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GeneralRe: Passing Cursor Coordinates as Parameters Pin
ASPnoob20-May-13 22:05
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AnswerRe: Passing Cursor Coordinates as Parameters Pin
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GeneralRe: Passing Cursor Coordinates as Parameters Pin
ASPnoob21-May-13 16:38
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GeneralRe: Passing Cursor Coordinates as Parameters Pin
lukeer21-May-13 21:47
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GeneralRe: Passing Cursor Coordinates as Parameters Pin
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QuestionPropertyGrid Multiple Objects Selection Pin
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AnswerRe: PropertyGrid Multiple Objects Selection Pin
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AnswerRe: PropertyGrid Multiple Objects Selection Pin
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QuestionNot able to use Modern UI Charts for Windows 8 Pin
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AnswerRe: Not able to use Modern UI Charts for Windows 8 Pin
Abhinav S20-May-13 18:49
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GeneralRe: Not able to use Modern UI Charts for Windows 8 Pin
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AnswerRe: Not able to use Modern UI Charts for Windows 8 Pin
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GeneralRe: Not able to use Modern UI Charts for Windows 8 Pin
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GeneralRe: Not able to use Modern UI Charts for Windows 8 Pin
Pete O'Hanlon20-May-13 22:54
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AnswerRe: Not able to use Modern UI Charts for Windows 8 Pin
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AnswerRe: Not able to use Modern UI Charts for Windows 8 Pin
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QuestionPROBLEM with SEND DATA to LOCAL PORT C# Pin
Andrew Nguyen20-May-13 17:18
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AnswerRe: PROBLEM with SEND DATA to LOCAL PORT C# Pin
Ron Beyer20-May-13 17:56
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QuestionUsage of IDataErrorInfo Pin
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Ron Beyer20-May-13 14:55
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GeneralUnderstanding Jagged Arrays Pin
N8tiv20-May-13 3:29
N8tiv20-May-13 3:29 
GeneralRe: Understanding Jagged Arrays Pin
Richard Deeming20-May-13 3:44
mveRichard Deeming20-May-13 3:44 
WidmarkRob wrote:
myJaggedArray[0][0] = 11; // This is changing the first element in both arrays to 11, right?
myJaggedArray[1][2] = 22; //this is changing the first element in the first array to 22 and changing the second element in the second array to 22, right?

Not quite. A jagged array is essentially an array of arrays. In your sample code, the myJaggedArray variable is an array containing two elements: an array of three integers, and an array of five integers.

myJaggedArray[0] returns the first element, so myJaggedArray[0][0] = 11 is updating the first element of the array stored in the first element of myJaggedArray, and myJaggedArray[1][2] = 22 is updating the third element of the array stored in the second element of myJaggedArray.

http://msdn.microsoft.com/en-us/library/2s05feca.aspx[^]



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GeneralRe: Understanding Jagged Arrays Pin
N8tiv20-May-13 4:00
N8tiv20-May-13 4:00 
GeneralRe: Understanding Jagged Arrays Pin
Richard Deeming20-May-13 4:19
mveRichard Deeming20-May-13 4:19 

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