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I did try everything. I think this simple program does not any require such
building process anyway.
Ganesh
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Ok, I see your problem.... To explain, the compiler finds the
void projectFrom(Point3D p3d) { i = p3d.i; j = p3d.j; }line difficult because the Point3D occupies a certain amount of memory (it doesn't yet know how many variable it has), and perhaps has a copy constructor (which the compiler might not yet know about). I'm not 100% sure here, but I think you have to change the Point3D p3d argument to Point3D &p3d - I think the compiler should cheer up then.
Joel Holdsworth
Wanna give me a job this summer?
Check out my online CV and project history[^]
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Joel Holdsworth wrote:
I'm not 100% sure here, but I think you have to change the Point3D p3d argument to Point3D &p3d - I think the compiler should cheer up then.
Not really. He must not inline the function because he uses i = p3d there:
void projectFrom(Point3D p3d);
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CP Visitor wrote:
Not really. He must not inline the function because he uses i = p3d there:
void projectFrom(Point3D p3d); // don't do this: { i = p3d.i; j = p3d.j; }
Purpose of inlining is optimization. Please see Bjarne Stroustrup
(C++ Prog. Lang., 3rd Ed, 1997, pages 675-676) on Ternary operation.
Ganesh
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Ganesh_Srim wrote:
CP Visitor wrote:
Not really. He must not inline the function because he uses i = p3d there:
void projectFrom(Point3D p3d); // don't do this: { i = p3d.i; j = p3d.j; }
Purpose of inlining is optimization. Please see Bjarne Stroustrup
(C++ Prog. Lang., 3rd Ed, 1997, pages 675-676) on Ternary operation.
Forward declaration or oprimization. Chose one! 
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Bob Helter wrote:
Forward declaration or oprimization. Chose one!
CP Visitor is right.
Inlining can be done at the point of defining the function below the
definition of Point3D class. So nothing is lost.
Thanks
Ganesh
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If you are not dead-set on using a pass-by-value or pass-by-reference then pass-by-pointer instead and your problem will be gone!
void projectFrom(Point3D p3d) { i = p3d.i; j = p3d.j; } // compilation error
void projectFrom(Point3D* p3d) { i = p3d->i; j = p3d->j; } // no compilation error
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I tried everything honestly. Nothing works!
I hope its not a hardware instruction set problem!
Ganesh
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I tried all your suggestions. But nothing worked.
The next thing I should suspect is some hardware instruction set bug!!
When I worked in Linux long time ago, I did not seem to encounter this problem!
Is there any way I can contact Micorsoft's personnel without having to purchase a subsciption.
I can't imagine programming without these constructs. But it is possible with virtual base classes containg the same data structure. Thus one ends up always using derived types when such a class is needed in a "cicular" way.
Ganesh
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I made this little test program and it compiled and worked :
#include "stdafx.h"
class Point3D;
class Point2D
{
public:
int i, j;
Point2D() { Set( 0, 0 ); }
Point2D(int a, int b) { Set( a, b ); }
void Set( int a, int b ) { i = a; j = b; }
__inline void projectFrom(Point3D *p3d);
};
class Point3D
{
public:
int i, j, k;
Point3D() { Set( 0, 0, 0 ); }
Point3D(int a, int b, int c) { Set( a, b, c ); }
Point3D& operator=(const Point2D& p2d) { Set( p2d.i, p2d.j, 0 ); }
void Set(int a, int b, int c) { i = a; j = b; k = c; }
};
void Point2D::projectFrom(Point3D *p3d)
{
i = p3d->i;
j = p3d->j;
}
int main()
{
Point2D p2d(1,2);
Point3D p3d(2,3,4);
p2d.projectFrom( &p3d );
fprintf( stdout, "p2d = (%d, %d)\n", p2d.i, p2d.j );
return 0;
}
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Rick York wrote:
void Point2D::projectFrom(Point3D *p3d)
... written below the class definition  ;)
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Hello CP Visitor.
You are right from the beginning. I misread the compiler remarks
as I put all function code in one line. Had I put those assigments on a
separate line, I would have at least undetstood that there is no
problem with forward referencing, but something else. I would have saved you all some time.
Thanks.
Ganesh
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Hello 'Rick York'
Thanks for your time. Just before checking for messages,
I got it right finally. You are absolutely right. Since I put all
the code in one line, I could not decipher compiler message clearly.
Had I put the assignment code
<br />
{i = p3d.i; j = p3d.j; }
on a different line, I would have saved myself and all of you so much time.
My apologies.
Ganesh
Ganesh
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Hello All,
I finally I uderstood the issue. Thanks everybody.
Ganesh
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i used FindFirstChangeNotification()FindFirstChangeNotification()AND WaitForSingleObject() to notify any change in a mentioned directory.its working.But i want to mention the cause of notification (say its due to deletion of a file).i declared every filter condition in FindFirstChangeNotification()
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this the code....
DWORD change= WaitForSingleObject(hr,INFINITE);
if(change==WAIT_OBJECT_0)
::AfxMessageBox("CHANGE HAS BEEN DETECTED");
FindCloseChangeNotification(hr);
in the ::AfxMessageBox() I WANT TO MENTION THE REASON FOR NOTIFICATION ie DUE TO FILE DELETION OR FILE RENAME ETC
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How to convert a LONGLONG data type to binary ?
Thanks for any help.
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I guess you mean convert to a binary string... right? If you can't find a runtime library function to do it, try something like this:
LONGLONG value = 12345;
TCHAR mystring[sizeof(LONGLONG)*8 + 1];
for(int i = 0; i < sizeof(LONGLONG)*8; i++)
mystring[i] = ((value >> (sizeof(LONGLONG)*8 - i - 1)) & 1) ? _T('1') : _T('0');
mystring[sizeof(LONGLONG)*8] = 0;Hope that helps.
Joel Holdsworth
Wanna give me a job this summer?
Check out my online CV and project history[^]
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Thank you.
I tried to put the answer to the code you gave me in a message box like that:
void CMyBitsDlg::ConvertLLtoBin()
{ LONGLONG value = 12345;
TCHAR mystring[sizeof(LONGLONG)];
for(int i = 0; i < sizeof(LONGLONG); i++)
mystring[i] = ((value >> (sizeof(LONGLONG) - i - 1)) & 1) ? _T('1') : _T('0');
AfxMessageBox(mystring);
}
The answer is 00111001P@
Any idea about the error?
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you forgot to end your string with
mystring[i] = '\0'; that doesn't happend with my CString (see here[^])
of course, int i; should be declared before for() loop...
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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Yes the thought just popped into my mind, and I just returned now to correct my mistake.
Joel Holdsworth
Wanna give me a job this summer?
Check out my online CV and project history[^]
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datas are written in binary format in memory...
however, if you like to print an integer in binary format, this link[^] should help.
here is the sample :
<font color=#0000FF>LONGLONG</font> iVal = 125932; <font color=#008000>
CString strVal = <font color=#808080>""</font>; <font color=#008000>
<font color=#0000FF>for</font> (<font color=#0000FF>int</font> i = 0; i < <font color=#0000FF>sizeof</font>(LONGLONG); i++) {
strVal.Insert(0, ((iVal & 0x00000001) ? <font color=#808080>"1"</font> : <font color=#808080>"0"</font>));
iVal >>= 1;
}
cheers,
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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