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this time i defined i globaly but still having the same problem...is there any problem in the insert statement??
have i written the sql command rite??/
$h@ma!|@
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hi,
i am using a report viewer control in my application.i have many records with the same value in name column.i have to group the name n display it once in the report with its other details
ex:
name job
zari swengineer
swtester
businessanalyst
zari
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Are you making use of the Crystal Report Wizard to create your report or are you creating your report in code? This you have to do in the report itself, since the viewer only do what it says: View.
There is 2 solutions.
You can either create a grouping for that field
OR
You can sort that field so that all that names are together then you format that field to tell him to suppress duplicates. That way you will see the name once.
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Hi,
I'm using MS Access 2003 database with c#.net 2003. Now I've a comobo, in which department name are shown and onchangeindex i use to get department code, show i textbox. Now the problem is this when i add department no 11 in the database, my comobox stop working and i got javascript error:
Error:Invaild Syntax in statusbar.
Kindly help where i made a mistake ( In web code or database) I use normal database settings.
Thanks
|Muhamad Waqas Butt|
waqasb4all@yahoo.com
www.sktech.freewebspace.com
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Please post your code or run your application with the Break point and try to locate in which line the error shows.
We are not magic man without seeing the code how can we tell where the error is.
Regards,
Satips. ![Rose | [Rose]](https://codeproject.freetls.fastly.net/script/Forums/Images/rose.gif)
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Here is a code:
try
{
string cmdstr="SELECT * FROM tablename where dp_head='"+ dpdhead.SelectedValue +"'";
con=new OleDbConnection(cons);
cmd=new OleDbCommand(cmdstr,con);
con.Open();
OleDbDataReader dr = cmd.ExecuteReader();
bool chkrec = dr.Read();
if(chkrec == true)
{
string dasv = dr.GetInt32(0).ToString();
txtacno.Text = dasv;
}
//
Output
'/LM/w3svc/1/root/expdemo-5-128280938191702288': Loaded 'c:\windows\microsoft.net\framework\v1.1.4322\temporary asp.net files\expdemo\280c9982\bd477ac7\gottf48d.dll', Symbols loaded.
// Now
|Muhamad Waqas Butt|
waqasb4all@yahoo.com
www.sktech.freewebspace.com
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You may be better off by using a Parameter List for your OleDBCommand Object.
replace your appropriate lines:
string cmdstr = "SELECT * FROM Tablename where field = @fieldvalue;";
cmd = new OleDBCommand(cmdstr,con);
cmd.Parameters.AddWithParameter("@fieldvalue",dpdhead.SelectedValue);
Parameter Lists help organization And is another obstacle for Hackers.
Also look to this:
string dasv = dr[0].ToString();
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Respected Gurus
I m using following code to import data from an excel file..
It works fine except one problem that
whenever i m trying to delete the file which i have saved on the server by using
file.delete(strfilename)
i left with the error "you do not have permission"
I think i have not closed the excel file.
how can i close it programmatically so that i can delete it also.
Dim strfilename As String
' Check the first open file dialog for a value
If Not (Me.File1.PostedFile Is Nothing) Then
' Get a reference to PostedFile object
Dim attFile As HttpPostedFile = File1.PostedFile
' Get size of the file
Dim attachFileLength As Integer = attFile.ContentLength
'Make sure the size of the file is > 0
If attachFileLength > 0 Then
' Get the file name
strfilename = Path.GetFileName(File1.PostedFile.FileName)
'Preceed the file name with "attachments/" so
'the file is saved to our Project's attachments Folder
strfilename = "Uploads/" + strfilename
'Save the file on the server
File1.PostedFile.SaveAs(Server.MapPath(strfilename))
End If
End If
Dim strConnectionString As String = String.Empty
'----------------------------------------------------------
'strConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Driver=Microsoft Text Driver (*.txt;*.csv);Data Source=" + Server.MapPath(strfilename) + ";Extensions=asc,csv,tab,txt;Persist Security Info=False"
'----------------------------------------------------------
strConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Server.MapPath(strfilename) + ";Extended Properties=""Excel 8.0;HDR=Yes;IMEX=1"""
Dim cnCSV As New OleDbConnection(strConnectionString)
cnCSV.Open()
Dim cmdSelect As New OleDbCommand("SELECT * FROM [sheet1$]", cnCSV)
cmdSelect.CommandType = CommandType.Text
Dim daCSV As New OleDbDataAdapter
daCSV.SelectCommand = cmdSelect
Dim ds As New DataSet
daCSV.Fill(ds)
after using the dataset.
at last i am trying to delete the file.
which give me the error.
