|
Now I know what I'm doing, I'd do it like this :
//could make it a variable parameter so you don't have to keep supplying
//it with a param when you just want a standard round.
double rounddouble(double val, int fig=0)
{
//Avoid division by zero by checking fig for zero
if(fig != 0)
{
//get the multiply divide factor
double sigfig = pow(10, (double)fig);
//multiply the figure by 10pow to get the pos to chop the end off
val *= sigfig;
//add 0.5 before rounding so we round up or down
val += 0.5;
//adding 0.5 affects round down value in effect, rounding up or down.
val = floor(val);
//return the decimal to original value with chopped off rounded crap
val /= sigfig;
}
else
{
//just round the figure without an offset
val += 0.5;
val = floor(val);
}
//finally return the value
return val;
}
Hope this helps. This will return the correct rounded double value based on however many significant fig's you specify.
Alan.;P
|
|
|
|
|
I think this short scribble should work:
<br />
double round(double x, int digits)<br />
{<br />
double _int = (double)((int)x);<br />
double _pow = pow(10, digits);<br />
double _fract = (x - _int) * _pow;<br />
<br />
return _int + (_fract / _pow);<br />
}<br />
|
|
|
|
|
Very (more that too much) important thing in DCOM-
is to create transparent or easily incorporated
branch to Internet compatible -transports-
for real cases - most DCOM solutions is not workable
due to default firewall security and uneebility to work in
this comditions with not predefined client IE Browser.
That is many methods is possible:
DCOM -SOAP - DCOM
DCOM -SOAP - ELSE STUB like .NET,
due to method proxy-stab is same
(!- in methodology)
but realisation is different.
Just need to connect realisations.
Can you say -
Does such transport proxy stabs exists ?
|
|
|
|
|
I've set CEdit control property as Numeric, but its not accepting decimail.
Any suggesstions , it should accept numbers with decimal.
Warm Regards,
KKRam
|
|
|
|
|
No, it cannot! You'll have to make your own CEdit control. I made one, if you want I can send you the files. Just give me an e-mail adress.
|
|
|
|
|
hi moonen
Thanks for u r reply, u can send it to kamesh.kln@sify.com
Warm Regards,
KKR
|
|
|
|
|
You'll need a masked/formatted edit control. Plenty to pick from here:
http://www.codeproject.com/editctrl/
|
|
|
|
|
Hello all,
I'm having the following problem and can't figure out what's wrong:
the application I'm working on has a View class to print. When I call the OnPrintPreview, it gives a nice preview screen, nothing wrong. When I call the OnPrint, it prints, no problems. However, when I press the 'Print' button in the Preview, it does nothing; it just closes. No printer dialog, no error, nothing.
I find this very strange, obviously the printing code is ok, since it DOES print and it DOES preview. It only doesn't print from the preview screen...
Anyone got a suggestion?
Thanks,
- Fahr
|
|
|
|
|
I'm looking for optimized routines to convert double vectors <--> float vectors, etc. (optionally with non-unit increment)
Any links?
"Dor säggsische Dialeggt eechnet sich wie keeen onderor für den Ausdrugg zäärdlischor Gefiehle."
sighist | Agile Programming | doxygen
|
|
|
|
|
Hello, I am working with Microsoft embedded Visual c++. If I include afx.h in the dll code when I run the main program it fails at the begining, in the code generated by the appwizard. Does somebody know the solution? or it is not allowed including afx.h in a dll?
Thanks
|
|
|
|
|
Hi !
I'd like to do a nightly build of my application. We are several people working on the same project, so we want to compile our work during the night so that in the morning everyone has a 'fresh' application. To do that, we run a script which will use the MSDEV.exe in the command line to build the application. It works fine : I get an executable file. But, if I try to recompile from Visual Studio, using the obj files produced by MSDEV during the nightly build, I get errors telling me that the pdb file are in an obsolete format and the obj files are not readable.
Do you know any workaround for this bug ? How do you do your nightly build ? What I just want is that in the morning when I come to work, I don't have to rebuild all my application !
Thanks for our help !
Jerome
|
|
|
|
|
What's the exact command you are using? I do this all the time and have never seen this. Have you tried doing full rebuilds?
"Sucks less" isn't progress - Kent Beck [^]
Awasu 1.1.1 [^]: A free RSS reader with support for Code Project.
|
|
|
|
|
Taka Muraoka wrote:
What's the exact command you are using?
msdev Sylvie.dsp /MAKE "ALL" /REBUILD /OUT Sylvie.plg
Jerome
|
|
|
|
|
This is what I use:
MSDEV.EXE ".\win32\XXX.dsp" /make all
I've got VC6 SP5 installed. Maybe that has something to do with it...
