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Oh, sorry. When I mention about central server, I think I wrote the wrong idea. So, yes they do have a central server.
The idea of the telephone operators sounds nice. It works in our country, once up on a time it had a problem which is fixed now (the problem was, if you take one card and when u send to the mobile operator and at the same time your friend is doing the same thing but both of you are using only on card, both of you will get the amount at the card. i.e by concurrency you faked the operator. But this time, even if I dont know they did it, the problem is fixed).
About the claim, I hope I will wait may be up to 2 or 3 days for the student to take the cash. If not the amount will be transfered back to the parent's account. I think it is a good idea, isnt it?
About the encryption, can you tell me the best algorithm for this one, or recommend me free book or sites to read it.
Thank you Michel.
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CoderForEver wrote: by concurrency you faked the operator
Probably because their central server had some bugs 
CoderForEver wrote: If not the amount will be transfered back to the parent's account
Be carefull with those things. Once you enter the wonderful world of online banking, local regulations may apply. I'm not sure if banks in your country can (or will) reverse a transaction which has not been opposed by the initiating party. There may be rules regarding the the validity and expiry date of the transaction, and since you will be introducing a new form of payment, you will be exploring uncharted legal territory. Now since this a senior project, this will not matter much (you'll be building a prototype) but if you pursue this project further later, you should get legal advice.
Regarding encryption and signing, you stand no chance of having your project adopted (by the banks) if you don't have at least 2-factor authentication. (something you own - something you know)http://searchsecurity.techtarget.com/sDefinition/0,,sid14_gci992919,00.html[^]
What banks use in my country for GSM payments is as follows: The bank assigns you a personal certificate, which is stored on the SIM card chip (this requires cooperation of the mobile operators, who distribute the SIM cards, and must allow the certificate to be stored there) this certificate (on the chip) is the something you own.
They also assign you a pin code, or you use the standard GSM pin-code, which unlocks the personal certificate
on your card. this is the something you know. (the personal certificate won't be regurgitated by the card if you don't type the right pincode). Once you have the personal certificate, you can use this certificate's keys to encrypt and/or sign any messages between the bank and the payer (in this case the parents).
Of course, for a senior project, you won't be able to use all this (building you own SIM-cards and re-programming them might be a bit out of scope). But you should at least be able to to simulate the process (maybe not on a mobile phone, but on a PC), in order to demonstrate that you thought about the problem.
On the receiving side, it's a bit more complicated (or a bit more simple, depending on how you look at it). Since the student does not have the something you own (he does not need to have a bank account with a banking card, or an account with a sim card private key), normal banking rules will apply: He will have to justify his identity (with whatever means are legal in your country: ID-card, passport, drivers license, ...), and present the transaction id to the collecting bank, together with his credentials. The transaction-id does not need to be encrypted, because it will allow the bank clerk to look up the right credentials from the central transaction server, and refuse payment if the physical credentials presented look iffy or do not correspond to the stored credentials.
This is the main difference between the parents transaction, and the students transaction: the parents do an electronic transaction, from the safety of their home or workplace, and use electronic means for justifying their identity. They need 2 factor authentication. The student still has to walk up to the bank counter, and justify ownership of the transaction, by PHYSICAL means. He does not need encryption or electronic signing, because his presence and ownership of the transaction code, plus his legal id is proof enough (and encryption and signing keys these days are so complicated and long that no one can remember them).
That's why I advised you not to use encryption on the message that is passed between the parents and the students: It either would be too easily cracked, or too long, or both.
Now, since this is a senior year project, it's obvious that you will not be able to implement all that. But I think the purpose of a senior project is to demonstrate that you can find solutions which are well-designed, and cater for all eventualities. If you cannot implement encryption algorithms, or mobile phone communications with access to the sim card, so be it. Use mock-ups, implement all your stuff on PC's, but demonstrate that you though about it, and that you've considered all the implications of your system. Have arguments ready when your teachers ask you why you didn't implement a new authentication and signing algorithm. I've given you plenty, and to be honest, I suspect that you could not invent one, your teachers could not invent one, and I'm sure that I couldn't invent one (and I've written online banking software since 1978, notably for the first country-wide ATM networks in Belgium).
