how find duplicate values from table according to name field ..

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dear

i have a table which contain duplicate values and i want to view all duplicate values according to
table column 'name' and i want to delete duplicate values from table..

table like...

eid     name
1	a
2	b
3	a
4	c
5	d
6	a
7	d
8	a
9	d
10	e
11	a
12	a
13	a
14	e

pls help me to resolve above problem..

[Update by OP:]
i have use this script but it shows error..

SQL

select name,COUNT(*) from t1 having COUNT(*)>=1 group by name

Posted 17-Feb-13 5:59am

Mukesh Bhagat

Updated 17-Feb-13 6:08am

Zoltán Zörgő

v2

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Zoltán Zörgő 17-Feb-13 12:02pm

And given this input table, what exactly have you imagined as output?
Are you interested only in the DISTINCT names, or is there any rule which of the eid values should go in the result.

Sergey Alexandrovich Kryukov 17-Feb-13 13:58pm

Please stop posting non-answers as "solution". It can give you abuse reports which eventually may lead to cancellation of your CodeProject membership.
Comment on any posts, reply to available comments, or use "Improve question" (above).
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3 solutions

Solution 2

The following statement is not correct.

SQL

select name,COUNT(*) from t1 having COUNT(*)>=1 group by name

This one is, since having is a condition that applies to the interim result after aggregation:

SQL

select name, COUNT(*) from t1 group by name having COUNT(*)>=1

But as COUNT(*) won't give 0 in this case, HAVING is no use:

SQL

select name, COUNT(*) from t1 group by name

But if you don't need the count, simply use:

SQL

select distinct name from t1

Posted 17-Feb-13 6:07am

Zoltán Zörgő

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gvprabu · Accepted Answer · 2013-02-17T22:27:00

Hi Mukesh,

Check the sample Script,

SQL

-- Table Creation
IF OBJECT_ID('TempDB..#Test') IS NOT NULL DROP TABLE #Test
CREATE TABLE #Test(eid  INT IDENTITY(1,1), name VARCHAR(10
0))
INSERT INTO #Test(name)
VALUES('a'),('b'),('b'), ('a'), ('c'), ('d'), ('a'), ('d'), ('a'), ('d'), ('e'), ('a'), ('a'), ('a'), ('e')
-- Actual Data
SELECT Name FROM #Test

-- Delete Duplicate Records
DELETE
FROM #Test
WHERE ID NOT IN
(
SELECT MAX(ID)
FROM #Test
GROUP BY Name)

-- Required Output
SELECT Name FROM #Test

Regards,
Venkatesh.

Arun1_m1 · Accepted Answer · 2013-02-18T03:26:00

For Deleteing the duplicate records from the table you can also use

SQL

CREATE TABLE #Test(eid  INT IDENTITY(1,1), name VARCHAR(100))
INSERT INTO #Test(name)
VALUES('a'),('b'),('b'), ('a'), ('c'), ('d'), ('a'), ('d'), ('a'), ('d'), ('e'), ('a'), ('a'), ('a'), ('e')

with cte
as
(
SELECT eid,name,ROW_NUMBER() OVER(partition by name order by eid) as rowids FROM #Test
)
delete #Test
from #Test
join cte on #test.eid = cte.eid
where cte.rowids > 1

select * From #test

how find duplicate values from table according to name field ..

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