C / C++ / MFC

11-Jul-03 21:17

i have a rowset to be update,insert,delete, and i want to known all modify infomation about the rowset,Is ole db or odbc support this?
or any idea else?
thank you!

i am realfly8)

realfly14-Jul-03 3:07

Is an STL vector an array?

14-Jul-03 3:07

up

i am realfly8)

DaveE9th11-Jul-03 20:53

DaveE9th

11-Jul-03 20:53

I'm learning about vector STL containers, is this also considered an array?

Andrew Walker11-Jul-03 21:37

Andrew Walker

11-Jul-03 21:37

No. But it can do many of the same types of things that an array can, and a bit more. Vectors are dynamic arrays, in that they can grow as you add elements to them. They are similar to arrays in that they provide the subscript operator[] (you can use standard array notation).

Use a vector if your code might throw exceptions.
Use a vector if most of your inserts will be at the back, and few near the front (otherwise consider deque or list).
Use a vector to support better initialisation.

Always prefer standard containers, list, vector, deque to arrays. less code, cleaner code, better support for copying - and in the end easier to work with.

[edit]Most vectors are internally implemented as arrays, but that shouldn't matter to the end user.[/edit]

If you can keep you head when all about you
Are losing theirs and blaming it on you;
If you can dream - and not make dreams your master;
If you can think - and not make thoughts you aim;
Yours is the Earth and everything that's in it.

Rudyard Kipling

peterchen11-Jul-03 21:59

peterchen

11-Jul-03 21:59

Andrew Walker wrote:
[edit]Most vectors are internally implemented as arrays, but that shouldn't matter to the end user.[/edit]

IIRC a vector must be implemented as an array, because &(vector[0]) is a legal expression to get a C pointer to the array. (ref. herb sutters Effective STL)

(Strings, OTOH, need not)

"Der Geist des Kriegers ist erwacht / Ich hab die Macht" StS

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Ryan Binns11-Jul-03 22:53

Ryan Binns

11-Jul-03 22:53

peterchen wrote:
IIRC a vector must be implemented as an array, because &(vector[0]) is a legal expression to get a C pointer to the array.

Yeah, I believe that is correct

Ryan

"Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

Tim Smith12-Jul-03 6:22

Tim Smith

12-Jul-03 6:22

That was left out of the original standard but has been (or will be) added. William would know for sure.

Tim Smith

I'm going to patent thought. I have yet to see any prior art.

realfly11-Jul-03 21:38

11-Jul-03 21:38

yes, it want to be a safe one

i am realfly8)

i am very confused please help me! i am chinese ,my english is very poor, i had troubled with a question in MFC

DaveE9th12-Jul-03 2:12

DaveE9th

12-Jul-03 2:12

Good explanation Andrew,

Thanks everybody.

Smile | :)

hongge11-Jul-03 20:13

hongge

11-Jul-03 20:13

please link to :http://www.my1489.ni8.net
please tell me what controls is this ,where could download it?i am very confused!help me

chinese girl

something like that8)

realfly11-Jul-03 21:35

Re: something like that8)

11-Jul-03 21:35

http://www.codeproject.com/miscctrl/TimeTestMfc.asp?target=mourad

i am realfly8)

hongge11-Jul-03 23:15

hongge

11-Jul-03 23:15

thank you 1谢谢!where are you ?你在那个国家？ Smile | :)

Re: something like that8)

realfly13-Jul-03 15:40

13-Jul-03 15:40

中国^-^

i am realfly8)

Need some help(Beginner)

Fightingbee11-Jul-03 19:43

Fightingbee

11-Jul-03 19:43

Ok here is the goal of the program:
Create a C++ Program that acts as a calculator for the user. The program should start off by printing, to the screen, a menu that offers the user one of five options. The menu should look somethings like this, but feel free to dress it up any way you want to make it look nice.
1.Add
2.Subtract
3.Multiply
4.Divide
5.Exit

The user wil then select one of the options. Then the program must prompt the user forthe input data and print the results to the screen. After the user has found the desired results, the menu should then reappear to allow the user to do another calculation. Do not let the user out of the program until the user has typed 5 for exit.