Good luck!
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Hello my friend. I think we got to go on the SMS banking thing. But we got one trouble before we submit our proposal. The following is the description. Please, help me if you know any thing about it.
Currently, we are not using GSM modem but CDMA. Because we cant find GSM modem in our area. We also found that a lot of applications that are done using Java MIDI, that are for mobile applications. We also found a tool, Netbeans for developing our software. But there is one thing. We got an application which send and receives SMS messages. But we cant view the SMS message. It is encrypted or I dont know about it. I also found that if I use a port number for it, it will be easy. So we have also found an application which uses GSM and works on serial port.
The problem is we are now using USB (the CDMA works like a flash .... it uses USB port)port not serial port. and the application is not working for us. So, if you know, please, how can use USB port to send data using this CDMA device. By the way we also used Hyperterminal on Windows 7 to work on with this application.
I hopt to hear from u soon. Bye
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Hi,
I have a DataGridView control on a POS application I am writing as a project. I am having issues when trying to remove certain items from the control. Below is an example :-
1 Item 1 $5.00
-Extra 1
-Extra 2
1 Item 2 $10.00
1 Item 3 $2.00
-Extra 1
I want the user to be able to click on an item (or extra) in the datagridview and delete it. I can do this for single items and extras and it works perfectly (using removeat)but when I select an item, I want to check if there are any "extras" associated with the item and remove them aswell. Extras are always immediately below the item in question. My stumbling point seems to be when I remove 1 using RemoveAt, the index numbers change and I get exceptions.
This datagridview is not bound to any datasource and I am creating it on the fly.
Any help with the logic would be muchly appreciated.
Thanks,
Daniel.
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/// My stumbling point seems to be when I remove 1 using RemoveAt, the index numbers change and I get exceptions.
delete items upward from bottom to top of datagrid
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When you delete an item in a list, any list, the indexes of the remaining items may change. There are two easy ways to cope with that:
1. not moving at all: assuming a range of items may have to be deleted, if the first item the be deleted is at index x, use RemoveAt(x); and continue testing for more removals at the same index x, as each removal there will decrement the index of all the # subsequent items by one.
2. working backwards: first determine the range to be deleted, without actually deleting anything; then delete from high index to low index; this also works when the items of interest aren't consecutive.
Beware, whatever you choose to do, a foreach will fail as an enumerator becomes invalid (and will throw an exception) when the collection gets modified.
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its a c# desktop application...i have items in flowlayout panel at form load event from db....i have to sort them ascending or descending order at run time... means user can view those items in ascending or descending order...can anyone help me how i do that..
regards tanzeel
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If you are getting the data from a DB then, assuming you are using a query to do so, investigate the ORDER BY keyword.Here[^] is one reference.
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
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I understand that you populate items in flowlayout panel
but my dear friend just tell me which control are you using
to populate the items...
So that it is easier to give you solution
Jinal Desai - LIVE
Experience is mother of sage....
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here is my code:
using System;
class one
{
public int a;
int f;
public bool e(int i)
{
for (f = 2; f <= i; f++)
{
if (i % f == 0)
{
return false;
}
else
{
return true;
}
}
}
}
class control
{
public static void Main()
{
one obj = new one();
Console.WriteLine("ENTER THE NUMBER TO BE CHECKED(SHOULD BE GREATER THAN 2)");
int o=obj.a = int.Parse(Console.ReadLine());
obj.e(o);
if (obj.e(o))
Console.WriteLine("THE VALUE IS PRIME");
else
Console.WriteLine("THE VALUE IS NOT PRIME");
}
}
now when i debug this program it returns an error "not all code paths return a value" pointing at e.
and gives a warning at f++ in the for statement "unreachable".....what is the fault??
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By looking at your code, it seems that you have written a program to checked whether entered number is prime or not.
I am sorry my friend but logic of this program is incorrect.
wjbjnr wrote: not all code paths return a value
This error is coming because its not returning anything if program control doesn't entered inside "for" loop.
You have to make your logic correct.
P.S: Please provide code snippets in code block, it enhances readability of code.
