what does equal this code in win32 project

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Hy what does equal this code in win32 project :

C#

if(radioButton1.Checked == True)
   MessageBox.Show("Hello");

Posted 15-Sep-12 20:29pm

khosro goudarzi

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CPallini · Answer 1 · 2012-09-16T01:06:00

Solution 2

C++

if ( Button_GetCheck(hwndRadioButton1) == BST_CHECKED)
{
  MessageBox(NULL, _T("Hello"), _T("Info"), MB_OK);
}

See Button_GetCheck macro[^], MessageBox function[^] at MSDN.

Posted 16-Sep-12 1:06am

CPallini

Comments

Mohibur Rashid 16-Sep-12 10:12am

+5

CPallini 16-Sep-12 10:32am

Thank you.

skydger · Answer 2 · 2012-09-16T00:53:00

Solution 1

For MFC:

C++

CButton * btn = (CButton *)GetDlgItem(IDC_MY_RADIO);
if( btn != NULL )
    if( btn->GetCheck() == BST_CHECKED )
        AfxMessageBox( "Hello" );

Posted 16-Sep-12 0:53am

skydger

Comments

Chuck O'Toole 16-Sep-12 22:24pm

I don't have VS installed on this PC at the moment so I can't check but I'm pretty sure that GetDlgItem() returns a CWnd * not a CButton *. Since CButton is derived from CWnd, you are "Upcasting" an object and you can't be sure that "GetCheck()" will work. If it does work, it's by accident and not design.

skydger 17-Sep-12 4:23am

I agree that this is not a good design of application, the DDX_Control and other things are better but also takes a time for additional code. If there is a need to use temporary variable whithout member object, GetDlgItem(...) is the way to do so.

Chuck O'Toole 17-Sep-12 13:20pm

My issue is *not* with GetDlgItem(), I use it all the time. My issue is that you cast the return (CWnd *) to a CButton * which is NOT the correct thing to do. CButton is *derived* from CWnd, not the other way round. You are improperly UPCASTING to a higher object and none of the Vtable or member variables that are unique to CButton will be there. The only right way to do this is to subclass the control into a variable using DDX. Showing this incorrect technique to an obvious newbie isn't helping him at all.