How To Check That I Connected To The Internet Or Not

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hi friends.

i developed a program that i want to when user connect to the internet some data be send to his email address.how can i know that i connected to internet or not.

thank you.

Posted 7-Aug-14 5:35am

_Starbug_

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Neetin_1809 · Answer 1 · 2014-08-07T09:07:00

Solution 2

Hello ,
As far as i know you Need to use system.net namespace.Lot of articles are being available.Check this links
InternetResponse

Best way

a article is available on code project you can refer this:Article

Hope this can solve your problem.
Happpy Coding :-)

Posted 7-Aug-14 9:07am

Neetin_1809

Comments

_Starbug_ 7-Aug-14 15:30pm

thanks

rameeznoormahal · Answer 2 · 2014-08-07T05:38:00

Solution 1

Try to send it to first in your mail id for trail

Posted 7-Aug-14 5:38am

rameeznoormahal

Comments

_Starbug_ 7-Aug-14 11:43am

this is very good answer that i see. boy first of all read question carefully after that answer it. i want to check internet connection status.i want to know i connected to the internet or not.

PIEBALDconsult 7-Aug-14 12:58pm

Generally, that's not a very reasonable thing to do. The thing is, you can check, and maybe the check succeeds. Then the connection dies. Then you try sending and the send fails -- you have to handle that, so the check was a waste of time.
Or you check and the check fails, but then the connection recovers.

Whether you're checking for network or database or a file or disk, it's better just to try it and see whether or not it fails. Doing otherwise is just a waste of effort, in time, in development, in testing, in maintenance.

In the case you mention, what if the connection is live, but the SMTP server isn't or refuses the connection? There are a lot more things that can go wrong than just "no connection to the Internet".

Try it, and handle any Exception that results -- you have to anyway.

_Starbug_ 7-Aug-14 13:48pm

i solved this problem my self. i want to see if the connection is open then send my file instead of send file and see that there is not any open connection. first way is smarter.