How to initialize ServiceHost for windowservice ?

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Please clarify me.

I am inintializing ServiceHost for windowservice as following and confused about httpUrl.

ServiceHost Host = new ServiceHost(typeof(WCFWindowsHositngService.SimpleCalculator), httpUrl);

How can i write httpUrl

1. Uri httpUrl = new Uri("http://localhost:8090/MyService/SimpleCalculator");
or
2. Uri httpUrl = new Uri("C:/MyService/SimpleCalculator");
Or
3. Uri httpUrl = new Uri("computerno//C:/MyService/SimpleCalculator");

Posted 6-Apr-11 22:33pm

BulbulAhmed

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Ramu Sangabathula Original 7-Apr-11 20:38pm

you mean did you host your wcf service as a windows service, and accessing the hosted service from client, and don't know how to frame the url?

[no name] 11-Apr-11 0:44am

Yes. Please let me know about url

2 solutions

Solution 1

It depends on the binding that you are using for your WCF service. If you use basicHttpBinding and your service listens on port 8090, option 1 is the URL that you should use.

Posted 7-Apr-11 21:53pm

Patrick Kalkman

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Ramu Sangabathula Original · Accepted Answer · 2011-04-11T13:23:00

Solution 2

if you are using netTCPBinding, url format will be like

net.tcp://servername:portnumber/ServiceName

for Http Protocol (basichttp,wshttp)

http://servername:portnumber/Servicename

for netnamedpipebinding.

net.pipe://localhost/Servicename

Posted 11-Apr-11 13:23pm

Ramu Sangabathula Original

Comments

[no name] 12-Apr-11 1:14am

Thank you very mutch