C / C++ / MFC

Re: application configuration is incorrect

17-Mar-10 6:45

So you didn't understand. Put the code here so it's better for someone to help.
Laugh | :laugh:

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

LittleYellowBird17-Mar-10 5:23

LittleYellowBird

17-Mar-10 5:23

Hi,

I had a similar problem recently and installing the 'Redistribution Package' did not solve it.

I found the Dependency Walker utility really handy (and its free), as it lets you see which libraries/dlls are needed for your app and a missing dll seems to be the cause of this error most of the time. Here's the link .....

http://www.dependencywalker.com/[^]

Hope this helps,

Ali

tooltips

Member 59031017-Mar-10 2:20

Member 590310

17-Mar-10 2:20

hi,
i have created a toolbar and enable tooltips nw i want to attach tooltips.hw can i do that?

Re: tooltips

Eugen Podsypalnikov17-Mar-10 2:31

Trying to intercept Hyperlink dialog in edit mode CHtmlEditCtrl (WebBrowser control)

17-Mar-10 2:31

Try to define your strings in the yourapp.rc file Smile | :)

STRINGTABLE
BEGIN
    IDC_CMD_BUTTON_1 "This is the tooltip for button 1" // the same IDC_CMD_BUTTON_1 ordered to the button 1
    IDC_CMD_BUTTON_2 "This is the tooltip for button 2" // the same IDC_CMD_BUTTON_2 ordered to the button 2
    IDC_CMD_BUTTON_3 "This is the tooltip for button 3" // the same IDC_CMD_BUTTON_3 ordered to the button 3
    IDC_CMD_BUTTON_4 "This is the tooltip for button 4" // the same IDC_CMD_BUTTON_4 ordered to the button 4
...
END

virtual void BeHappy() = 0;

Paul Vickery17-Mar-10 1:32

Paul Vickery

17-Mar-10 1:32

Hi,

I have an application that uses CHtmlEditCtrl for some WYSIWYG HTML editing. All is good, except that I need to add some custom protocols to the Hyperlink editor dialog. I have tried a couple of ways of doing this, but have some up against problem with each. The things tried are:

1. Open our own dialog in place of the in-built: ok if adding a new link, but when editing a link don't get the default behaviours of selecting the whole link text if caret is in middle of link, and can't get the existing URL to edit.

2. Catch the creation of the dialog with a hook, so I can fiddle with its controls: no good - the hook doesn't get entered on creation of the dialog

I would prefer option 1 if I can:
a. get it to select the whole link text (may not be required, but better if it can)
b. retrieve the URL of the selected link

Does anyone have any ideas? Has anyone managed to successfully intercept the Hyperlink dialog in any way?

Thanks,

Paul.

"The way of a fool seems right to him, but a wise man listens to advice" - Proverbs 12:15 (NIV)

Converting DWORD

hrishi32117-Mar-10 0:52

hrishi321

17-Mar-10 0:52

Hi can any one please tell me how to convert one DWORD
to CString in VC++. (Both in Hex and decimal Formate)

Eugen Podsypalnikov17-Mar-10 1:00

17-Mar-10 1:00

Try it

DWORD dwTest(1234);
 
CString cszTest;
cszTest.Format(_T("DEC: %u; HEX: 0x%08x"), dwTest, dwTest);

virtual void BeHappy() = 0;

hrishi32117-Mar-10 1:33

hrishi321

17-Mar-10 1:33

Hi Thanks for your kind reply..

I tried the way, but i guess it is showing me the memory location

DWORD dwTest(0xFFFFFFFF);
CString cszTest;
cszTest.Format(_T("DEC: %u HEX: 0x%08x"), dwTest, dwTest);
cout<<cszTest;

I am getting a output of
0036AA20

Cool_Dev17-Mar-10 1:47

Cool_Dev

17-Mar-10 1:47

problem may be with cout and unicode. To ensure it, try with _tprintf(_T("%s", cszTest));

I don't know whether there is any unicode version of cout.

Richard MacCutchan17-Mar-10 4:16

Richard MacCutchan

17-Mar-10 4:16

Cool_Dev wrote:
I don't know whether there is any unicode version of cout.

wcout[^]

txtspeak is the realm of 9 year old children, not developers. Christian Graus

Cool_Dev17-Mar-10 4:52

Cool_Dev

17-Mar-10 4:52

yep.. got it from Rajeesh's post Thumbs Up | :thumbsup:

CPallini17-Mar-10 1:47

17-Mar-10 1:47

hrishi321 wrote:
cout<<csztest< blockquote="">
try changing change it to:
CT2A pszTestA( cszTest );
cout << (LPCSTR) pszTestA;
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

how can i get the path of a specific application?

KingsGambit17-Mar-10 1:52

KingsGambit

17-Mar-10 1:52

If the project setting is UNICODE, you may have to use as follows:
wcout << (LPCTSTR)cszTest;
Give it a try if cout is not working Smile | :)

mazizi17-Mar-10 0:00

mazizi

17-Mar-10 0:00

hi i need to gain the path of adobe acrobat but i don't know how.
i know that i can use registery but i don't know the adobe acrobat's key in registery.
can you help me?
thanks.

Re: how can i get the path of a specific application?

Eugen Podsypalnikov17-Mar-10 0:11

Re: how can i get the path of a specific application?

