To string Trims leftmost Zero

Question

2.00/5 (1 vote)

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Convert.tostring() trims leftmost 0

ex.
int x= 01234
Convert.tostring(x)
results into 1234 and not 01234
Any suggestions
Thanks

Posted 14-Jan-13 20:08pm

ersumitsahu

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4 solutions

Solution 2

You can use TrimStart(). So when you converted it to string

C#

string _YourText = "01234";
_YourText = _YourText.TrimStart(new Char[] { '0' } );

--or--

C#

_YourText = _YourText.TrimStart('0');

String.TrimStart Method In MSDN[^]

Good luck,
OI

Posted 14-Jan-13 20:15pm

Orcun Iyigun

Updated 14-Jan-13 20:17pm

v2

Solution 1

HI,

you can use like this:

C#

String a = "000454332";
a=a.TrimStart('0');
int b = Convert.ToInt32(a);

Thanks

Posted 14-Jan-13 20:14pm

sisir patro

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Aarti Meswania · Accepted Answer · 2013-01-14T20:38:00

integer variable will not consider Leading zeroes
so that
if you will assign
01234 to integer variable it will automatically save it in x variable as 1234

so, add leading zeros after converting x to string

C#

string myString = String.Format("{0:00000}",x) // this will add leading zeros in a way that passed number will be have minimum 5 digits e.g. 123 -> 00123

Happy coding!
:)

OriginalGriff · Accepted Answer · 2013-01-14T20:30:00

Solution 3

Integer values ignore all leading zeros: 01234 is teh same as 1234, is the same as 00000000000000000000000000001234
You need to format the ToString operation:

C#

int x = 01234;
Console.WriteLine(x.ToString());
Console.WriteLine(x.ToString("D5"));

Will print:

1234
01234

Posted 14-Jan-13 20:30pm

OriginalGriff

Comments

fjdiewornncalwe 15-Jan-13 9:50am

+5. This is the correct answer.