Get Hour & Time in SQL

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SQL-Server-2008R2

Dear

In my table I have two Column Start & End both Data Type is datetime.

I want to get the hour and time.

I used this one for hour

DATEDIFF(hour,Dr_TimeStart,Dr_TimeEnd)

I got the hour. But when the Start and End column data are less then hour means time, Start is 0:00 and End 0:15 then return hour is 0

that's why i used min

DATEDIFF(mi,Dr_TimeStart,Dr_TimeEnd)

then i used the case

case when DATEDIFF(hh, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd) > 0 then DATEDIFF(hh, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd) else DATEDIFF(mi, dbo.Trn_Daily3.Dr_TimeStart, dbo.Trn_Daily3.Dr_TimeEnd) / 60 end

What i want is

I want to show the hour and time

Please help on this

Thanks
Basit.

Posted 18-Nov-15 19:21pm

basitsar

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Naveen.Sanagasetti · Accepted Answer · 2015-11-18T19:41:00

Solution 1

Try like below,

SQL

DECLARE @StartDate DATETIME;
DECLARE @EndDate DATETIME;

SET @StartDate = '2015-11-18 00:00:16';

SET @EndDate = '2015-11-18 00:55:36';

select CONVERT(varchar(10), DATEDIFF(HOUR,@StartDate,@EndDate)) +':'+CONVERT(varchar(10), DATEDIFF(MINUTE,@StartDate,@EndDate)%60 )

Posted 18-Nov-15 19:41pm

Naveen.Sanagasetti

Comments

basitsar 19-Nov-15 2:07am

Many Thanks Dear, Perfect.

basitsar 19-Nov-15 2:11am

Another thing dear, how to get the sum of that difference?

select CONVERT(varchar(10), DATEDIFF(HOUR,@StartDate,@EndDate)) +':'+CONVERT(varchar(10), DATEDIFF(MINUTE,@StartDate,@EndDate)%60 ) as DifferenceHour

Means how to get the sum of DifferenceHour column.