"Sucks less" isn't progress - Kent Beck [^]
Awasu 1.1.1 [^]: A free RSS reader with support for Code Project.
|
|
|
|
|
Hi i have a dialog box where i have enabled the scroll bars by using the horizontal and vertical scroll bar check boxes in the dialog properties box
my question is how do actualy get the scroll bars so i can control them etc
im not able to give them an id so im not sure what thier ids are thats all i need to know how to get
thanks
|
|
|
|
|
Dialog with scroll bars are BAD.
|
|
|
|
|
Hi guys,
I want to control an IP camera from my program. The IP camera can be controlled through a web browser. Initially I captured the packets ( using Winpcap API calls) going from my machine to the IP camera, and again tried to send those packets to control the camera from my program. ( I established a TCP connection before sending those control packets). I couldn't get the result. Now my doubt is what I did is correct or not. Could any body guide me?? Any links on this may be helpful to me.
Thanks and Regards,
Satya 
|
|
|
|
|
If it is controlled only through browser, it's enough to send correct http requests, which can be easily done by opening tcp connection to the device and sending the request. You should see then in captured data something like GET /image HTTP/1.0 followed by crlf and some set of headers, ended by 2*crlf
If there's some ActiveX or whatever that keeps separate tcp connection there can be a problem, that the protocol inside doesn't allow simple replaying, but I don't see a reason for doing that. Maybe that you just missed something or add some more data or whatever that your protocol differs from the protocol of device.
|
|
|
|
|
Hi
Thanks for ur reply. As you said, the http header is there in the captured packet. But what I did is I sent the data after the http (ended by 2 ctrlf) thinking as that payload is having the control signal. Beacause when I captured packets (in four directions top,left,bottom,right) they are differing only in the content after the http header.
So what I can do, any clues??
Regards,
SatyaDY
|
|
|
|
|
Hmm then I assume that the header contains POST on beginning and these are the POST data. Then there's only one URL and the 'commands' are transferred to the camera inside the POST data.
I think, that if you try to do left, left, left, capture the packets, and these three packets doesn't differ in their content, you have to do something wrong in your sending side - try to capture your packets as well and compare the data at this binary level with originally captured 'left command'
If the data in these three commands differ, it will be much more difficult, because then you have really to hack the protocol. Even that can be done, but before I'd recommend to contact the vendor asking for the description. They are usually willing to do it, if you're doing something serious with that hw - like integrating that to your application or whatever.
We'll see what it will do 
|
|
|
|
|
Hi,
I could not understand what u told, sorry. Can U explain in detail??
I am trying to integrate this IP camera to my existing application, which plots the path of a falling object whose coordinates(x,y,z) are given by radars. I just want control this IP camera to track the falling object from the inputs given by the radars in addtion to plotting it on bitmap, so that people can view the object with their web browsers.
Thanks a lot for ur help.
Regards,
SatyaDY
|
|
|
|
|
well, so again
I would check this:
- send and capture 3x left command sent from webbrowser.
- compare these captured packet, if they are the same
- if yes, construct my packet (the same as the original)
- send it and capture it
- compare my captured packet with original captured, shouldn't differ
if the three packets generated by the 3x left commands differs in a data section, this will be more complicated to do and first think I would do is to contact the vendor of the hardware to get the protocol
|
|
|
|
|
Hi again,
I have given the 3 left commands, and saw the packets.
The packets details are like this:
One command is having the following packets twice.
1.368 byte packet (with http header)(from my pc to IP camera)
2.60 byte packet (without http header)(from IP camera to mypc)
3.121 byte packet(with http header)(from IP camera to mypc)
And there is a change in the payload of 368 byte packet.
I thought, the first 368 is the control signal, 60 is the ack, and this 121 I could not guess?? What it could be?? Any guess.
Thanks again,
SatyaDY
|
|
|
|
|
Normally the ACK should be only on TCP level, therefore every data you receive are supposed to be delivered to the application. For that reason I assume that there must be something that understands the data returned back.
How about content of the control packets (PC to IPcam) - does it changes between the three left commands?
|
|
|
|
|
Yeah you right it's not pure browser it's opening an applet for viewing the picture and one more for showing the controls.
As I told the control(left) is sending sequence of 368,60,121 byte packets. For one control(left button) it is sending two sets of the above sequence. And the 368 byte packet is having only one byte change in the payload(that is after the http content).
Satya
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
