Comments by Md Jamaluddin Saiyed (Top 47 by date)

:D no not at all !! Actually I am not much familiar with .net ! I am trying to learn it ! soon I will be migrate from vb6 to .net ! this is my old project in which i want to add one new report !!

the problem is when i debug with f8 its running completely but with f5 its works only first time ! when i pass another date its not work and i get blank datareport !!

I am Creating an application

Yes My forms Application started with Main form ! I have number of secondary forms and I wish to display First-Last-next-Previous buttons on each form ! I want to create user control library for this action

I want to use one public class in multiple forms. I want to make method for First-next-prev-Last buttons for my different forms! which can perform same action in different forms !!

Thanks for your reply sir . I am working on windows application software !! can you example me with code ?

Thanks for help sir ! I will try this code !!

Its showing blank msg

I have done it some time ago as per your reply but not working !!

Thanks for response to help me sir !! my code is here and its working now I dont know why its working

$(document).ready(function() {

$("#btn").click(function() {
var name = $("#inputname").val();
var email = $("#inputEmail").val();
var feed = $("#feedback").val();
var send = "InputName=" + name + "&InputEmail=" + email + "&Feedback=" + feed ;

$.ajax({

url:"Feedback_conx.php",
type:"POST",
data:send,
success: function(data1){
$("#disp").html(data1);
}
});
alert($.ajax());
});
});

I put $.ajax() after ajax request and its done !! why ? can you tell me ?

i have done it but i cant see msg !! its disappeared immediately

how to check

no

I have tried but its not working ! my html code is here <div class="row">
<form class="form-horizontal col-lg-5" id="frmfeed" name="frmfeed">
<fieldset>
Feedback
<div class="form-group">
<label for="inputEmail" class="col-lg-2 control-label">Name</label>
<div class="col-lg-10">
<input class="form-control" id="inputname" name="InputName" placeholder="Name" type="text">
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-2 control-label">Email</label>
<div class="col-lg-10">
<input class="form-control" id="inputEmail" name="InputEmail" placeholder="Email" type="text">
</div>
</div>
<div class="form-group">
<label for="feedback" class="col-lg-2 control-label">Feedback</label>
<div class="col-lg-10">
<textarea class="form-control" rows="3" id="feedback" name="Feedback"></textarea>

</div>
</div>
<div class="form-group">
<div class="col-lg-10 col-lg-offset-2">
<button class="btn btn-default" type="reset" name="cancelbtn" id="cancelbtn">Cancel</button>
<button type="submit" class="btn btn-primary" name="btn" id="btn">Submit</button>
</div>
</div>
</fieldset>
</form>
<div id="disp" class="col-lg-5">



</div>

</div>

I solved the problem with your help thank you very much sir !!!

Thanks a lot sir !! you solved my problem !! I could not found my mistake !!

I have checked but I found nothing like that!

I have done it but it still inserts two records !!

Thanks for your answer but I have posted data with php post method successfully I want to do it with jquery ajax $.post method !!

ok sir I tried to narrow down coding!! Thanks for your suggestions ! I learning jquery so I am not accurate in it !!

Ok thanks for solution first error solved but second still comes

now you can properly read the code ! Its edited !

Thanks for editing the code

Thanks for responding sir ! There is no problem sir !! but I want to learn about it ! I am new to php !! we have project about social networking in out college !!

Want to update particular record whose srno is given in TxtEdit textbox

Thanks !! can you suggest solution for it or Give me example of above question using two things in one button

This method is working same as data reader I want to change header text !! When I trying to do that error " Index was out to range" is coming !! please give me solution for this , thanks for support

sir I have all ready do that !! but got above error

When I using above code GridView1.Columns(index).HeaderText = "My Header Text" I am getting
"Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: index" error

Thanks ! but I dont want to use smart tag !! How to write a custom event handler ? Can you give me any example Pls ?

I mean to say code behind !!

Thank you Very much sir ! Now I got my mistake !! I have solved it !! Thanks again !! I could not found my mistake

I have refreshed it but record not deleted

I want to display whole data in database not particular one

Thanks for Solution Avik but I dont understand in above code where I can use this code ?

Thanks a lot sir !! I got the solution by removing "Excel8.0" from coding provided by you !! with excel 8.0 I got table format error !! Thanks again