Load XML File for what it contains into textboxes

Question

3.00/5 (2 votes)

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IM GOING CRAZY !!!

here's is my situation i can write xml w/o anyproblem example

VB

dim xmlwrt as xmlwriter = xmlwriter.create("C:\sample.xml", settings)

with xmlwrt
.writestartdocument()
.writestartelement("employee")

'Employee Data
.WriteStartElement("FirstName")
.WriteString(nametxt.text.tostring())
.WriteEndElement

same for lastname and address and employer card

lets say the employercard is 123456

now i want to create a BUTTON the load whats on "C:\sample.xml" by what it contains

example:

Textbox1.text = "123456"
Button1 = acceptbutton

then brings all the information is on that "C:\sample.xml" back to the TextBoxes
FirstName
Lastname
employercard
in case the i have to save it i just have to change something and click the button save on that design again to save the XML with the new data

Any help will be great!!!

Posted 5-Aug-12 14:15pm

jitforce2585

Updated 5-Aug-12 14:26pm

Wes Aday

v2

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Comments

[no name] 5-Aug-12 20:28pm

I see a lot of "I want"... You want does not make a question. If you want to do all this then go right ahead and do it. You have my permission.

jitforce2585 5-Aug-12 20:48pm

Thanks for your permission and you right i want does not make a question so i guess i dont have a question..

Christian Graus 5-Aug-12 20:30pm

He also emailed me...

jitforce2585 5-Aug-12 20:48pm

Like i said sorry to bother you and i didnt mean to email you all the time i just needed some help wont happens again man

Christian Graus 5-Aug-12 20:55pm

And to be clear, I am very happy to help, I just like to limit the free help I give people to what is public on these boards. Feel free to ask me questions if you get stuck after working through the links in my answer

jitforce2585 5-Aug-12 20:59pm

ok thanks im trying to get the source code beginning from there i will keep going i just need the start code

2 solutions

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Kenneth Haugland · Accepted Answer · 2012-08-05T15:14:00

Here is how you could read an XML file:

VB

Dim name as string

Public Sub Load(ByVal p_XMLfilename As String)
       XMLFilename = p_XMLfilename

       Dim x As New System.Xml.XmlDocument
       x.Load(p_XMLfilename)

       Dim x_nodes As System.Xml.XmlNodeList = x.SelectNodes("employee")
       For Each node As System.Xml.XmlNode In x_nodes

           For Each node2 As System.Xml.XmlNode In node
               Select Case node2.Name
                   Case Is = "FirstName" : name = node2.InnerText

               End Select
           Next

       Next
   End Sub

Christian Graus · Accepted Answer · 2012-08-05T14:18:00

Solution 1

What have you tried ? Do you know how to use LINQ to XML[^] or the XmlDocument[^] class to read and parse XML ? Do you know how to use the OpenFileDialog[^] class ?

Posted 5-Aug-12 14:18pm

Christian Graus

Comments

Christian Graus 5-Aug-12 20:32pm

I'm sorry, I never answer emails because, well, then you'd have my email and feel free to email me questions all the time. Also, it would mean that no-one else could find the solutions on this forum. So, instead of emailing me the same question, look at my answer and read the documentation I've linked to. You emailed me that you're 'GOING CRAZY', but what you want is trivial, and I've linked you to the documentation for the objects you need. By all means, comment here if you have more questions, I am more than happy to help you if you apply yourself to the thing I've told you and get stuck again. But, this is all the answer I can give right now, unless I went and wrote all the code for you and if I did that, experience tells me you'd paste it without understanding it, and be asking similar questions here in no time.

jitforce2585 5-Aug-12 20:51pm

Thanks you and you are right about if the copy / paste but i just needed a clue and from there ill take it i dont need the entire code but let me try to get it from what you gave me ... thanks again