gps week day of week and gps time

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I need help. Actually I do not know how to calculate a GPS time and GPS week, GPS day of the week.

I would like the current date calculated GPS date, GPS week and GPS time in seconds.

thanks for the help, if there is some sample code to help me out a lot.

Posted 30-Sep-12 22:20pm

lazicsasa

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Richard MacCutchan · Answer 1 · 2012-10-01T00:16:00

Solution 1

See here[^].

Posted 1-Oct-12 0:16am

Richard MacCutchan

Code-Hunt · Answer 2 · 2012-10-01T00:58:00

Solution 2

http://stackoverflow.com/questions/6608080/convert-from-gps-week-number-time-of-week-to-datetime[^]

check the link..u will get the code idea...

Posted 1-Oct-12 0:58am

Code-Hunt

lazicsasa · Answer 3 · 2012-10-02T02:57:00

C#

// racunam gps nedelju
           // prvo racunam julijanski dan
           // koriscen algoritam "Practical Ephemeris Calculations" - oliver Montenbruck
           // Springer - Verlag, 1989)
           double yr = Convert.ToDouble(godina);
           double mn = Convert.ToDouble(mesec);
           double dy = Convert.ToDouble(datumUmesecu);
           double y = 0;
           double m = 0;
           double b = 0;
           double jd = 0;

           if (mn > 2)
           {
                y = yr;
                m = mn;
           }
           else
           {
                y = yr - 1;
                m = mn + 12;
           }

           double date0 = dy + 31 * (mn + 12 * yr);
           double date1 = 4 + 31 * (10 + 12 * 1582);
           double date2 = 15 + 31 * (10 + 12 * 1582);

           if (date0 < date1)
           {
                b = -2;
           }
           else
           {
                b = y / 400 - y / 100;
           }

           if ( y > 0)
           {
                jd = 365.25 * y + 30.6001 * (m + 1) + b + 1720996.5 + dy;// julijanski datum
           }
           else
           {
                jd = 365.25 * y - 0.75 + 30.6001 * (m + 1) + b + 1720996.5 + dy;// julijanski datum
           }

           double mjd = jd - 2400000.5;// modifikovvani julijanski datum

           // GPS nedelja racunam
           double jd1 = 0;
           yr = 1980;
           mn = 1;
           dy = 6;
           if (mn > 2)
           {
               y = yr;
               m = mn;
           }
           else
           {
               y = yr - 1;
               m = mn + 12;
           }
            date0 = dy + 31 * (mn + 12 * yr);
            date1 = 4 + 31 * (10 + 12 * 1582);
            date2 = 15 + 31 * (10 + 12 * 1582);

           if (date0 < date1)
           {
               b = -2;
           }
           else
           {
               b = y / 400 - y / 100;
           }

           if (y > 0)
           {
               jd1 = 365.25 * y + 30.6001 * (m + 1) + b + 1720996.5 + dy;// julijanski datum
           }
           else
           {
               jd1 = 365.25 * y - 0.75 + 30.6001 * (m + 1) + b + 1720996.5 + dy;// julijanski datum
           }
           double jdgps = jd1 - 2400000.5;// modifikovani julijanski datum
           double gpsWeek = (jd - jd1) / 7;// gps nedelja
           double sow = (jd - (jd1 + Convert.ToInt32(gpsWeek) * 7)) * 3600 * 24;// sekunda u nedelji
           // kraj racunanja gps nedelje