XML how to get child nodes?

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XML

<groups>
 <group name="Accounts">
    <subgroup name="Tally persons>
       <list name="AB"\>
       <list name="CD"\>
    <subgroup\>
 </group>
 <group name="Marketing">
       <list name="EF"\>
       <list name="GH"\>
 </group>
 <group name="Manager"></group>
</groups>

Here is the XML file.
Some group are have sub groups others don't.
I need the name value for the list node inside subgroup.
that AB,CD,EF,GH only.
How to get it?
Thanks
Saranya1388

Posted 2-Dec-10 22:39pm

SwaxRak

Updated 2-Dec-10 22:46pm

Ankur^\m/

v2

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Manfred Rudolf Bihy 3-Dec-10 4:59am

Well, all I can see is that EF and GH are list nodes that are NOT inside a subgroup tag.
The XML example is either wrong or the descriptive text is. Take your pick!

Tarun.K.S 3-Dec-10 8:13am

but still the names can be retrieved. give the Xpath expression as //list. It will return all the list nodes!

Manfred Rudolf Bihy 3-Dec-10 9:34am

@Tarun:What you're saying is correct, but please read my comment carefully and then check with OP's post. He's obviously having a problem with either his XML or in his description:

<quote>I need the name value for the list node inside subgroup

and then mentions nodes EF and GH also, eventhough they're not inside a subgroup tag.

Tarun.K.S 4-Dec-10 6:32am

hmmm you are right.

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Manfred Rudolf Bihy · Answer 1 · 2010-12-02T22:57:00

Solution 1

1. Load xml into XmlDocument
2. Use XPath expressions to extract data from document.

Done!

This here is an excellent resource: http://www.w3schools.com/xpath/

Cheers,

Manfred

Posted 2-Dec-10 22:57pm

Manfred Rudolf Bihy

Updated 2-Dec-10 23:00pm

v2

Comments

Dalek Dave 3-Dec-10 5:00am

Good Call.

#realJSOP · Answer 2 · 2010-12-03T00:09:00

Solution 2

If you're using .Net 3.0 or higher, you can use Linq-To-Xml.

Posted 3-Dec-10 0:09am

#realJSOP