C / C++ / MFC Discussion Boards

Re: newbie : why doesn't this work? plz plz plz

lucy8-Apr-02 8:46

8-Apr-02 8:46

according to MS document, long double is equal to double. and atof() will convert a string to double. I think this is what you want for the assignment?

Re: newbie : why doesn't this work? plz plz plz

8-Apr-02 8:47

atof function does return a double value.

Try this ...

#include <stdlib.h>
#include <stdio.h>
#include <isostream.h>

using namespace std;

int main()
{
char str1[] = "123.21";

double d = atof(str1);

cout << d;

return 0;
}

Re: newbie : why doesn't this work? plz plz plz

davun8-Apr-02 9:24

davun

8-Apr-02 9:24

thanks all. Very much appreciated.

ScrollWindowEx Problem!

G.Richard8-Apr-02 5:43

G.Richard

8-Apr-02 5:43

does anyone knows how to use ScrollWindowEx?

c++ : my dream

Re: ScrollWindowEx Problem!

alex.barylski8-Apr-02 7:22

alex.barylski

8-Apr-02 7:22

Nope..no one uses ScrollWindowEx anymore... Poke tongue | ;-P

I'm afraid your going to have to be more specific than that...

Cheers

"An expert is someone who has made all the mistakes in his or her field" - Niels Bohr

Re: ScrollWindowEx Problem!

G.Richard9-Apr-02 3:36

G.Richard

9-Apr-02 3:36

I want to use the ScrollWindowEx to animate window, when scrolling.
i mean I can't use ScrollwindowEx do the same thing that scrollwindow do, if i change the last parameter to SW_SMOOTHSCROLL. it can't update the region scrolled.why not have a try? you can test the following code inyou application.

...
CRect rcClient;
GetClientRect(&rcClient);
ScrollwindowEx(100,0, &rcClient, &rcClient, NULL,NULL, SW_SMOOTHSCROLL);
...

c++ : my dream

Help with multiple classes

Xds8-Apr-02 5:32

Xds

8-Apr-02 5:32

Hi all,

This is my first post; I'm new to C++ so go easy on me.
I have two classes; and their functions include code that refer to the other:
i.e: Class X has code that uses a variable/function from Class Y and vice-versa. The classes are completely different, so it would not help to derive one off the other.

In Header.h:

------------------------------------------------------------
class X {
public:
	int  myint;
	void doit(void);
};

void X::doit(void) {
	printf("CY.myint = %i", CY.myint); // Print Class Y's myint
}


class Y {
public:
	int  myint;
	void doit(void);
};

void Y::doit(void) {
	printf("CX.myint = %i", CX.myint); // Print Class X's myint
}
------------------------------------------------------------

In Main.CPP:

------------------------------------------------------------
#include  "stdio.h"
#include "Header.h"

int main(void) {

	class X CX;
	class Y CY;

	CX.myint = 100;
	CY.myint = 200;
	CX.doit();
	CY.doit();

	return 1;

}
------------------------------------------------------------

How can I get these classes to work together?
I can't put an 'extern class Y' before the 'class X' declaration, so how can I let the compiler know that the other class exists and will be declared?

Thanks!

Mike

Re: Help with multiple classes

Rickard Andersson²⁰8-Apr-02 5:39

Rickard Andersson²⁰

8-Apr-02 5:39

Xds wrote:
int main(void)
{
class X CX;
class Y CY;

CX.myint = 100;
CY.myint = 200;

CX.doit();
CY.doit();

return 1;
}

I'm not sure about this but isn't it "wrong" to write 'class X CX'?
Isn't 'X CX' the right way!?

I can be wrong!!!!!!

------------------------------------
Rickard Andersson, Suza Computing
ICQ#: 50302279
I'm from the winter country SWEDEN!

------------------------------------

Re: Help with multiple classes

Xds8-Apr-02 5:49

Xds

8-Apr-02 5:49

Pretty sure it works either way, but in any case, that's not the problem.
Thanks!

