Convert 8bit ASCII to 6bit

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Hi,

I am trying to take a char and convert it to 6 bit binary. Any idea how one can do this in C#. Here is what I have so far.

C#

char c = '1';
int i = Convert.ToInt32(c);
while (i > 40)
    i -= 8;
Console.WriteLine(Convert.ToString(i, 2));
Console.ReadLine();

The result for this is '100001', where it should be '000001'.

Any ideas?

Posted 23-Nov-11 10:21am

DominicZA

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Richard MacCutchan · Answer 1 · 2011-11-23T10:31:00

Solution 1

In your example the ASCII character '1' is 0x31 hex or 11 0001 in binary which is already 6 bits. However the character 'A' is 0x41 hex or 100 0001 in binary, which is 7 bits. How exactly do you expect to convert that to 6 bits without losing its definition?

Posted 23-Nov-11 10:31am

Richard MacCutchan

Comments

DominicZA 23-Nov-11 16:36pm

I am trying to create an AIS decoder using this tutorial: http://www.bosunsmate.org/ais/

Maybe you can help me understand it a bit better?

Richard MacCutchan 23-Nov-11 17:04pm

Sorry but I don't know what an AIS decoder is, and I am not going to be following that link. Maybe you should talk to the author of the tutorial.

Michel [mjbohn] · Answer 2 · 2011-11-23T11:24:00

Try this:

C#

private string ascii2ais(string p)
        {
            StringBuilder sb = new StringBuilder();

            char[] chars = p.ToCharArray();
            foreach (char c in chars)
            {
                int i = Convert.ToInt32(c);
                i -= 48;
                if (i>40)
                {
                    i -= 8;
                }

                string sixBit = Convert.ToString(i, 2).PadLeft(6, '0');
                sb.Append(sixBit + " ");
            }

            return sb.ToString();

        }

This should do the trick. At least I tried that 14eG is translated to '000001 000100 101101 010111'