Why I cant retreive image from database via php?

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1.80/5 (2 votes)

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This is my code. Could you correct? Thanks in advance.

XML

<?php
echo <<<_END
<DOCTYPE html><html><head><meta charset="utf-8"></head>
_END;

require_once'login.php';
$connection=new mysqli($db_hostname, $db_username, $db_password, $db_database);

if($connection->connect_error) die($connection->connect_error);

if (
    isset($_POST['title'])&&
    isset($_POST['category'])&&
    isset($_POST['name'])&&
    isset($_POST['telno'])&&
    isset($_POST['price'])&&
    isset($_POST['info']))
{
    $title=get_post($connection, 'title');
    $category=get_post($connection, 'category');
    $name=get_post($connection,'name');
    $telno=get_post($connection,'telno');
    $price=get_post($connection,'price');
    $info=get_post($connection,'info');

        if (is_uploaded_file($_FILES['img1']['tmp_name']))
    {

                $imgData=addslashes(file_get_contents($_FILES['img1']['tmp_name']));
                    $query="INSERT INTO avto(title, category, img1,  name, telno, price, info) VALUES" .
                    "('$title', '$category', '$imgData',  '$name', '$telno', '$price', '$info')";

                $result = $connection->query($query);

                if(!$result)
                    echo "Кушиб булмаяпти: $query<br>".
                    $connect_error. "<br><br>";

    }


}

echo <<<_END
    <form action="index.php" method="post" enctype="multipart/form-data"><pre>
    Title <input type="text" name="title">
    Category <input type="text" name="category">
    Main img <input type='file' name='img1' >

    Name <input type="text" name="name">
    Tel NO <input type="text" name="telno">
    Price <input type="text" name="price">
    Info <textarea rows="6" cols="30" name="info"></textarea>
    <input type="submit" value="Submit">
    </pre></form>
_END;


$query="SELECT * FROM avto";
$result=$connection->query($query);

If (!$result) die ($connection->error);
$rows=$result->num_rows;

for ($j=0;$j<$rows;++$j)
{
$result->data_seek($j);
$row=$result->fetch_array(MYSQLI_NUM);

    echo <<<_END
        <pre>
        $row[0]
        $row[1]
        $row[2]
        $row[3]
        $row[9]
        $row[10]
        $row[11]
        $row[12]
        $row[13]
        </pre>
_END;
}
$result->close();
$connection->close();
function get_post($connection, $var)
{
    return $connection->real_escape_string($_POST[$var]);
}
echo <<<_END
</html>
_END;
?>

Posted 24-Jun-15 18:42pm

Shamsiddin Muhibillayev

Updated 24-Jun-15 18:46pm

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3 solutions

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Arthur V. Ratz · Answer 1 · 2015-06-24T20:01:00

XML

<?php
echo <<<_END
<DOCTYPE html><html><head><meta charset="utf-8"></head>
_END;

require_once'login.php';
$connection=new mysqli($db_hostname, $db_username, $db_password, $db_database);

if($connection->connect_error) die($connection->connect_error);

if (
    isset($_POST['title'])&&
    isset($_POST['category'])&&
    isset($_POST['name'])&&
    isset($_POST['telno'])&&
    isset($_POST['price'])&&
    isset($_POST['info']))
{
    $title=get_post($connection, 'title');
    $category=get_post($connection, 'category');
    $name=get_post($connection,'name');
    $telno=get_post($connection,'telno');
    $price=get_post($connection,'price');
    $info=get_post($connection,'info');


    $img=addslashes(file_get_contents($_FILES['img1']['name']));
    $img_name=addslashes(file_get_contents($_FILES['img1']['tmp_name']));
    $img_data=file_get_contents($img_name);
    $img_data=base64_encode($img_data);
    if (is_uploaded_file($_FILES['img1']['tmp_name']) != FALSE)
    {
                    $query="INSERT INTO avto(title, category, img1,  name, telno, price, info) VALUES".
                    "('$title', '$category', '$img_data', '$name', '$telno', '$price', '$info')";

                $result = $connection->query($query);

                if(!$result)
                    echo "Кушиб булмаяпти: $query<br>".
                    $connect_error. "<br><br>";

    }


}

echo <<<_END
    <form action="index.php" method="post" enctype="multipart/form-data"><pre>
    Title <input type="text" name="title">
    Category <input type="text" name="category">
    Main img <input type="file" name="img1" >

    Name <input type="text" name="name">
    Tel NO <input type="text" name="telno">
    Price <input type="text" name="price">
    Info <textarea rows="6" cols="30" name="info"></textarea>
    <input type="submit" value="Submit">
    </pre></form>
_END;