Rules: The program must use at least 5 functions, not including MAIN.One funtion will be for the menu and one function for each of the calculations.

Input for the program will be data that is in the integer range, and you can make the assumption that I will NOT type 0 to force a divide by 0 error ( Nice instructor eh?? . However, if the user types in a menu item number that does not appear, then the program should return the user an error message that they have typed an incorrect number and allow the user to retype a valid number.

Ok with all that said below is the source code that I have written in MS Visual C++. I am thinking I am running into problems with my functions, although I am not to sure. And thanks in advance for anyone who takes the time to offer some help.

#include <iostream>
#include <conio.h>

using namespace std;


int sum = 0;
int ssum = 0;
int msum = 0;
double dsum = 0;
int x = 0;
int y = 0;
int menu();
int c = menu();

int main()
{	
	do
	{
		int menu();

		if(c == 1)
		   int add();
		else if(c == 2)	
	       	   int sub();
		else if(c == 3)
		   int multi();
		else if(c == 4)
		   double div();
	}

	getch();
	return 0;
}
		 
int menu()
{	
	int sel = 0;

    cout<<"Please select a menu choice..."<<endl
    <<"1. Add"<<endl
    <<"2. Subtract"<<endl
    <<"3. Multiply"<<endl
    <<"4. Divide"<<endl
    <<"5. Exit program"<<endl;
		cin>>sel;
		
	if(c = 5)
	    cout<<"Thank you for using the calculator!"<<endl;
	else if(c > 5 && c < 1)
	    cout<<"You have entered an invalid selection!"<<endl;

	return sel;
}

int add()
{
        cout<<"Please enter a number..."<<endl;
		cin>> x;
	cout<<"Please enter your second number..."<<endl;
		cin>>y;

	sum = x + y;
	cout<<"The answer is "<<sum<<endl;

	    return sum;
}

int sub()
{
        cout<<"Please enter a number..."<<endl;
		cin>> x;
	cout<<"Please enter your second number..."<<endl;
		cin>>y;
	
	ssum = x - y;
	cout<<"The answer is "<<ssum<<endl;

	    return ssum;
}

int multi()
{
	cout<<"Please enter a number..."<<endl;
		cin>> x;
	cout<<"Please enter your second number..."<<endl;
		cin>>y;
	
	msum = x * y;
	cout<<"The answer is "<<msum<<endl;

		return msum;
}

double div()
{
	cout<<"Please enter a number..."<<endl;
		cin>> x;
	cout<<"Please enter your second number..."<<endl;
		cin>>y;
	
	dsum = x / y;
	cout<<"The answer is "<<dsum<<endl;

		return dsum;
}

*Edit* Hopefully this helps now Wink | ;)

Michael Dunn11-Jul-03 20:09

Michael Dunn

11-Jul-03 20:09

Hi Fightingbee, welcome to CP. Smile | :)

It's hard to read your code, please edit the post and either wrap your code in a <pre> block, or check the "Display this message as-is (no HTML)" box so spacing is preserved.

From a quick glance, your function calls are wrong.
int add();
is only a prototype, telling the compiler that a function add() exists and returns an int. When you want to call the function, you write
add();

--Mike--
"I'm working really, really fast at the moment, so a 3 minute outage becomes, due to time dilation, a 5 minute outage."
-- Chris Maunder, relativistic system administrator
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Fightingbee11-Jul-03 20:21

Fightingbee

11-Jul-03 20:21

Well I tried pulling the int out of the int add(); and likewise functions ( when they are called and when I am defining them and the compiler threw up about 7 errors at me. So I am not sure exactly what it is I am to do. Big Grin | :-D

Michael P Butler11-Jul-03 21:43

Michael P Butler

11-Jul-03 21:43

Fightingbee wrote:
and the compiler threw up about 7 errors at me.

What errors did you get?

Michael

'War is at best barbarism...Its glory is all moonshine. It is only those who have neither fired a shot nor heard the shrieks and groans of the wounded who cry aloud for blood, more vengeance, more desolation. War is hell.' - General William Sherman, 1879