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I'll reformat your code so that we can read it:
using System;
class one
{
public int a;
int f;
public bool e(int i)
{
for (f = 2; f <= i; f++)
{
if (i % f == 0)
{
return false;
}
else
{
return true;
}
}
}
}
class control
{
public static void Main()
{
one obj = new one();
Console.WriteLine("ENTER THE NUMBER TO BE CHECKED(SHOULD BE GREATER THAN 2)");
int o=obj.a = int.Parse(Console.ReadLine());
obj.e(o);
if (obj.e(o))
Console.WriteLine("THE VALUE IS PRIME");
else
Console.WriteLine("THE VALUE IS NOT PRIME");
}
}First of all, why f++ is unreachable. In your code, the for loop will always exit after the first run through - there is no way for it not to. Remove the return true to outside the loop and you'll solve both parts of your problem - the loop condition will be reachable and the code will return a value from all parts.
[Edit]I just want to point out that you need to code for an edge case here. What happens if I put 0 in as a value? The code will never enter the loop and will incorrectly report out that it's a prime number. You should add a check in here to ensure that it's not less than 2 and return the value accordingly.
"WPF has many lovers. It's a veritable porn star!" - Josh Smith As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.
My blog | My articles | MoXAML PowerToys | Onyx
modified on Monday, May 10, 2010 7:27 AM
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take a look at this code..
using System;
class one
{
public int a;
int f;
public bool e(int i)
{
if (i <= 2) return false;
}
}
class control
{
public static void Main()
{
one obj = new one();
Console.WriteLine("ENTER THE NUMBER TO BE CHECKED(SHOULD BE GREATER THAN 2)");
int o = obj.a = int.Parse(Console.ReadLine());
obj.e(o);
if (obj.e(o)) Console.WriteLine("THE VALUE IS PRIME");
else
Console.WriteLine("THE VALUE IS NOT PRIME");
}
just look at the upper portion....it still doesnt return a value and gives the same error
now look at this code
using System;
class ChkNum {
// Return true if x is prime.
public bool IsPrime(int x) {
if(x <= 1) return false;
for(int i=2; i <= x/i; i++)
if((x %i) == 0) return false;
return true;
}
}
class ParmDemo {
static void Main() {
ChkNum ob = new ChkNum();
for(int i=2; i < 10; i++)
if(ob.IsPrime(i)) Console.WriteLine(i + " is prime.");
else Console.WriteLine(i + " is not prime.");
}
}
now look at this code(the upper section)..in this also it uses "if(x &lt;= 1) return false;"
in this code this statement works...but not in the first one...why is that!!
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well in the first case there is still a path through the method that doesnt assign a return value you know its like what if i is more than 2 let me just break off here to say how difficult it is to read unformatted code whatever thats just me in the second case all paths through the method assign a return value hope thats cleared things up for u
[EDIT fixed typo]
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While the other both answers are correct, I only want to mention the reasoning behind it.
The code considers all possible exits in a program and if it doesn't achieve the desired result in it, it raises an error.
In your for loop, you have trapped all possible outcomes. So, whatever the number f be, there will be an answer. But what happens when the code doesn't enter the loop? what if i = 1?
Hence, there should be one more return statement after the loop ends.
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take a look at this code..
using System;
class one
{
public int a;
int f;
public bool e(int i)
{
if (i <= 2) return false;
}
}
class control
{
public static void Main()
{
one obj = new one();
Console.WriteLine("ENTER THE NUMBER TO BE CHECKED(SHOULD BE GREATER THAN 2)");
int o = obj.a = int.Parse(Console.ReadLine());
obj.e(o);
if (obj.e(o)) Console.WriteLine("THE VALUE IS PRIME");
else
Console.WriteLine("THE VALUE IS NOT PRIME");
}
just look at the upper portion....it still doesnt return a value and gives the same error
now look at this code
using System;
class ChkNum {
// Return true if x is prime.
public bool IsPrime(int x) {
if(x <= 1) return false;
for(int i=2; i <= x/i; i++)
if((x %i) == 0) return false;
return true;
}
}
class ParmDemo {
static void Main() {
ChkNum ob = new ChkNum();
for(int i=2; i < 10; i++)
if(ob.IsPrime(i)) Console.WriteLine(i + " is prime.");
else Console.WriteLine(i + " is not prime.");
}
}
now look at this code(the upper section)..in this also it uses "if(x <=1) return false;"
in this code this statement works...but not in the first one...why is that!!
