find number of inversions in array

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C#

find number of inversions in array
Where array are randomly 1 to 100000 ????

Posted 31-Jan-13 20:17pm

Sant Osha

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Sergey Alexandrovich Kryukov 1-Feb-13 2:32am

What is "randomly"? length? values? Who cares if it is random or not, the problem is the same.
Anyway, what did you try?
By the way, programming is not needed here, only some mathematics...
—SA

Sant Osha 1-Feb-13 2:59am

I'm new to it..... please, tell me your solution..

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CPallini · Answer 1 · 2013-01-31T21:15:00

Solution 1

I suspect Google won't be of any help in your case: "About 3,240,000 results"[^].

Posted 31-Jan-13 21:15pm

CPallini

Tanumay99 · Answer 2 · 2013-02-01T19:38:00

hi
if you want to make a number inverse then follow the follow the following code:

console.writeLine("Enter the position of the number for reverse :");
int no,rem,rev=0;
no= Console.ReadLine();
while(no!=0)
{
  rem=no%10;
  rev=rev*10+rem;
  no=no/10;
  
}

if you want to inversion of the array then use the following:

int count,no,j,i;
<data type=""> array[],temp[];
for(i=0;i<array.lenght;i++);>
for(j=0;i>=0,j<array.lenght;i--,j++)>
{
  temp[j]=array[i];
}
console.writeLine("your reverse array is:");
for(i=0;i<array.lenght;i++)>
{
 console.writeLine(temp[i]);
}
</data>