the update handler? If that way the menu option is grayed, the problem is the condition you have.

By the way, if that update handler is called only for item 3, you don't need that verification.

Finally, I tell you that I use my own application to place pCmdUI->Enable(FALSE) for a specific menu item and it worked (disabled and grayed) so the problem may be in your condition.

Jaime

Re: i can disable menu item but cannot gray it!!!!!!!!

caykahve5-Aug-04 5:27

caykahve

5-Aug-04 5:27

Yes, it was only one line pCmdUI->Enable(true/false) before I encluntered the problem of non-grayed disabling. I put the other code to be able to gray it. actually I found it in some documents on internet, but none of the examples I saw directly match the situation I have.

You're right about the verification being unncessary, i did that to be sure.

Re: i can disable menu item but cannot gray it!!!!!!!!

Jaime Stuardo5-Aug-04 6:06

Jaime Stuardo

5-Aug-04 6:06

I can guess that you have in other part of your program a code to "ungray" the item. Check that.

Other fact to check. Are other menu items grayed that you see grayed? maybe is only a display problem.

Jaime

solution!

caykahve6-Aug-04 0:25

caykahve

6-Aug-04 0:25

I solved the problem and I'm very happy for that!! Big Grin | :-D

ok.. forget the function mapped to UPDATE_COMMAND_UI - delete it! Somewhere outside do this to switch between enabled and disabled menu items - nothing else

//enable-disable switch<br />
// Item3Enable is the bool value to decide if it will be enabled or disabled<br />
Item3Enable = !Item3Enable;<br />
<br />
UINT fGray = Item3Enable ? 0 : MF_GRAYED|MF_DISABLED;<br />
CMenu *hMenu;    <br />
hMenu = GetMenu();		    <br />
CMenu *sub;    <br />
sub = hMenu->GetSubMenu(1);    <br />
sub->EnableMenuItem(ID_SETTINGS_ITEM3, MF_BYCOMMAND|fGray);

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