Largest of 3 number in c# .net

Question

1.00/5 (1 vote)

See more:

Hi i had an task like have to find the largest of 1st 3 numbers in a group i tried with my code bt getting output as fist largest number alone.. pls help me to solve it...

C#

int[] arr1 = new int[8] { 10, 5, 15, 11, 2, 0, 9, 7 };

            int firstHighestNumber1 = arr1[0];
            int secondHighestNumber1 = arr1[0];
            int thirdHighestNumber = arr1[0];
            for (int i1 = 0; i1 < arr1.Length; i1++)
            {
                if (arr1[i1] > firstHighestNumber1)
                {
                    firstHighestNumber1 = arr1[i1];
                }
            }

            for (int x = 0; x < arr1.Length; x++)
            {
                if (arr1[x] > secondHighestNumber1 && firstHighestNumber1 != arr1[x])
                {
                    if (arr1[x] < secondHighestNumber1)
                    {
                        secondHighestNumber1 = arr1[x];
                    }
                }
            }
            for (int y = 0; y < arr1.Length; y++)
            {
                if (arr1[y] > thirdHighestNumber && secondHighestNumber1 != arr1[y])
                {
                    thirdHighestNumber = arr1[y];
                }
            }

Am expecting the op fr

firstnumber=15
seconfnumber=11
thirdnumber=10

Help me Thank you Have a grt Day :-)

Posted 30-Aug-13 18:22pm

usha C

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sadique KT · Accepted Answer · 2013-08-30T19:49:00

Solution 2

try following code

C#

int[] arr = { 10, 20, 10, 15, 25, 30, 11 };
arr = arr.Distinct().ToArray();
Array.Sort(arr);
Array.Reverse(arr);
int first = arr[0];
int secont = arr[1];
int third = arr[2];

Posted 30-Aug-13 19:49pm

Sadique KT

Updated 30-Aug-13 19:50pm

v2

Comments

usha C 31-Aug-13 1:52am

Thanks fr ur update..

Sadique KT 31-Aug-13 1:53am

welcome ..+5 !!!

Mehdi Gholam · Accepted Answer · 2013-08-30T19:30:00

Solution 1

1) Sort the numbers
2) Take the last 3 from the sorted array.

Posted 30-Aug-13 19:30pm

Mehdi Gholam