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Can i use and redistrubute GDI+ v1.1 with my application???
From Where can i download GDI+ V1.1?? Microsoft site still has old version for GDI+.
-- modified at 8:14 Tuesday 3rd July, 2007
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It's available on Vista+.
I thought I heard something about it being with .NET 3.x as well but I could have dreamed it 
No, you can't redistribute it.
Mark
Mark Salsbery
Microsoft MVP - Visual C++
"Go that way, really fast. If something gets in your way, turn."
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I am porting a COM object from VC6.0 to Visual Studo 2005 and I get the following error:
error C2011: 'spcADO::CursorTypeEnum' : 'enum' type redefinition
The reason for this is that the file msado15.tlh gets generated in the DebugU directory AND the project directory.
Any idea how I can solve this?
Thanks,
Jerome
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Strange, #import doesn't generally do this. Have you tried quitting VS, removing the tlh/tli files, and doing a clean and build?
Steve S
Developer for hire
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Yes it was weird - I tried that indeed but it did not work.
I think it was caused by the fact that two cpp files had the same name. For some unknown reason, the obj files were generated incorrectly. I removed them from the project and re-added and it now works. Touch wood!
Thanks for your help anyway!
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My requirement is
If i select an item in a tree Control that Selected item's color of text should be changed.(or i want to recognize whether it is selected or not--some way to identify)So can you please tell me how to do it.
bhw
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Handle the NM_CUTOME draw message and put the following code inside it.
void TreeCtrlEx::OnCustomDraw( NMHDR* pNMHDR_i, LRESULT* pResult_o )
{
NMTVCUSTOMDRAW* pLVCD = reinterpret_cast<nmtvcustomdraw *="">( pNMHDR_i );
NMCUSTOMDRAW &nMcd = pLVCD->nmcd;
*pResult_o = CDRF_DODEFAULT;
switch( nMcd.dwDrawStage )
{
case CDDS_PREPAINT:
// Item prepaint notification.
*pResult_o = CDRF_NOTIFYITEMDRAW;
break;
case CDDS_ITEMPREPAINT:
{
// Set the color of the text according to its state.
HTREEITEM nRow = reinterpret_cast< HTREEITEM >( nMcd.dwItemSpec );
if( CDIS_SELECTED == ( nMcd.uItemState & CDIS_SELECTED ))
{
pLVCD->clrText = clrSelText;// Selected text color
pLVCD->clrTextBk = clrSelBk;// Selceted backgroung
}
else
{
pLVCD->clrText = clrNormal;// text color in normal state
pLVCD->clrTextBk = clrBk// bakck ground color in normal state
}
// Allow it to do the default painting.
*pResult_o = CDRF_DODEFAULT;
break;
}
default:
*pResult_o = CDRF_DODEFAULT;
break;
}
}
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Hi,
I have assigned a huge string of about 32800 chars to CString object, but i am getting this "error C2026: string too big, trailing characters truncated", does any one know how can i resolve it, or is there any work around?
Best Regards,
Mushq
Mushtaque Ahmed Nizamani
Software Engineer
Ultimus Pakistan
"English is my second language, so please don't mind if i do some grammatical or spelling mistakes in my messages."
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Can you tell me why you want to have this string? and what is it?
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There is a compiler limit on string literals of 2048 characters, so this has nothing to do with CString.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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How do you create this string in the First Place. You hardly typed it by hand!
Anyways:
Try CString MyString;
MyString.GetBuffer(32000);
The problem occurs with items such as strings which are zero terminated. If the compiler does not find a 0 after a reasonable number of chars, ( and 2048 is a reasonable limit in most cases)the compiler decides that there must be a syntax error (forgotten a terminating ") etc.
LateNightsInNewry
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I have done an application in which i need to interact with 2 other systems using RS 232 cables.
Individually i am able to communicate with either systems but facing problems when executed and trying to interact with 2 systems simultaneously. The main reason for this is the I am using a Pentium 3 processor which is a must for me.Can anyone help me out to overcome this problem in pentium 3 processor.
NAVEEN
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naveen27gupta wrote: The main reason for this is the I am using a Pentium 3 processor
Why the above is the main reason?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Your not trying to just connect the PCs together like this are you?
PC 1 <---\
PC 2 <---|
PC 3 <---/
Just connect all 3 ports together... RxD to RxD to RxD etc.
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A simple question.
I define an array.How to calculate its length?
int[] arInt = { 1, 2, 3 ,4, 5 };
Thanks in advance.
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Peter, Chan wrote: int[] arInt = { 1, 2, 3 ,4, 5 };
The correct syntax should be:
int arInt[] = {....
int nSize = sizeof(arInt) / sizeof(int);
this is this.
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Then if it is a array of string.Should I write like this.
char * arLang[] = {"english", "chinese"};
int nSize = sizeof(arLang) / sizeof(char);
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Nope
Then you get the number of char's in the array, not the number of strings
You can't count it this way, because each string has a different lenght.
You can determine the length of arLang, then loop on it and count the occurence of \0 (End of a String)
So you get the number of strings in the array, if i tell no mistakes
Good luck
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No, it can't be done with multi-dimensional arrays.
You can only do it with single-dimensional arrays like:
char arLang[] = {"english"};
And the length will be 8 bytes.
And whenever you get the operator * anywhere, you just can't be sure of the size.
But you can write:
int nSize1 = strlen(arLang[0]) + 1;<br />
int nSize2 = strlen(arLang[1]) + 1;
etc.
this is this.
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Peter, Chan wrote: int nSize = sizeof(arLang) / sizeof(char);
Mistake!
change as follows:
int nSize = sizeof(arLang) / sizeof(char *);
or (better):
int nSize = sizeof(arLang) / sizeof(arLang[0]);
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Peter, Chan wrote: I define an array.How to calculate its length
Did you have a look at the sizeof()
Somethings seem HARD to do, until we know how to do them.
 _AnShUmAn_
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It depends on what you want. If the array is dynamically declared, i.e. You used 'malloc', there is no knowing, unless if you build in your own scheme of determining these things. At any rate, the size of the array is known to you, because you had to give the size to the malloc function. In these cases, you need to devine a scheme to pass this knowledge on to where it is needed.
in statically declared arrays, you can use the sizeof() operator to get the size of an array in bytes. But, still again, beware and look at the language definition.
i.e.:
char * Arr[]={"First Item","Second Item"};
This is an array of pointers to character strings. Arr contains two 4-Bit Items ( or 2 8-Bit items in a 64 bit Compiler), namely the Addresses of the two strings, "First Item" and "Second Item". So in the above example,
sizeof(ARR) would always give 8 ( or 16 in a 64 bit Compiler environment). If you need to know wat's needed to store the structure ans it's data, you need:-
size_t GetTotalDataSize(){
size_t NrOfItems= sizeof(Arr)/sizeof(char*);
size_t TotalSize=sizeof(Arr);
for(int i=0;i<NrOfItems;i++)TotalSize+=(strlen(Arr+i)+1);
return TotalSize;
}
LateNightsInNewry
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Your description is very clear. I now know clearly how to use sizeof().
I still just have one question.
Just as your sample.
char * Arr[]={"First Item","Second Item"};
Do I need to delete Arr when it is useless.
<br />
delete Arr[0];<br />
delete Arr[1];
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Peter, Chan wrote: Do I need to delete Arr when it is useless.
In this case, no. Since you did not allocate the strings using new, you do not have to free them using delete.
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