Comments by nothingx11x

nothingx11x 29-May-15 19:28pm View

Now, my question status is not solve. I just want to ask you and everyone how to improve [1], [2], [3], [4]. What is the alternative way to implement the idea which changes from DerivType to double and conversely. Thank you

nothingx11x 29-May-15 18:46pm View

I am very appriciate if you can help me. If I can ask my teacher, it does not make sense I send a question here.

nothingx11x 28-May-15 17:22pm View

Do you mean I have to change the code of class DerivType. But in this case, can you tell me how can I change it. I am high appriciate your suggestions.
I just want to "convert" from DerivType to int.
Please help me.
Thank you

nothingx11x 28-May-15 14:58pm View

Thank for your response. But can you tell me how the new code is, I am sorry,I do not have any idea for new code. How can I fix it and say "convert" a DerivType to int variable. Thank you

nothingx11x 28-May-15 11:23am View

I am sorry to make disturb you.
The definition of MLPutInteger is MLPutInteger[pointer, int]. That means its second argument has to be an integer. In this case, I want to assign x into this argument, but in this case, x is DerivType. How can I convert x into integer?

nothingx11x 28-May-15 10:58am View

Deleted

This is the Class DerivType class DerivType;

typedef DerivType (*ddf_FctPtr)(const DerivType&);

class DerivType { private: interval f, df, ddf;

public: DerivType ( ); DerivType ( const interval&, const interval&, const interval& ); DerivType ( const DerivType& );

DerivType& operator= ( const DerivType& );

friend DerivType DerivConst ( const real& );
friend DerivType DerivConst ( const interval& );
friend DerivType DerivVar ( const real& );
friend DerivType DerivVar ( const interval& );

friend inline const interval fValue ( const DerivType& );
friend inline const interval dfValue ( const DerivType& );
friend inline const interval ddfValue ( const DerivType& );

friend DerivType operator+ ( const DerivType& );
friend DerivType operator- ( const DerivType& );

....

And I have a function likes this

DerivType f ( const DerivType& x ) // Sample function { DerivType result;

int sum;

MLPutInteger(lp, x); [1]

MLGetInteger(lp, &sum);
printf( "sum = %d\n", sum);
result = sum; [2]

return result; }

You see the error comes from [1] and [2]. Because, in the second argument of MLPutInteger is an Integer while x is DerivType. In [2], the sum is an integer while the result is DerivType. Please help me fix this code. How can I implement this idea. Thank you very much Yours sincerely,

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