C# error : already defines a member called 'Fan' with the same parameter types"

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C#

class Fan
    {
         class Fan
    {
        private int speed = 1;
        private bool on = true;
        private double raduis = 5.0;
        private string color = "blue";

     

        public int spee { get { return speed; } set { speed = value; } }
        public bool o { get { return on; } set { on = value; } }
        public double radu { get { return raduis; } set { raduis = value; } }
        public string colour { get { return color; } set { color = value; } }

        public Fan(int speed, bool on, double raduis, string color)
        {
            this.speed = speed;
            this.on = on;
            this.raduis = raduis;
            this.color = color; 
        }
        public Fan(int se)
        {
            speed = se;
        }
        public Fan(int se , bool t )
        {
            speed = se ;
            on = t;
        }
        public Fan(int se, bool t , double r)
        {
            speed = se;
            on = t;
            raduis = r;
        }
        public Fan(int seo, bool to, double ro, string ce)
        {
            speed = seo;
            on = tp;
            raduis = ro;
            color = ce;
        }
        public string DisplayFan()
        {
            String printme = null;

            if (fan.on = true)
            {
                printme = ("Speed: " +  get.spee() + " Color: " + fan.color + " Radius: " + fan.radius);
            }
            if (fan.on = false)
            {
                printme = ("Color: " + fan.color + " Radius: " + fan.radius + " Fan is Off");
            }

            return (printme);

        }

        }
     static void Main(string[] args)
        {
            Fan f1 = new Fan();
            f1.spee(3);
            f1.radu(10.0);
            f1.colour("Yellow");
            f1.DisplayFan(true);

            Fan f2 = new Fan();
            f2.spee(1);
            f2.radu(5.0);
            f2.colour("blue");
            f2.DisplayFan(false);
        }
    } 

    }

C# error:

already defines a member called 'Fan' with the same parameter types"

Posted 17-Dec-12 3:46am

zaak taylor

Updated 20-Dec-12 21:01pm

v4

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Comments

lukeer 21-Dec-12 5:32am

I assume this is the second time you ask this question, re-phrased. If it's the other way round, same applies nonetheless: Don't post the same question again. Use the "Improve question" link instead to provide further information. It helps keeping the topic together.

3 solutions

Solution 2

Look at your code, you have the following constructors:

C++

        public Fan(int speed, bool on, double raduis, string color)
        {
            this.speed = speed;
            this.on = on;
            this.raduis = raduis;
            this.color = color; 
        }

// 3 others removed for clarity

        public Fan(int seo, bool to, double ro, string ce)
        {
            speed = seo;
            on = tp;
            raduis = ro;
            color = ce;
        }

You cannot have two with the same signature, remove the one that you do not want.

Posted 20-Dec-12 23:50pm

Richard MacCutchan

Solution 3

I am getting this error in one of the silver light application which works fine in VS2010 bu when i oprned it in VS2013 its giving this error for all the initialize methods and also the services are not getting reffered, my services works fine.

Posted 8-Aug-14 3:44am

Kiran Shivaramappa

Comments

[no name] 8-Aug-14 10:46am

Exactly how is this a solution to the question asked, a year and a half ago?

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fixthebugg · Accepted Answer · 2012-12-17T03:59:00

Solution 1

Isn't it self explaining ..

C#

public Fan(int seo, bool to, double ro, string ce)
{
speed = seo;
on = tp;
raduis = ro;
color = ce;
}

and

C#

public Fan(int speed, bool on, double raduis, string color)
{
this.speed = speed;
this.on = on;
this.raduis = raduis;
this.color = color;
}

Posted 17-Dec-12 3:59am

fixthebugg

Comments

CHill60 17-Dec-12 10:05am

Or to put it another way ...
Each overload of a function must have a unique signature so the compiler can determine which one you actually meant to call.
You have two functions both with (int, bool, double, string) signature. Luckily for you they appear to trying to do the same thing