C / C++ / MFC

ClassA::ClassA( const ClassA &from)
     :member1( from.member1 )
     ,member2( from.member2 )
     ,.... etc
{}

......
CC operator+( CC &source ) const;
......
CC CC::operator+( CC &source ) const   
{
     CC result = *this;
     double sum = source.Query_X() + X;
     result.Set_X( sum );
     return result;
}

int* x = new int[1000];

void foo(int i)
{
   if(i>0 && i<1000)
   {
      x[i] = 0;
   }
   else
   {
      // print error.
      // assert.
      // throw an exception.
   }
}

CPallini wrote:

Possibly documentation helps.

Luc Pattyn [Forum Guidelines] [My Articles]

---

Voting for dummies? No thanks.

---

int main()
{
    char *abc[10][10];
    char *def[10];
    int i = 0;

    def[0] = "String 0";
    def[1] = "String 1";
    def[2] = "String 2";
    def[3] = "String 3";
    def[4] = "String 4";
    def[5] = "String 5";
    def[6] = "String 6";
    def[7] = "String 7";
    def[8] = "String 8";
    def[9] = "String 9";


    // Method 1 - copy strings themselves
    printf("Method 1 - copy strings themselves\n");
    printf("----------------------------------\n");
    for (i=0; i<10; i++)
    {
        abc[0][i] = malloc(strlen(def[i])+1);   /*-- try commenting this line out --*/
        strcpy(abc[0][i], def[i]);
    }
    for (i=0; i<10; i++)
    {
        printf("%s\n", abc[0][i]);
        free(abc[0][i]);
        abc[0][i] = NULL;
    }
    printf("\n\n");


    // Method 2 - just copy pointers to the strings
    printf("Method 2 - just copy pointers to the strings\n");
    printf("--------------------------------------------\n");
    for (i=0; i<10; i++)
    {
        abc[0][i] = def[i];
    }
    for (i=0; i<10; i++)
    {
        printf("%s\n", abc[0][i]);
    }

}