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Please ask stupid questions/make stupid statements in Q&A please. This is my refuge.
Regards,
Rob Philpott.
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No, it's already full of them.
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1. Take your computer into the pharmacy
2. Load Visual studio
3. Create a C# program
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I'm an optoholic - my glass is always half full of vodka.
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Chris Quinn wrote: Take your computer into the pharmacy
One with free wifi.
There are only 10 types of people in the world, those who understand binary and those who don't.
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You don't need wifi to program in C#
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I'm an optoholic - my glass is always half full of vodka.
=========================================================
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Are you sure? 
How else do you get to QA? You so silly.
Actually, with VS online you would now. 
There are only 10 types of people in the world, those who understand binary and those who don't.
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You need you're head examined if you think anyone is going to write your code for you.
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This seems to be a general trend in this forum, (or is it just me?). There seems to be a plethora of entries from people with names like 'member xxxxxxx' where xxxxxx is a big number, asking for programmes to be written for them, usually written in bad english. What's going on here?
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We are happy to help answer questions but you it appears you don't have a single question but need to hire someone. I would search google for sites where you can hire a developer.
There are only 10 types of people in the world, those who understand binary and those who don't.
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Even if you PAID us to do it, we couldn´t. There is no specification whatsoever.
Alternitavely you can wait until telepathy is possible in which case we can read your mind and know what your talking about.
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I tried this
public sealed class sample
{
public sample(){}
public add(object item)
{
}
public add<T>(T item)
{
PropertyInfo[] pi;
}
}
now when i created new object of it and call the first add, i end up the second add has been called
sample
sample s = new sample();
string newString = "sample string";
s.add(newString);
i try to debug it to track how the process goes but it called the add<t>(t item) method.
even in the intellisense, when i point my cursor the s.add(newString), it would say sample.add<string>(string item) something like that.
what is that happening?
i will appreciate for any help will come thank you
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As you have a method with an object, and a method that is accepting a generic, unless you actually specify object as your type, your code will resolve to the generic. You can think of this as being because the string is a more specialized type than an object, so while it is derived from object, it is NOT of type object. So, if you want to call the first method, you would do:
object newString = "sample string";
s.add(newString); Oh, one small point, your class won't compile because you haven't specified the return type of your add methods.
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ops i forgot the return type.
BTW thank you so much, now it is clear to me why is that happen.
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You're welcome. I'm glad I could help.
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Out of interest, do you know what would happen in that example if the add method took a string rather than object? I don't although I'm pretty sure I've come up against this before.
Regards,
Rob Philpott.
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Base on Pete O'Hanlon answer, I am pretty sure that it will call the first method.
Gonna try it.
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Could be, but its veering towards the 'undefined' where what it does now may change with different versions of compiler/framework etc.
Regards,
Rob Philpott.
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Looking at the C# specification, section 7.5.3.2:
7.5.3.2 Better function member[ ^]
... the following tie-breaking rules are applied, in order, to determine the better function member:
- If MP is a non-generic method and MQ is a generic method, then MP is better than MQ.
- ...
In other words, if two candidate methods are found, and one is generic but the other isn't, then the non-generic method is always chosen.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Outstanding. 
Regards,
Rob Philpott.
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It would call the string based method because that was the most specialised version it could call.
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It's a really bad idea to do this for exactly the reason you describe here: it's totally unobvious which of those two methods will be called in what context. (I think Pete is right, I think the first will be called if and only if the parameter has a compile time static type of object and not a subclass, but that's confusing and unclear.)
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I have more than 4 year experience so can i move to consultant profile, if yes please let me know , How can i do this? Give me some some ideas.
Thanks in Advance.
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Pramod Kumar Singh 2010 wrote: Give me some some ideas
ahm, wrong forum? 
Don't mind those people who say you're not HOT. At least you know you're COOL.
I'm not afraid of falling, I'm afraid of the sudden stop at the end of the fall! - Richard Andrew x64
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Looking at your messages in CP, ... well, sorry, ... I think you mix up "time" and "experience".
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