Please Help.
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please check out your system configuration. have your system has permission to delete any file. could be possible this.
Devjit
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Your web site runs under an app pool. That app pool has an identity. That user that the app pool is running as needs to be able to delete files in the correct directory. Often it makes sense to create a new app pool for each new web application. Then you can create a network user for that specific application and give that user the correct rights.
Ben
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Thanks sir
resolve it
was a permission issue.
given the rights and now working smoothly.
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I have developed a two way Client Server Chat Application using .Net Remoting. where Server Application have real IP but Client Application Donot have real IP. but my application is working in LAN Environment But CallBack and deleget is not working in real world scenario.
Pavan Pareta
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can i personally talk to u.I need to talk to u about chat programatically.
my yahoo mail id is soniagupta1@yahoo.co.in.
i am waiting at yahoo messenger
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Hi Sonia Gupta,
here is not allowed any kind of messenger.
Pavan Pareta
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how to give runtime file name to file control
i have created file control at run time
FileUpload up = new FileUpload();
but i want to give its path in code view how will i give it
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if you wanna see the absoulte path you could use : fu.PostedFile.FileName;
or else you can use to get only file name you uploaded using that code : fu.FileName;
Hope it helps..'
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i want to copy file in web application i am using
File.Copy("c:/somefile.txt","http://makarand/Wow/Data/Origs/someotherfile.txt"
);
i am getting this error
URI formats are not supported
pls tell me what is an issue does and what should i do to copy the file
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man you gotta use Server.MapPath to point a place in your server.
-- modified at 8:13 Thursday 5th July, 2007
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i have did that. it works fine when i am working on my machine but it won't work wen i am using remote machine.
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i was trying to write the asp code in asp.net 2.0
the following code.
<% @Language=VBScript%>
<% Option Explicit %>
<%
set objRS=Server.CreateObject("ADODB.Recordset")
objRS.Open objConn
%>
but the set and get keywords ae not supported .
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u want to use property of asp.net.
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In asp.net 2.0 is based on C# language you gotta use properties as shown below :
private my_Name;
string MyName
{
get
{
return my_Name;
}
set
{
my_Name = value;
}
}
hope it helps...
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hi ...
I am writing the code in source file(design).
there i am trying to connect the application with the back end(sqlserver).
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Sonia Gupta wrote:
This doesn't work, you're using ASP.NET, not asp.
If you're using ASP, you're not using ASP.NET, and you're in the wrong forum. This sure is bringing back bad memories of asp, what makes you think you're using ASP.NET 2.0 ?
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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hi
i want generate gridview programmatically to but having a error in
hyp1.DataNavigateUrlFields = "link";
ERROR:- cannot implicitly convert type 'string' to 'string[]'
plzzzz help me
thanks in advance
DataTable dt = new DataTable("dtable");
DataRow dr1;
DataRow dr2;
dt.Columns.Add(new DataColumn("Text", typeof(string)));
dt.Columns.Add(new DataColumn("link", typeof(string)));
dr1 = dt.NewRow();
dr1[0] = "Yahoo";
dr1[1] = "http://www.yahoo.com";
dt.Rows.Add(dr1);
dr2 = dt.NewRow();
dr2[0] = "Google";
dr2[1] = "http://www.google.com";
dt.Rows.Add(dr2);
GridView GV = new GridView();
GV.AutoGenerateColumns = false;
HyperLinkField hyp1 = new HyperLinkField();
hyp1.HeaderText = "UsefulLinks";
hyp1.DataTextField = "Text";
hyp1.DataNavigateUrlFields = "link";
hyp1.Target = "_blank";
GV.Columns.Add(hyp1);
GV.DataSource = dt;
GV.DataBind();
plhPlaceHolder.Controls.Add(GV);
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