how to divide the numbers?

Question

0.00/5 (No votes)

See more:

Dear All,

I am using vs2010 with c# language.I am go to divide a two number i can't get the Expected output.I am using Following Coding.

Int32 tmpcnt = 0;
Double totalHours ;

tmpcnt=105094;

totalHours = tmpcnt / 60000;

I expect the answer is 1.75 but i get the answer is 1.0 only any tell me what is my mistake or give the solution.

thaks advance!....

Posted 29-Sep-15 1:28am

Member 11889799

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

phil.o · Accepted Answer · 2015-09-29T01:42:00

Solution 1

You are using an integer division (in the line totalHours = tmpcnt / 60000;, both tmpcnt variable and 60000 constant are integers.
Thus, you get the integer division result.

If you want a real division, you should use double type for at least one of the operands.
For example:

C#

totalHours = tmpcnt / 60000d;
// OR
totalHours = tmpcnt / 60000.0;

This will give you expected result.

Posted 29-Sep-15 1:42am

phil.o

v2

Comments

Krunal Rohit 29-Sep-15 7:48am

Yeah. 5!

-KR

phil.o 29-Sep-15 7:51am

Thanks :)

Andy Lanng · Accepted Answer · 2015-09-29T01:43:00

You can cast an int to a double and a double to an int. Int to double is loss-less but double to int will lose precision. it will round down.

tmpcmt / 60000 is int / int so the result will be int. The result will be rounded down.

To change this, just make one number or the other not an int. The equation will try to keep the most precision.

tmpcmt / 60000.0 is now int / double which will keep the double precision.

In other cases you may need to cast:

int myint = 60000
tmpcmt / (double)myint

Hope that helps ^_^
Andy