Equivalent code without the library

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I used a tutorial to get the following ajax code. In the tutorial, they have the library jquery.form.js. Here is the code:

JavaScript

function onsuccess(response,status){
    $("#onsuccessmsg").html(response);
        alert(response);
    }
    $("#uploadform").on('change',function(){
        var options={
        url     : $(this).attr("action"),
        success : onsuccess
    };
    $(this).ajaxSubmit(options);
        return false;
});

What if I don't want to have jquery.form.js implemented. What would be the equivalent code with normal ajax (without the library)?

Posted 10-Nov-15 19:45pm

Member 11360293

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Krunal Rohit · Answer 1 · 2015-11-10T20:23:00

This code looks like a form-submission and callback after that.
Yeah, you can do it without using that library.

JavaScript

$("#yourForm").submit(function() {
    $.ajax({
        url: $(this).attr("action"),
        data: $(this).serialize(),
        cache: false,
        success: function(response){
            $("#onsuccessmsg").html(response);
        },
        error: function(xhr){
            $("#onsuccessmsg").html(xhr.responseText);
        }
    });
});

-KR