Database

 hi friends actually i am working on a mlm project in which members are added in a tree pattern, and get the payment accordingly.

My table  structure is as follow:

        Id         ParentId        IsLeft           IsRight
         1          Null             Null             Null
         2           1                1               Null
         3           1               Null               1
         4           2                1               Null
         5           2               Null               1
         6           3                1               Null
         7           3               Null               1
         8           4                1               Null
         9           4               Null               1
         10          5                1               Null

the problem is that initially 1500$ are given to parent when two nodes are added to its left and one to his right(2:1) . and then 500$ for each pair.

My problem is to find the query which can return the total income of any given node.

enter image description here

According to figure node 1 must get 2500$ (1500+500+500) first 500$ is for node 4 and second 500$ is for node 3.

According to figure node 2 must get 1500$ because it has two nodes to its left and one node to its right this means a ratio of (2:1). and has no pairs

According to figure node 3 must get 0$ because it does not have any nodes in ratio(2:1)

one thing has to be kept in mind that 1500$ will be the first payment and then only the other pairs will be counted, and 1500$ will be given when node has ratio 2:1(two nodes on left and one on right) but no money when ratio is 1:2(one node on left and two on right)

I have found the query which will count all the pairs below a particular node and give receiving amount according to 500$, but the query has not been able to consider the first condition that is the 2:1 condition

        declare @ParentId as int
         set @ParentId=1

       create table #temp_table_name
        (
          ParentId varchar(30) null,
         )


      ;with Child as
       (
    select id,ParentId from tblTestingTree where id=@ParentId
    union all
    Select tblTestingTree.Id,tblTestingTree.parentId from tblTestingTree 
    inner join Child 
    on tblTestingTree.ParentId=Child.Id
       )

  insert into #temp_table_name
  select c.ParentId  from tblTestingTree T join Child c
  on c.Id=t.Id
  WHERE ISNULL(T.ParentId, 0) <> 0 and c.ParentId!=@ParentId
  group by c.ParentId
  having COUNT(c.ParentId)>1 

  select COUNT(*)*500 as totalmoney from #temp_table_name

  drop table #temp_table_name