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Hi Bimbaa,
Bimbaa wrote: ...can help me to resolve my problem and can advice what i to do that is better.
Perhaps the Usenet group sci.crypt[^] will prove to be a better resource for you.
Jeff
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http://csrc.nist.gov/nissc/1997/proceedings/128.pdf
Need a C# Consultant? I'm available.
Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
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Oh thanks dear. This paper is important for me and published ready before ten years ago. Is the criteria of measurement for the cryptography in this paper still same with nowadays criteria?
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I would imagine so. If not it is still a good baseline.
Need a C# Consultant? I'm available.
Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
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If you are lucky (I was once), you could pose your question to Prof. Rivest. You'll stand a much better chance of receiving help if you ask specific questions that can be easily answered without the reader having to invest much time.
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Hey David Crow. This is also important for me. Thank you for your giving contacts.
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It's not like I gave you secret information. His Web page, as well as his e-mail address, are public.
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Yes. dear your right. I have seen the contact and sent him a mail ready. Thank you again.David
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Hi,everyone,
This is my first time to post here. This website is amazing and I get a lot of help.
I have a question. You may hear about variable elimination in the subject of Artificial Intelligence. But how can I realize this algorithm, using what data stucture to store the datas. What is the format of output data? If anyone has good idea or even the source code (C++ prefered), please tell me ASAP. Thanks very much.
Best wishes.
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Google might help.
"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon
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Dear All, I have read bimbaa issues and i'm currently doing same oh him/her encryption/Decryption algorith at Qatar University and i wrote the algorithm for that but i want to measure the strength of my algorithm and i dont know how,exactly i dont know what the critria that i should use it to measure it. Moreover, my output consist of 1 byte as well my input.if u say not enough because the standard one should be at least 16 bytes then i will say that any hacker not know what is the original data that i encrypted as well i feel the speed of my application ( the application of the algorithm)if high speed then the attacker cannot hack my security data. Please, advice me.
researcher need advice
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"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon
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hai all,
i need some algorithm to find the day code(1 to 366) based on the date.
for example, the code for feb 2nd 2007 will be
31+2=33.
for march 2nd 2007 will be 31+28+2=61
and for march 2nd 2008 will be 31+29+2=62 since 2008 is a leap year.
iam sure that, this is not a very big task. but, how simple our logic is, matters.
any ideas please?
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chandu004 wrote: hai all,
i need some algorithm to find the day code(1 to 366) based on the date.
for example, the code for feb 2nd 2007 will be
31+2=33.
for march 2nd 2007 will be 31+28+2=61
and for march 2nd 2008 will be 31+29+2=62 since 2008 is a leap year.
iam sure that, this is not a very big task. but, how simple our logic is, matters.
any ideas please?
There probably is a way, in the language that you use, to subtract two dates and return the result in days. Just subtract 31 Dec of the previous year from the date that you want...
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oh cool,
nice technique.
how ever, i strained my brain for half an hour and wrote a three lined logic to achieve this.
thank you.
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century years rules (of course if you need to deal with):
(1) Century years aren't leap years (though they're divisible by 4).
(2) Century years divisible by 400 (as 2000, for instance) are leap years.
Maybe you have to further strain your brain.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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yes pallini,
i certainly had to deal with it and iam aware of it.
thank you.
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the main important thing how to prove the correctness of ur function
researche in mobile databases
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just supply some valid values to it and see.
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I also recomend testing invalid values and testing for proper failures as well.
Quite often we just test for success and don't test for failure. Failing in a predictable manner of often times more important than being correct. Correct is always predictable. Failing often times is not.
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this validation logic is implemented before the algorithm in my application.
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chandu004 wrote: just supply some valid values to it and see.
Don't let Prof. Knuth know your secret. 
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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The Gregorian calender doesn't have any leapyear exception rules for above 400. IF they did, IIRC the next toggle points would have been 2000 and 10,000. Instead we're adding single leap seconds as needed at new years to keep everything in sync.
--
If you view money as inherently evil, I view it as my duty to assist in making you more virtuous.
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dan neely wrote: IIRC the next toggle points would have been 2000 and 10,000
I doubt that; Wikipedia[^] gives some arguments for a leapyear correction every 4000
or 8000 years.
dan neely wrote: Instead we're adding single leap seconds as needed at new years to keep everything in sync
That can not be correct: with a one second correction every year
you would need 60 * 60 * 24 = 86400 years to shift time by one day, not quite sufficient.
[added] Again Wikipedia[^] explains
the purpose of leap seconds.[/added]
-- modified at 18:06 Thursday 1st November, 2007
Luc Pattyn [Forum Guidelines] [My Articles]
this months tips:
- use PRE tags to preserve formatting when showing multi-line code snippets
- before you ask a question here, search CodeProject, then Google
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Hai friends,
Here is my logic to find the day code.
if any body can please suggest a better logic, or if any body can validate the logic and find any bugs there, i would apprieciate it.
int offset[12]={0,31,59,90,120,151,181,212,243,273,304,334},l=0;<br />
if((((curyear%4==0) && (curyear%100!=0)) || (curyear%400==0)) && (curmonth>1))<br />
l=1;<br />
daycode=offset[curmonth]+curdate+l;
opinions please.
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