Mike

Re: Help with multiple classes

Roger Allen8-Apr-02 6:09

Roger Allen

8-Apr-02 6:09

You need to use a forward declaration of the class.

class Y ; // forward class declaration

class X
{
 void DoIt(Y& y) ; // pass in a reference to a Y object
} ;

class Y
{
} ;

You also cannot print out the content of CY in CX unless you pass a reference / pointer / copy of the object you want to print in as a parameter. The CX in main does not know anything about the CY:

#include  "stdio.h"
#include "Header.h"
int main(void) 
{
	X CX;
	Y CY;
	CX.myint = 100;
	CY.myint = 200;
	CX.doit(CY); // see class declaration above
	CY.doit();
	return 1;
}

Roger Allen
Sonork 100.10016

If I'm not breathing, I'm either dead or holding my breath.
A fool jabbers, while a wise man listens. But is he so wise to listen to the fool?

Re: Help with multiple classes

Le centriste8-Apr-02 7:34

Le centriste

8-Apr-02 7:34

That code wont't compile because in your doit methods you reference hard-coded instances.
Michel

If I am wrong or said something stupid, I apologize in advance Wink | ;)

Need a control to show .gif files

Hans Ruck8-Apr-02 5:26

Hans Ruck

8-Apr-02 5:26

Do you know an activex control able to show .gif files?

rechi

Re: Need a control to show .gif files

C^hris L^osinger8-Apr-02 5:31

C^hris L^osinger

8-Apr-02 5:31

first, you need a GIF/LZW license. see www.unisys.com.

-c

   "What the hell are you getting so upset about? I thought you didn't believe in God".
   "I don't," she sobbed, bursting violently into tears, "but the God I don't believe in is a good God, a just God, a merciful God. He's not the mean and stupid God you make Him out to be".
   -- Joseph Heller

Smaller Animals Software, Inc.

Re: Need a control to show .gif files

Carlos Antollini8-Apr-02 5:39

Carlos Antollini

8-Apr-02 5:39

Use image.ocx...

Regards...

A couple of month agou in MSDN magazine, Paul Dilascia wrote a class for display those type of files....

Regards

Carlos Antollini.
Sonork ID 100.10529 cantollini

Re: Need a control to show .gif files

Rickard Andersson²⁰8-Apr-02 5:41

Rickard Andersson²⁰

8-Apr-02 5:41

I'm pretty sure there is an article here on CP about that!

------------------------------------
Rickard Andersson, Suza Computing
ICQ#: 50302279
I'm from the winter country SWEDEN!

------------------------------------

Re: Need a control to show .gif files

Hans Ruck8-Apr-02 8:27

Hans Ruck

8-Apr-02 8:27

Thank you all, the problem is now solved!
Thanks1

rechi

Using Arabic Character in the MFC

Mesut8-Apr-02 5:23

Mesut

8-Apr-02 5:23

hi,
I want the arabic character writing in the Edit Text and Static Text in the English Windows (No Arabic Windows) . Arabic fonts is best writing but it is wrong connect the arabic character.. (in the MFC od Embedded VC++)..
I'm not good speak englih.. Sorry all!
Please help me.

best regads..

Mesut
mgencer99@hotmail.com

MFC

Re: Using Arabic Character in the MFC

Carlos Antollini8-Apr-02 5:43

Carlos Antollini

8-Apr-02 5:43

You need to use Unicode Strings, and need to work in a PC with that language. Never but never save the project in a pc, with another idiom.
I worked in a multy language project, And I nedded to save same parts of the project in OS that supports that languajes, like Arabic, Hebrew and Russian...

