Algorithms

struct {<br />
   char findstring[64];<br />
   char licensename[64];<br />
   time_t licensedate;<br />
   time_t licenselen;<br />
   unsigned long crc32a;<br />
   unsigned long licensedfeatures;<br />
   char licensekey[64];<br />
} lincenseinfo;

nonadoes wrote:

123456789012%34

nonadoes wrote:

...there are always balance althought it shouldnt be.

Cyclone02 wrote:

I have been working on a project for several months now and it is almost finished all i need is some kind of security so that only the people that buy my software will be able to run it although when they first run it, it will display a key

Cyclone02 wrote:

Could you please point me to a good tut that explains encryption in general as i will start and put things together from there.

roberto_santinni wrote:

how to make a faster algorithm

while (!fastEnough()) {
    accelerate();
}

for(int j=0;j<plainTxt.Text.Length;j++)
{
 if(plainTxt.Text[j] == myAlphabet[i]) //if a plaintext char matches an alphabet char
 {
   numTimes++; //increase count for numTimes
   break; //found a match, so break out of inner loop, no use looking at the rest
 }
}

<code lang=cs>
private string DoCount(string input)
{
    string alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ01234567890\u0027\u002E\u002C\u003A\u003B\u003F\u0021\u0023\u0028\u0029";
// create hash-table for counters, set initial capacity to number of counters (characters in alphabet).
    Dictionary<char, int> counters = new Dictionary<char, int>(alphabet.Length); 
//initialize just to be safe:
    foreach(char c in alphabet)
        counters[c] = 0;
//count the characters in the input string:
    foreach(char c in input)
        if(counters.ContainsKey(c))
            counters[c]++;
//now output statistics
    string output = string.Empty;
    for (int i = 0; i < alphabet.Length; i++)
    {
        flost percent = 0.0F;
        char c = alphabet[i];
        int count = counters[c];
        if(count > 0)
             percent = (float)count / input.Length;
        output += string.Format("Letter {0} is displayed {1} times.  It is {2:P2} of the whole text.{3}", c, count, percent, Environment.NewLine);
    }
    return output;
}
</code>

- Xint0