How do I solve my dynamic menu bar and submenu creation using PHP and MYSQL problem?

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I am having a small problem. please help me to resolve it.

my code is displaying this error:

( ! ) Fatal error: Call to a member function fetch_array() on a non-object on line 44

this is my code:

PHP

<?php
$dbcon=mysql_connect("localhost","root","");
$link = mysql_connect('localhost','test',''); 
if (!$link) { 
	die('Could not connect to MySQL: ' . mysql_error()); 
} 
echo 'Connection OK'; mysql_close($link); 
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>front page</title>
<script type="text/javascript"  src="jquery-3.4.1.min.map"></script>
<link rel="stylesheet" type="text/css" href="style.css" media="all" />
</head>
<body>
<div id="head">
<div class="wrap"><br />
<h1 align="center">Create your own Menu Bar</h1>
<label><a href="add_menu.php">Click to Add Menu</a></label>
</div>
</div>

<div class="wrap">
<ul id="nav">
<li><a href="#">Homepage</a></li>
<?php
$res=$dbcon->query("SELECT * FROM main_menu");
while($row=$res->fetch_array())
{
 ?>
 <li><a href="<?php echo $row['m_menu_link']; ?>"><?php echo $row['m_menu_name']; ?></a>
 <?php
 $res_pro=$dbcon->query("SELECT * FROM sub_menu WHERE m_menu_id=".$row['m_menu_id']);
 ?>
        <ul>    
  <?php  
  while($pro_row=$res_pro->fetch_array())
  {
   ?><li><a href="<?php echo $pro_row['s_menu_link']; ?>"><?php echo $pro_row['s_menu_name']; ?></a></li><?php
  }
  ?>
 </ul>
 </li> 
 
<?php
}
?>
</ul> 
</div>
<script type="text/javascript">
$(document).ready(function() 
{
 $('#nav li').hover(function() 
 {
  $('ul', this).slideDown('fast');
 }, function() 
 {
  $('ul', this).slideUp('fast');
 });
});
</script>
</body>
</html>

What I have tried:

it is giving me error at this:

while($row = $res->fetch_array())

Posted 9-Jan-20 9:04am

User 14674545

Updated 9-Jan-20 10:59am

Patrice T

v4

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2 solutions

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MadMyche · Answer 1 · 2020-01-09T11:00:00

It appears you are mixing MySql APIs and/or styles; which are incompatible with one another.

This is using the old mysql API: $dbcon=mysql_connect("localhost","root","");
While this appears to be either mysqli or PDO while($row = $res->fetch_array())

I am a master of neither MySql nor PHP... so you may need to do some further research. I would recommend you review these links:
PHP: Choosing an API - Manual[^]
PHP: mysqli_result::fetch_array - Manual[^]

Kris Lantz · Answer 2 · 2020-01-09T09:20:00

Solution 1

I know little of PHP, but the top answer here might be of use. It's possible $dbcon has not been declared correctly. PHP and MYSQLI Error, Call to a member function query() on a non-object - Stack Overflow[^]

Posted 9-Jan-20 9:20am

Kris Lantz

Updated 9-Jan-20 9:21am

v2

Comments

[no name] 9-Jan-20 15:29pm

i have solved that isssue. now it is giving me a new error:

Fatal error: Call to a member function fetch_array() on a non-object on line 44
here is the line 44

while($row = $res->fetch_array())

Kris Lantz 9-Jan-20 15:49pm

Where is $res fetching an array from? Does fetch take a param?