Carlos Antollini.
Sonork ID 100.10529 cantollini

Re: Using Arabic Character in the MFC

Carlos Antollini8-Apr-02 5:44

Carlos Antollini

8-Apr-02 5:44

You need to set the RTL proprti in the Edit and in the static controls, the same for the combo boxes

Carlos Antollini.
Sonork ID 100.10529 cantollini

help

8-Apr-02 3:41

Dose anybody know where I can find demonstration packages programmed in Visual c++, which show you the encryption of eg transposition cipher. I can find alot of help in Java but sadly none in Visual c++

Any suggestions? urls? Or people I can e-mail?

thanks

Problems with accessing a control from another class

James P8-Apr-02 3:22

James P

8-Apr-02 3:22

I am well and truely stumped. I have created a progress bar within a formview and I am trying to access it via a totally different class and getting all sort of errors.

Here is the code: -
percentage=int(((float)i/(float)(mrecords*4))*100.0);
str.Format("Mailsort is %d%% complete (Coding - %s)", percentage, currentmailsortfile);
m_progress.SetWindowText(str);
m_progress.SetPos(percentage);

and the progress control is created in the IYIView.h header file as follows: -

//{{AFX_DATA(CIYIView) enum { IDD = IDD_IYI_FORM };
CTextProgressCtrl m_progress;
//}}AFX_DATA

I am trying to access the view header file (IYIView.h) in order to create an instance of the class and access the progress control (m_progress) but I am getting the following errors on compliation but don't know how to get round it without effecting the rest of the program.

d:\my projects\iyi\iyiview.h(23) : error C2065: 'IDD_IYI_FORM' : undeclared identifierd:\my projects\iyi\iyiview.h(23) : error C2057: expected constant expression
d:\my projects\iyi\iyiview.h(115) : error C2143: syntax error : missing ';' before '*'
d:\my projects\iyi\iyiview.h(115) : error C2501: 'CIYIDoc' : missing storage-class or type specifiers
d:\my projects\iyi\iyiview.h(115) : error C2501: 'GetDocument' : missing storage-class or type specifiers

MSDN is no help, so do you have any ideas?!?

Re: Problems with accessing a control from another class

Mazdak8-Apr-02 4:06

Mazdak

8-Apr-02 4:06

Check this.

Mazy

"The path you tread is narrow and the drop is shear and very high,
The ravens all are watching from a vantage point near by,
Apprehension creeping like a choo-train uo your spine,
Will the tightrope reach the end;will the final cuplet rhyme?"Cymbaline-Pink Floyd

Re: Problems with accessing a control from another class

James P8-Apr-02 5:31

James P

8-Apr-02 5:31

I don't need to access the whole view but simply the progress bar to update from a different class. Is it really necessary to do all of this code just to pass a value to a control?

Re: Problems with accessing a control from another class

Mazdak8-Apr-02 6:02

Mazdak

8-Apr-02 6:02

James P wrote:
Is it really necessary to do all of this code just to pass a value to a control?

If you wanna use your view you have to do something like that.There are another way exist but I didn't test.Read the messages at the bottom of that article,they are easier. Smile | :)

Mazy

"The path you tread is narrow and the drop is shear and very high,
The ravens all are watching from a vantage point near by,
Apprehension creeping like a choo-train uo your spine,
Will the tightrope reach the end;will the final cuplet rhyme?"Cymbaline-Pink Floyd

listen() problem

lucy8-Apr-02 3:21

lucy

8-Apr-02 3:21

I am driven to the wall. Can anyone help me?
I have a server and a client both use TCP/IP socket. The server runs Vxworks while the client runs Windows 2000. the requrirement is that the server can have one client only at a time, so when I initialize the server socket, I say:
nRet = listen(ListenSocket, 1);
But still, when I run two clients to test it, both can connect()!!!
And when I check the messages received by the server,

if ( FD_ISSET(ListenSocket, &ReadSet) && ClientSocket == 0)
    HandleNewConnection();
else    
    logMsg("don't accept\n", 1, 2, 3, 4, 5, 6);

I will see that: after the first client successfully connected to the server (ClientSocket != 0 then), I let the second client try to connect to the server. The client will tell me its connect() okay, while the server will say "don't accept\n" all the time until the second client close the connection.

What's the use of the MAX_CONNECTION = 1 in my listen() then??

Or if I over look something?

any help is highly appreciated!

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