|
hello
i'm trying to develop some logic that depends on the response i get from different system messages meaning that when a message box is displayed i want to apply some conditions if the user clicks on the Ok button, or some code takes effect if the user clicks Cancel button on the MessageBox.
the message box is the one that is usually displayed by
MessageBox.Show(""); method
can u please tell me if what i'm trying to do is possible?
if yes then please guide me how to do it
Regards
Saira
|
|
|
|
|
MessageBox.Show() returns one of the DialogResult values:
DialogResult.OK, DialogResult.Cancel, ... and so on ...
SkyWalker
|
|
|
|
|
thankyou
Regards![Rose | [Rose]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/rose.gif)
Saira
|
|
|
|
|
welcome 
SkyWalker
|
|
|
|
|
The Show method returns a value of the type DialogResult.
DialogResult result = MessageBox.Show("Hello world!");
The value of the return value reflects what the user did with the message box.
---
Year happy = new Year(2007);
|
|
|
|
|
all my messageBoxes are displaying OK buttons only.
how do i get to add a Cancel button on my MessageBox??
Saira
|
|
|
|
|
Hello,
System.Windows.Forms.MessageBox.Show("your text", MessageBoxButtons.OKCancel);
All the best,
Martin
|
|
|
|
|
hi,
the code gives the following error
the best overloaded method match for System.Windows.Forms.MessageBox.Show("your text", MessageBoxButtons.OKCancel); has some invalid arguments
if i convert the second argument to string it doesn't display the cancel button either.
whats wrong with it??
|
|
|
|
|
Sorry,
You have to set the:
using System.Windows.Forms;
or use:
System.Windows.Forms.MessageBoxButtons
All the best,
Martin
|
|
|
|
|
hey Martin
i checked it out,
There is no overloaded method for the Show function that takes a String and MessageBoxButton as argument.
|
|
|
|
|
Yep, you are right!
Haven't checked it, Sorry!
|
|
|
|
|
i had using System.Windows.Forms; set
how do i use:
System.Windows.Forms.MessageBoxButtons
and where do i put it???
|
|
|
|
|
Sorry,
Gave you the wrong parameters!
Look at 'quitesmart's answer.
|
|
|
|
|
write this:
<br />
MessageBox.Show("Your text", "Your message Caption", MessageBoxButtons.OKCancel);<br />
|
|
|
|
|
ThankYou
you really are quiteSmart
Regards
Saira
|
|
|
|
|
Saira Tanwir wrote: you really are quiteSmart
thanks a lot,
if you need any help be free to contact me on my msn address jamilaboukhalil@hotmail.com
|
|
|
|
|
Hi
I have a 'new person' form that i want to start with a height of 276 and if the person will have a photo the form to open up to 440. So for eas of working with it, in the designer it is 440 high, but I want it to open with 276. So I figured...
public frmNewPerson () {
InitializeComponent ();
Form.ActiveForm.Height=276;
}
would work, but it doesn't, it says...
Message="Object reference not set to an instance of an object."
and highlights the line Form....
So am I just putting this line of code in the wrong place or what?
TIA
Graham
|
|
|
|
|
have u tried to initiallize the form through the syntax
Form frm=new Form();
here Form is the name of the form that u are trying to manipulate and frm is its instance or objet that u have created for manipulating it.
try this approach as its worked for me.
hopefully this helps.
Saira
|
|
|
|
|
Saira
I just did that on the last form, to cause this form to appear so that doesn't seem the right thing to do.
Michael's suggestion has worked use - this.Height = 276;
Thanks
|
|
|
|
|
the-Yetti wrote: I have a 'new person' form that i want to start with a height of 276 and if the person will have a photo the form to open up to 440. So for eas of working with it, in the designer it is 440 high, but I want it to open with 276. So I figured...
public frmNewPerson () {
InitializeComponent ();
Form.ActiveForm.Height=276;
}
would work, but it doesn't, it says...
Message="Object reference not set to an instance of an object."
and highlights the line Form....
So am I just putting this line of code in the wrong place or what?
As you are in the constructor of the form, the ActiveForm property hasn't been initialised yet.
Try
this.Height = 276;
|
|
|
|
|
Put it in the Form's Load event instead of constructor.
private void frmNewPerson_Load(object sender, EventArgs e)
{
this.Height = 276;
}
|
|
|
|
|
That's what I thought, but I had tried ( as suggested by engsrini ) that I try it in the Load event, but it still failed. But thanks this.Height works.
|
|
|
|
|
Hi .
Need to Convert base64 string representing header of the binary field with image data.
//ds.Tables[6].Rows[1].ItemArray[2].ToString() contains base64string
{
Byte[] byt = Convert.FromBase64String(ds.Tables[6].Rows[1].ItemArray[2].ToString());
SaveToOut("image/jpeg", byt, true);
PerformScaleImage(contentType, content, Response, 150, 50);
MemoryStream stream = new MemoryStream();
stream.Write(buff, 0, buff.Length);
using (Bitmap img = new Bitmap(stream))/*---Giving invalid parameter exception-------*/
{
--------------------------}
}
Can you give details.
Srinivas
|
|
|
|
|
The error comes because you haven't reset the memory stream before reading it.
You should create a read-only memory stream from the array instead:
MemoryStream stream = new MemoryStream(buff, false);
Now the memory stream contains the data from the start, and you can read from it right away.
---
Year happy = new Year(2007);
|
|
|
|
|
The error is at the line pointing to ------(A)
MemoryStream stream = new MemoryStream();
stream.Write(buff, 0, buff.Length);
------(A)
using (Bitmap img = new Bitmap(stream))/*---Giving invalid parameter exception-------*/
{
--------------------------}
}
Srinivas S
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
