How to generate 1000 random numbers between 1 and 500, and find minimum, maximum and average?

Question

1.00/5 (1 vote)

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C#

using System;

public class Test
{
	public static void Main()
	{
		Random myRandom = new Random(1, 1001);
        int A = new int[1000];
        int i = 0;

        While (i < 1001) 
        
        A[i] = myRandom.Next(1, 501);
        i ++;
        }
        
		int output1 = Math.Min(i); 
		Console.WriteLine("The minimum number is: " + output1);
		
		int output2 = Math.Max(i);
		Console.WriteLine("The maximum number is: " + output2);
		
		int output3 = Average(params int[] A);
		Console.WriteLine("The average of these numbers is: " + output3);
    
        }
	public static int Math.Min(int i) //To calculate the minimum//
	{
    	        int answer = i;
      	        return answer;
	}
	
	public static int Math.Max(int i) //To calculate the maximum//
	{
		int answer = i;
		return answer;
	}
	
	public decimal Average(params int[] A) //To calculate the average//
        {
    	 	
                int sum = Sum(A);
                decimal result = (decimal)sum / A.Length;
                return result;
     
        }
	}

}

Posted 23-Jul-15 9:58am

Member 11858958

Updated 23-Jul-15 10:26am

v5

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Comments

[no name] 23-Jul-15 16:16pm

Just dumping a bunch of unreadable unformatted code into a posting is not a question.

3 solutions

Solution 2

C#

using System;

public class Test
{
    public static void Main()
    {
        const int NUMBERS = 1000;
        Random myRandom = new Random();
        int [] a = new int[NUMBERS];

        int i = 0;
        int max = int.MinValue, min = int.MaxValue, sum = 0;

        while (i < NUMBERS)
        {
          a[i] = myRandom.Next(1, 501);
          if (max < a[i]) max = a[i];
          if (min > a[i]) min = a[i];
          sum += a[i];
          ++i;
        }
        double avg = (double)sum / NUMBERS;


        Console.WriteLine("The minimum number is: {0}", min );
        Console.WriteLine("The maximum number is: {0}", max);
        Console.WriteLine("The average of these numbers is: {0}", avg);

  }
    public static int find_min(int[] a)
    {
        int min = int.MaxValue;
        for (int n = 0; n < a.Length; ++n)
    {
        if (min > a[n]) min = a[n];
    }
        return min;
    }

    public static int find_max(int[] a)
    {
        int max = int.MinValue;
        for (int n = 0; n < a.Length; ++n)
        {
        if (max < a[n]) max = a[n];
        }
        return max;
    }

    public static double find_sum(int[] a)
    {
        sum = 0;
        double avg = (double)sum / NUMBERS;
        for (int n = 0; n < a.Length; ++n)
        {
            sum += a[n];
        }
        return avg;
    }
}

Posted 24-Jul-15 23:42pm

Member 11858958

Solution 3

C#

int average = 0;
int largestNumber = 0;
int smallestNumber = int.MaxValue;
int _avr = 0;
int index = 0;

while (index < 1000)
{
    byte[] ba = new byte[4];
    RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider();
    rng.GetBytes(ba);
    int n2 = BitConverter.ToInt32(ba, 0);

    Random rd = new Random(n2);
    int n = rd.Next(1, 501);

    if (n > largestNumber)
        largestNumber = n;
    if (n < smallestNumber)
        smallestNumber = n;
    _avr = _avr + n;

    index++;
}

average = _avr / 1000;

Posted 25-Jul-15 4:08am

adriancs

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CPallini · Accepted Answer · 2015-07-23T10:32:00

You possibly meant

C#

using System;

public class Test
{
    public static void Main()
    {
        const int NUMBERS = 1000;
        Random myRandom = new Random();
        int [] a = new int[NUMBERS];

        int i = 0;
        int max = int.MinValue, min = int.MaxValue, sum = 0;

        while (i < NUMBERS)
        {
          a[i] = myRandom.Next(1, 501);
          if (max < a[i]) max = a[i];
          if (min > a[i]) min = a[i];
          sum += a[i];
          ++i;
        }
        double avg = (double)sum / NUMBERS;


        Console.WriteLine("The minimum number is: {0}", min );
        Console.WriteLine("The maximum number is: {0}", max);
        Console.WriteLine("The average of these numbers is: {0}", avg);

  }
}

Please note you actually don't need to store the extracted numbers in the array in order to compute minimum, maximum and average.

[Update]

Quote:
Thanks for the advice, and the solution, really helpful. I was wondering how I would go about putting the commands for finding the minimum, maximum and average of the numbers in different methods?

Then the essential modification is you need to pass the array to the relevant method, e.g.

C#

public static int find_min(int[] a)
{
  int min = int.MaxValue;

  for (int n = 0; n < a.Length; ++n)
  {
    if (min > a[n]) min = a[n];
  }
  return min;
}

[/Update]