17-Mar-10 0:11

I could find it, for the version 9.0 Smile | :)

:
HKEY_LOCAL_MACHINE\SOFTWARE\Adobe\Acrobat Reader\9.0\Installer\Path

virtual void BeHappy() = 0;

mazizi17-Mar-10 0:49

mazizi

17-Mar-10 0:49

do you think the other version, store in the other place?!!

Re: how can i get the path of a specific application?

Eugen Podsypalnikov17-Mar-10 0:58

Re: how can i get the path of a specific application?

17-Mar-10 0:58

Yes, I think so,
the registry path part "9.0" may be different... Smile | :)

virtual void BeHappy() = 0;

David Crow17-Mar-10 4:34

David Crow

17-Mar-10 4:34

Have you tried AssocQueryString()?

"One man's wage rise is another man's price increase." - Harold Wilson

"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

"Man who follows car will be exhausted." - Confucius

Unanticipated behavior from overloaded cast operator... [modified]

Mike the Red16-Mar-10 23:01

Mike the Red

16-Mar-10 23:01

The code:

class testClass {
public:
	testClass() {	m_buff = new BYTE[20]; 
			memcpy(m_buff, "0123456789", 10); 
	};
	~testClass() { delete m_buff; };

	operator LPBYTE () { return m_buff; };

	void show() {
		cout << "m_buff = " << (__int64) (void *) m_buff << "\n\t"; // Show address of m_buff
		for (int i = 0; i < 10; i++) // Show contents of m_buff
			cout << m_buff[i];
		cout << "\n";
	};
private:
	LPBYTE m_buff;
};

int main(int argc, char * argv[])
{
	testClass * foo = new testClass();
	foo->show();
	cout << "foo = " << (__int64) (void *) foo << "\n"; // Show address of foo
	cout << "(LPBYTE) foo = " << (__int64) (void *) ( (LPBYTE) foo ) << "\n\t"; // Show address of cast (LPBYTE) foo
	for (int i = 0; i < 10; i++) // Show contents of cast (LPBYTE) foo
		cout << ((LPBYTE) foo)[i];
	
	cout << "\n";
	delete foo;
	return true;
};

And some output:

m_buff = 9180016
	0123456789
foo = 9179968
(LPBYTE) foo = 9179968
	-garbage-

I was expecting to see:

m_buff = 9180016
	0123456789
foo = 9179968
(LPBYTE) foo = 9180016 // same address as m_buff
	0123456789

What am I missing ?

I know I could accomplish something similar with a member function returning the address of m_buff, but in my ever more ridiculous quest to learn more aspects of C++, I wanted to try this operator overloading bit....

As always, any guidance you can offer is greatly appreciated.

MZR

modified on Wednesday, March 17, 2010 5:11 AMP.S.
My apologies for using __int64... I know it's Microsoft specific, but I use what I've got.

Re: Unanticipated behavior from overloaded cast operator...

Moak16-Mar-10 23:36

Moak

16-Mar-10 23:36

Mike the Red wrote:
operator LPBYTE () { return m_buff; };

Don't you mean (LPBYTE)*foo since foo is a pointer?

/Moak

PS: You might want to add copy constructor and assignment operator to your class. Law of the Big Two, classes that handle memory/resources usually need a copy constructor and an assignment operator.

Webchat in Europe Java | [Coffee]

(only 4K)

Thanks, Moak! I didn't understand you at first, but that's exactly the problem.

Mike the Red17-Mar-10 0:24

Mike the Red

17-Mar-10 0:24

I didn't understand your post until Pallini gave a longer explanation of this.

Thanks for your help!!!

PS:
Thanks for the suggestion about the Big Two, but I don't think so in this case.

The idea behind the class is for it to always behave as a dynamically-allocated LPBYTE, but somtimes point to a MMF, when the buffer is larger than a certain threshold.
In both cases (true LPBYTE or LPBYTE pointing to an MMF), the standard memory functions (memcpy, memset, etc.) are appropriate.
(Which is why I want the cast to point to the same place as the member pointer m_buff.)

Re: Thanks, Moak! I didn't understand you at first, but that's exactly the problem.

Moak17-Mar-10 0:30

Moak

17-Mar-10 0:30

Good teamwork with Pallini Smile | :)

Webchat in Europe Java | [Coffee]

(only 4K)

Re: Unanticipated behavior from overloaded cast operator...

CPallini16-Mar-10 23:45

Wait.. my overloaded operator isn't being called....

16-Mar-10 23:45

Mike the Red wrote:
I was expecting to see:

Mike the Red wrote:
m_buff = 9180016 0123456789 foo = 9179968 (LPBYTE) foo = 9180016 // same address as m_buff
0123456789

Mike the Red wrote:
What am I missing ?

The address of the class and the one of the m_buff variable (i.e. &m_buff) are the same.
On the other hand, the address of the class differs from that of the memory buffer (i.e. m_buff).

To verify, add the following line to the show method:

cout << "&m_buff = " << (__int64) (void *) &m_buff << "\n\t"; // Show the REAL address of m_buff

(that happens because of dynamic memory allocation).

Smile | :)

Mike the Red16-Mar-10 23:59

Mike the Red

16-Mar-10 23:59

I changed the operator function to:

operator LPBYTE () { cout << "Inside operator.\n"; return &this->m_buff[0]; };

...but Inside operator. never appears in the output.

If I explicitly use foo->operator LPBYTE() then Inside operator. appears in the output but not if I use an explicit cast (LPBYTE) foo.

Any ideas on that one ?

Thanks,

MZR

Re: Wait.. my overloaded operator isn't being called....

CPallini17-Mar-10 0:09