Getting status of file without using Open function

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Hi All,
This mornning i face new problem while dealing with my file manipulation software.
I'm currently working on file manupulation utility which take 13 CSV (Comma saparators of EXCEL) files as input file and manupulates to create output file.

MY QUASTION:-

HOW I'M GOING TO KNOWN IS FILE IS OPEN OR NOT?

If i used Open function like below,

C++

if(!MyTestFile.Open("ABC.csv",CFile:ModeRead)
{
    MyTestFile.Close();
}

but it work if file failed to open
not if file open success fully

REQUIREMENT:-
Now if i want to close a file.if file not open then close give me assertion but before i used Close() i must check whether file already open or not something like given algorithm

Check file is OPEN //Want fucnction to do so,
IF File is OPEN
Close File
ELSE
Continue

_____________________________________________________________________
ALL RELATED HELPS,LINKS,CODE BLOCK,CODES ARE MOST WELCOME

Posted 30-Aug-11 19:00pm

Coder Block

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this_is_my_alias · Answer 1 · 2011-08-30T19:06:00

Solution 1

try to use a try catch. I haven't tried it here since I unistalled my IDE. But do try it.

Posted 30-Aug-11 19:06pm

this_is_my_alias

Comments

Coder Block 31-Aug-11 1:17am

my application in try catch but it gives me assertion first then catch message

buyong · Answer 2 · 2011-08-30T19:20:00

Solution 2

C#

if(!MyTestFile.Open("ABC.csv",CFile:ModeRead)
{
    //do not close your file when you fail to open it
    //MyTestFile.Close();
}

//if you can get here, you can do something
............
//and then you can close your file
     MyTestFile.Close();

Posted 30-Aug-11 19:20pm

buyong

Comments

Coder Block 31-Aug-11 2:55am

That exactly i doesn't want