Even after mentioning I<5 why it is printing values till 5 it should stop at 0 and why I am not able to pass input by user properly

Question

0.00/5 (No votes)

See more:

#include <stdio.h>
    int main(){ 
int marks[4];
int i;
for ( i = 0; i < 5; ++i)// Even after mentioning i<5 why it is printing values till 5 it should stop at 0 and why I am not able to pass input by user properly 
{
   printf("Enter the  value of  %d: \n",i+1);
    scanf("%d\n", &marks[0]);
}

    

return 0;
}

What I have tried:

Even after mentioning i<5 why it is printing values till 5 it should stop at 0 and why I am not able to pass input by user properly

Posted 1-Jun-22 0:41am

Aayush Jain 2022

Updated 1-Jun-22 1:15am

Add a Solution

Comments

0x01AA 1-Jun-22 6:54am

Why? Because you print i+1 and because you read in allways to marks[0] ....

Greg Utas 1-Jun-22 9:56am

You're going to have a problem when you change this. You define marks[4] but then check i < 5. This will lead to using marks[4], which is out of bounds. The index for an array defined with [n] goes from 0 to n-1.

2 solutions

Solution 1

I gave you the correct code in your previous question at I need to enter marks in 5 exams using array , but while passing user to input I am not getting right output .[^].

Posted 1-Jun-22 1:01am

Richard MacCutchan

Comments

merano99 1-Jun-22 17:55pm

Apparently the questioner is not interested in a working solution to his question. I'll give you another 5

Richard MacCutchan 2-Jun-22 3:58am

The sad thing is that far too many of these questions are from people who really have no ability in this field. They just believe it is a shortcut to a well paid job.

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Patrice T · Accepted Answer · 2022-06-01T01:15:00

Even id this code does nothing, I would try to replace

C++

<pre>scanf("%d\n", &marks[0]);

with

C++

<pre>scanf("%d\n", &marks[i]);

Your code do not behave the way you expect, or you don't understand why !

There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your code is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]

1.11 — Debugging your program (stepping and breakpoints) | Learn C++[^]

The debugger is here to only show you what your code is doing and your task is to compare with what it should do.