C / C++ / MFC

CPallini wrote:

You should work on this, I suppose. Which line is giving you this message?

int APIENTRY WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd)
{
    hInst = hInstance;
	return DialogBox(hInstance, MAKEINTRESOURCE(DLG_MAIN), NULL, DialogProc);
}

return static_cast<int>(DialogProc());

INT_PTR nRet = DialogProc();
return nRet != ID_OK ? 1 : 0;

Smart Arab wrote:

DialogProc function Return INT_PTR while the WinMain which return the DialogProc "must return int."

Smart Arab wrote:

I think I must find a way to convert from IntPtr to int safely ..

// in WinMain
return DialogBox(hInstance, MAKEINTRESOURCE(DLG_MAIN), NULL, (DLGPROC)DialogProc);

1. Assign the DialogBox return value to an (INT_PTR) variable (say result).
2. Based on result value, return an appropriate (int) number from the WinMain function.

pix_programmer wrote:

I've to select a number radomly from 1 t0 6. What is the C++ code for this?

int number;

// initialize random seed (best call it very early in the programm)
srand ( time(NULL) );

// generate number
number = rand() % 6 + 1;

int n = 1 + 6.0 * rand() / (RAND_MAX + 1.0);

CPallini wrote:

Notice though that this modulo operation does not generate a truly uniformly distributed random number in the span (since in most cases lower numbers are slightly more likely), but it is generally a good approximation for short spans.

CPallini wrote:

How did you perform the test?

<pre>int randomizedValueInRange = (rand()%(maxRange-minRange+1))+minRange;

#include <cstdlib>
#include <ctime>
#include <iostream>
using namespace std ;



int main(void)
{   //seed
    srand(static_cast<unsigned>(time(0)));


    cout<<" \nDICE GAME\n";

    //Generate a random number between 1 and 6
    int random_number = (rand() % 6) + 1;

    cout<<" \nYou threw a ["<<random_number <<"]\n\n";


   return 0;
}