$query="SELECT * FROM avto";
$result=$connection->query($query);

If (!$result) die ($connection->error);
$rows=$result->num_rows;

for ($j=0;$j<$rows;++$j)
{
$result->data_seek($j);
$row=$result->fetch_array($result, MYSQLI_BOTH);

  echo "<img width=320 height=200 src='data:image;base64,'".$row[2]."'></img>";
}
$result->close();
$connection->close();
function get_post($connection, $var)
{
    return $connection->real_escape_string($_POST[$var]);
}
echo <<<_END
</html>
_END;
?>

Shamsiddin Muhibillayev · Answer 2 · 2015-06-27T18:23:00

Solution 2

Arthur V. Ratz I tried your code but it did not work
It shows this http://img.uz/s?a4hbh0d[^]

Posted 27-Jun-15 18:23pm

Shamsiddin Muhibillayev

Arthur V. Ratz · Answer 3 · 2015-06-28T12:48:00

I'm sorry for that code above that occasionally is not working :)
This one should exactly work:

HTML

<html><head><meta charset="utf-8"></head>

if (
    isset($_POST['title'])&&
    isset($_POST['category'])&&
    isset($_POST['name'])&&
    isset($_POST['telno'])&&
    isset($_POST['price'])&&
    isset($_POST['info']))
{

$connection=new mysqli($db_hostname, $db_username, $db_password, $db_database);
 
if($connection->connect_error) die($connection->connect_error);

    $title = $_POST['title'];
    $category = $_POST['category'];
    $name = $_POST['name'];
    $telno = $_POST['telno'];
    $price = $_POST['price'];
    $info = $_POST['info'];
 

    if (($img_data = file_get_contents($_FILES['img1']['tmp_name'])) && 
        is_uploaded_file($_FILES['img1']['tmp_name']))
    {
                $query="INSERT INTO avto (title, category, img1, name, telno, price, info) 
				VALUES ('$title', '$category', '".base64_encode($img_data)."', 
                                  '$name', '$telno', '$price', '$info')";
                $result = $connection->query($query);
                if(!$result) echo "Кушиб булмаяпти: $query<br>";
 
    }

    $query="SELECT * FROM avto";
    $result=$connection->query($query);
 
    If (!$result) die ($connection->error);
    $rows=$result->num_rows;
 
    for ($j=0;$j<$rows;++$j)
    {
         $result->data_seek($j);
         $row=$result->fetch_array(MYSQLI_BOTH);
         echo "<img src="data:image/gif;base64,".$row[3].""></img>";
    }
    
    $result->close();
    $connection->close();

    function get_post($connection, $var)
    {
        return $connection->real_escape_string($_POST[$var]);
    } 
}?>
    <form action="index.php" method="post" enctype="multipart/form-data">
    Title <input type="text" name="title">
    Category <input type="text" name="category">
    Main img <input type="file" name="img1" >
 
    Name <input type="text" name="name">
    Tel NO <input type="text" name="telno">
    Price <input type="text" name="price">
    Info <textarea rows="6" cols="30" name="info"></textarea>
    <input type="submit" value="Submit">
    </form>
</html>

Here's the sql dump for the database this code is working with:

SQL

-- --------------------------------------------------------
-- Хост:                         127.0.0.1
-- Версия сервера:               5.6.25-log - MySQL Community Server (GPL)
-- ОС Сервера:                   Win64
-- HeidiSQL Версия:              9.2.0.4947
-- --------------------------------------------------------

/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET NAMES utf8mb4 */;
/*!40014 SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0 */;
/*!40101 SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO' */;

-- Дамп структуры базы данных images
CREATE DATABASE IF NOT EXISTS `images` /*!40100 DEFAULT CHARACTER SET utf8 */;
USE `images`;


-- Дамп структуры для таблица images.avto
CREATE TABLE IF NOT EXISTS `avto` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `title` varchar(50) NOT NULL,
  `category` varchar(50) NOT NULL,
  `img1` longblob NOT NULL,
  `name` varchar(50) NOT NULL,
  `telno` varchar(50) NOT NULL,
  `price` varchar(50) NOT NULL,
  `info` varchar(50) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=11 DEFAULT CHARSET=utf8;

-- Дамп данных таблицы images.avto: ~0 rows (приблизительно)
/*!40000 ALTER TABLE `avto` DISABLE KEYS */;
/*!40000 ALTER TABLE `avto` ENABLE KEYS */;
/*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, '') */;
/*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */;
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;

P.S. Don't forget to specify the correct path to the temporary files uploaded in php.ini:
file_uploads = On
upload_tmp_dir = h:\temp

Why I cant retreive image from database via php?

3 solutions

Solution 1

Solution 2

Solution 3

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