Upload multiple file in asp.net c#

Question

1.00/5 (1 vote)

See more:

Hi,
I want to upload multiple image file just like 10,100,200 or 400 image file upload one time in asp.net project folder(folder name "Images").

Posted 8-Nov-15 0:56am

Ram jha

Add a Solution

Comments

Afzaal Ahmad Zeeshan 8-Nov-15 7:07am

Why?

If you upload an image, like of 1MB size, then even just 10 images would cause the request to have 10MB of data. Users with slow internet connection would lose the process and upload would be cancelled.

Now, the answer is, you can upload as many images as you want. Just increase the maximum HTTP request size and upload the images you want.

3 solutions

Solution 1

Google is your friend: Be nice and visit him often. He can answer questions a lot more quickly than posting them here...

A very quick search gave over half a million hits: Google "multiple image file upload in asp.net c#"[^]
On teh first page was an article from this very site: Upload multiple files in asp.net[^]

In future, please try to do at least basic research yourself, and not waste your time or ours.

Posted 8-Nov-15 1:30am

OriginalGriff

Solution 2

Agreed with the comment.

You need to create the chunks of these files and upload it using Worker (JavaScript solution).
Search for for the concepts.

-KR

Posted 8-Nov-15 1:36am

Krunal Rohit

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sanjeev Maurya · Accepted Answer · 2015-11-16T01:05:00

use uploadify

use jquery.uploadify.js, jquery-1.3.2.min.js,uploadify.css

XML

<asp:FileUpload ID="file_upload" runat="server" />
                         (Upload Multiple File Required Flash Player)

<a href="javascript:$('#<%=file_upload.ClientID%>').fileUploadStart()" class="bttnPage">Start Upload</a>
use this in below of your code
<script type = "text/javascript">
    $(window).load(
    function () {
        $("#<%=file_upload.ClientID %>").fileUpload({
            'uploader': 'scripts/uploader.swf',
            'cancelImg': 'images/cancel.png',
            'buttonText': 'Browse Files',
            'script': 'upload_demo.ashx',
            'folder': '~/demo_pdf/',
            'fileDesc': 'Pdf Files',
            'fileExt': '*.pdf',
            'multi': true,
            'auto': false
        });
    }
);
</script>


Create Handler upload_demo.ashx

public void ProcessRequest(HttpContext context)
    {
        context.Response.ContentType = "text/plain";
        context.Response.Expires = -1;
        try
        {
            HttpPostedFile postedFile = context.Request.Files["Filedata"];

            string savepath = "";
            string tempPath = "";
            tempPath = "~/demo_pdf/";
            savepath = context.Server.MapPath(tempPath);
            string filename = postedFile.FileName;
            if (!Directory.Exists(savepath))
                Directory.CreateDirectory(savepath);

            postedFile.SaveAs(savepath + @"\" + filename);
            context.Response.Write(tempPath + "/" + filename);
            context.Response.StatusCode = 200;
        }
        catch (Exception ex)
        {
            context.Response.Write("Error: " + ex.Message);
        }
    }