C# " } expected" Error Need Help Fixing this error

Question

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I wrote my program and I got this error. " } expected".
after the If

C#

namespace ConsoleApplication7
{
    class Program
    {
        static void Main(string[] args)
        {
            double a;
            double b;
            double c;
            double x1;
            double x2;
            double formula;

            Console.WriteLine("Calculadora para la formula general");
            Console.WriteLine("inserte el valor de A");
            a = double.Parse(Console.ReadLine());
            Console.WriteLine("inserte el valor de B");
            b = double.Parse(Console.ReadLine());
            Console.WriteLine("inserte el valor de C");
            c = double.Parse(Console.ReadLine());
            formula = b * b - 4 - 0 * a * c;

            if (formula < 0) ;
            {
                Console.WriteLine("los resultados son imaginarios");
                formula = -formula;
            }
            
            else 
             Console.WriteLine("los resultados son reales");

            x1 = (-b + Math.Sqrt(formula)) / (2* a);
            x2 = (-b - Math.Sqrt(formula)) / (2 * a);

            Console.WriteLine("x1= " + x1);
            Console.WriteLine("x2= " + x2);
            Console.ReadKey();
            
        }
    }
}

Posted 22-Jan-16 18:23pm

Member 12282050

Updated 22-Jan-16 18:56pm

Garth J Lancaster

v2

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Comments

Sarath kumar.N 23-Jan-16 0:58am

remove

BillWoodruff 23-Jan-16 1:34am

What's happening that when you click on the no-compile error in Visual Studio you are not shown the line number where the error occurs and "taken there" ?

Visual Studio is your friend.

3 solutions

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Garth J Lancaster · Answer 1 · 2016-01-22T18:55:00

Solution 2

think about this

C#

if (formula < 0) ;

what is that semi-colon doing there ?

Posted 22-Jan-16 18:55pm

Garth J Lancaster

Sarath kumar.N · Answer 2 · 2016-01-22T19:15:00

Solution 3

Remove semicolon from

C#

if(formula>0);

line

Posted 22-Jan-16 19:15pm

Sarath kumar.N

v2

Abhinav S · Answer 3 · 2016-01-22T18:53:00

C#

if (formula < 0) ;
{
    Console.WriteLine("los resultados son imaginarios");
    formula = -formula;
}

else
 Console.WriteLine("los resultados son reales");

The else condition needs a bracket.

C#

if (formula < 0) ;
{
    Console.WriteLine("los resultados son imaginarios");
    formula = -formula;
}

else {
 Console.WriteLine("los resultados son reales");
}