#include <stdio.h> int main() { int a=(1, 2, 3); int b=(3, 2, 1); for(; a>0; a--) for(; b<3; b++); printf("%d ", a*b); return 0; }

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I have tried a lot but I didn't get solved will you help me out with this
thank you...!!

C++

#include <stdio.h> 
int main() 
{   
  int a=(1, 2, 3);   
  int b=(3, 2, 1);   

  for(; a>0; a--)      
    for(; b<3; b++);        

  printf("%d ", a*b); 

  return 0; 
}

What I have tried:

want expiation with suitable figure

Posted 24-Oct-17 7:20am

Member 13483115

Updated 24-Oct-17 8:15am

PIEBALDconsult

v3

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CPallini 24-Oct-17 15:55pm

OUt of curiosity, where did you find such a code?

2 solutions

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C^hris L^osinger · Answer 1 · 2017-10-24T07:57:00

Solution 1

Look into C's comma operator. When you know how that works, you will know what a and b will be initialized to.

Posted 24-Oct-17 7:57am

C^hris L^osinger154.1K

Comments

CPallini 24-Oct-17 15:54pm

5.

OriginalGriff · Answer 2 · 2017-10-24T08:15:00

The Comma operator looks like this:

C++

x = a, b;

It evaluates the expression a, discards the result, evaluates b and returns it.
So the code for a and b both get executed, and x is set to the value of b.

Your code is just an extension of that: effectively

C++

x = ((a, b) , c);

So it evaluates a and b, then evaluates c and sets x to that value.
I.e. Your code is:

C++

int main() 
{   
  int a = 3;   
  int b = 1;   
 
  for(; a>0; a--)      
    for(; b<3; b++);        
      printf("%d ", a*b); 
  return 0; 
}