C#

public class Form1
{
    private StatusBar status;
    private bool busy;
    private Control control;
    
    public Form1()
    {
        //status.Capture = true;    1)Don't put this or you'll lose capture to the status bar. Whyis that?
        busy = false;
        control = new Control();
        control.Capture = false;
        control.LostFocus += new EventHandler(control_LostFocus);
    }

    private void control_LostFocus()
    {
        if(busy)
            control.Capture = true;
    }

    private void Search()
    {
        status.Text = "Searching";
        busy = true;
        control.Capture = true;
    
        // search code here
    
        busy = false;    //2)This must be before changing the capture to false
        control.Capture = false;
        status.Text = "";
    }
}

if(busy)
    return;

private void m_Control_LostFocus(object sender, EventArgs e)
{
	if(this.m_BusySearching)
	{
		Debug.WriteLine("control_lostfocus: busy");
		this.m_Control.Capture = true;
	}
	else
	{
		Debug.WriteLine("control_lostfocus: not busy");
	}
}

dummy.Capture = true;

dummy.Select();

myControl.Select();
myControl.Capture = true;

myControl.Focus();
myControl.Capture = true;

SearchButton.Enable = false;

lushgrass wrote:

however this doesnt work either.

lushgrass wrote:

how is your Control solution different from Form.Controls?

lushgrass wrote:

i'm not able to add MainMenu items to Form.Controls

lushgrass wrote:

however, there is a this.Capture field. can i use that somehow?

public partial class Form1 : Form
    {
        private delegate void React();

        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            Thread MyThread = new Thread(new ThreadStart(MySearchMethod));

            foreach (Control C in this.Controls)
                C.Enabled = false;

            MyThread.Start();
            //Code would fall here before the thread finish, so reactivate in anthoer method
        }

        private void Reactivate()
        {
            foreach (Control C in this.Controls)
                C.Enabled = true;
        }

        private void MySearchMethod()
        {
            int temp = 0;
            while(temp < long.MaxValue)
                temp++;

            Invoke(new React(Reactivate));
            //We have to call this method by Invoke to avoid Cross thread access
        }
    }

if(e.Modifiers == Keys.Control && e.KeyCode == Keys.M)
{
	// Do something here...
}

foreach(DataRow r in MyTable.Rows)
{
    if (MyTreeView.Nodes.Find(PARENT_CAT_ID, true).Length == 0)
        MyTreeView.Nodes.Add(CAT_ID);
    else
    {
        foreach (TreeNode MyNode in MyTreeView.Nodes.Find(PARENT_CAT_ID, true))
            MyNode.Nodes.Add(CAT_ID);
    }
}

ah_jiang_9 wrote:

how can i possibly display graphics object?

ah_jiang_9 wrote:

i created it from a picturebox and i added something to the picture but i have no idea on how to display it

Point BasePoint = new Point(BaseX, BaseY);
Point GradePoint = new Point(X, Y);
pictureBox1.Image = new Bitmap("MyAccImg.bmp");
Graphics g = Graphics.FromImage(picturebox1.Image);
g.DrawLine(Pens.Black, BasePoint, GradePoint);

System.Diagnostics.Process.Start(@"C:\WINDOWS\system32\shutdown.exe", "/f /t 00");<br />