How Do I Convert Wchar_T To Lpwstr

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1.80/5 (2 votes)

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Hi,
My code snippet looks like this.

C++

typedef char* PSTRING;

LPWSTR   usri1_name;
wchar_t  ws[100];

PSTRING createUserVar = NULL;

/*"createUserVar"  is assigned with some value*/
/*Converting PSTRING to wchar_t */
swprintf(ws, 100, L"%hs", createUserVar);

Now i need to assign ws value to usri1_name but i am not getting how to convert it.
Please let me know your suggestion on this.

different ways of doing this also welcomed.

code is written in c

Posted 26-Jun-15 4:12am

Darshan VC

Updated 27-Jul-20 14:48pm

Leo Chapiro

v2

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3 solutions

Solution 2

As WCHAR is actually wchar_t and LPCWSTR is actually wchar_t const*, you can do simple:

C++

usri1_name = ws;

Posted 26-Jun-15 4:39am

Leo Chapiro

Comments

Sergey Alexandrovich Kryukov 26-Jun-15 11:03am

5ed.
—SA

Leo Chapiro 26-Jun-15 13:37pm

Thank you, Sergey :)

Solution 3

I think both of the answers miss an important point, which is that you must ensure that the character following the last character that you want to be part of the string must be NULL (0x00). Otherwise, you risk a buffer overrun when your code searches for the end of the string, and runs off the end of your 100 character array.

Posted 29-Jun-15 6:46am

David A. Gray

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Jochen Arndt · Accepted Answer · 2015-06-26T04:39:00

There is no need for a conversion. LPWSTR is a pointer to a wide string and ws is an array of wide characters. So you can just write:

C++

usri1_name = ws;

But you must take care of the memory pointed to by usri1_name. The pointer will become invalid when ws goes out of scope (e.g. when leaving the function or block where ws is defined). Then you must allocate memory on the heap using new or malloc for usri1_name, copy the content of ws into it, and release the memory when no longer needed.