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IMPORTANT:
Use 'pre' tags for your code. without those tags, the code is totally unreadable. Also, do preview your post. There are many errors in your post.
Now, the second code works because it considers all possible values of x. if it is less than 1, it returns false. otherwise, for all other values, it can be either true or false.
try changing the code to x<=0
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that maybe...but i just wrote this code in the upper section
public bool e(int i)
<pre> {
<pre> if (i <= 2)
<pre> return false;
<pre> }
even then it gives the same error!!!....wats wrong in this code??
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because the method returns a value only when i<=2. what if i>2? think how the code will proceed? where does the code get return statement if i>2?
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alrite.....see this code
using System;
class one
{
public int a;
// Return true if x is prime.
public bool e(int x)
{
if (x <= 2 && x>=0) return true;
for (int i = 2; i<;x; i++)
if (x % i == 0) return false;
return true;
}
}
class control
{
public static void Main()
{
one obj = new one();
Console.WriteLine("ENTER THE NUMBER TO BE CHECKED(SHOULD BE GREATER THAN 2)");
int o = obj.a = int.Parse(Console.ReadLine());
obj.e(o);
if (obj.e(o))
Console.WriteLine("THE VALUE IS PRIME");
else
Console.WriteLine("THE VALUE IS NOT PRIME");
}
}
now see this code.....
using System;
class one
{
public int a;
public bool e(int i)
{
if (i <= 2 && i >= 0) return true;
for (int f = 2; f<i; f++)
<p=""> {
if (i % f == 0)
{
return false;
}
else
{
return true;
}
}
}
}
wats the difference between the two???
the upper one works the lower one gives the same error!!!
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What are you trying to do here buddy? Are you trying to prove that your inefficient coding techniques are right and C# language is incorrect?
Every programming language has a syntax. You need to follow them in order to use it.
You need to ask these questions yourself and tell us why one code works and why the other doesn't. When you can find the reason yourself, you will be able to write the correct code from next time onwards.
All the best.
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i'm nt condeming any body.....
i just dont understand the difference...the syntax and logic in both codes are same..but one gives the error and the other doesnt....never before i have encountered such a problem....there is another way to do this program...but i wanted to use return types....and now it gives this error ....i am greatful to all your replies!!!
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public bool e(int x)
{
if (x <= 2 && x >= 0) return true;
for (int i = 2; i >= x; i++)
if (x % i == 0) return false;
return true;
}
This is your first piece of code which works. I have only reformatted it to see the code flow. Here, for every value of x, there is a return path available. Hence this one is a legal code.
public bool e(int i)
{
if (i <= 2 && i >= 0) return true;
for (int f = 2; f <= i; f++)
{
if (i % f == 0)
{
return false;
}
else
{
return true;
}
}
}
As correctly pointed out by the compiler, not all paths return the value. Hence the code syntax is incorrect.
I suggest you think a bit more logically to see the difference in two cases. I also suggest to take a break from coding. it happens sometimes when you have done coding for a very long time. trust me.
Som
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They are not the same.
They just look it because you don't see what is happening.
Indenting your code shows why they are different:
public bool e(int x)
{
if (x <= 2 && x>=0)
return true;
for (int i = 2; i<;x; i++)
if (x % i == 0)
return false;
return true;
}
and
public bool e(int i)
{
if (i <= 2 && i >= 0)
return true;
for (int f = 2; f <= i; f++)
{
if (i % f == 0)
{
return false;
}
else
{
return true;
}
}
}
In the first case, there is always a return statement - in every exit path.
In the second case, the compiler assumes there is an exit path at the end of the loop that does not have a return statement. It doesn't need one, because your loop is crap - it will always return on the first iteration. But the compiler doesn't know that. It does not look at "i % 1" and say: that will always be 0 or 1, so there is a control path that ends in a return for all cases. It just looks and sees a control path after the loop that will never include a return.
Surprisingly, the compiler is not as intelligent as you.
I have learnt that you can not make someone love you, all you can do is stalk them and hope they panic and give in.
Apathy Error: Don't bother striking any key.
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