Question about c code

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#include <stdio.h>
#include <conio.h>
void main()
{

int x=2,y=3;
x=y++ + x++;
y=++y + ++x;
printf("%d%d",x,y);
getch();

THE OUTPUT OF CODE IS 7 AND 12

i not understand how this output comes plz help me

Posted 19-Oct-11 20:31pm

2 solutions

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Mehdi Gholam · Answer 1 · 2011-10-19T20:37:00

1) x=2, y=3
2) x = 3 + 2 -> x++ , y++ -> x=6 y=4
3) y = (y+1) + (x+1) -> x= 7 , y = 12

Posted 19-Oct-11 20:37pm

sravani.v · Answer 2 · 2011-10-19T20:38:00

x=y++ + x++;

With this line u got x=(3)+(2)=5
now post increment will done
so x++ gives (5+1)=6
y++ gives (3+1)=4

y=++y + ++x;

From this line you got y=12 i.e
pre increment will be done before execution of expression.
so now x=7,y=5
y=(5)+(7)=12

Posted 19-Oct-11 20:38pm

Updated 19-Oct-11 20:45pm

v2