alphanumeric validation javascript without regex

Question

1.00/5 (2 votes)

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if i run, validation just can be work only on symbol "/", if I input the other symbol except / didnt working. I'm not use regex. loop like stop work.

JavaScript

if(nama!==""){
var i;
var list = new Array ("/","!", "@", "#","$","%","%","^","&","*",
                      "(",")","_","+","=","-","`","~",";","<",
                      ">",".","?","[","]","{","}",",");

var llength = list.length;
for(i=0; i<llength;>{
    if(nama.match(list[i]))
    {
        alert("Full Name must not contain any number and symbol");
        return false;
    }

}
}

Posted 9-Dec-15 6:49am

Member 12196709

Updated 9-Dec-15 7:42am

Suvendu Shekhar Giri

v2

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Comments

Sergey Alexandrovich Kryukov 9-Dec-15 14:32pm

This is not a correct question. You need to formally define the rule. In particular, there are a lot more "symbols" (what is it, precisely? :-) then what you listed.
—SA

2 solutions

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Suvendu Shekhar Giri · Answer 1 · 2015-12-09T08:15:00

Solution 2

Why not a simple Regex?
Try this-

JavaScript

if(nama!==""){
  var regex= /^[a-zA-Z]+$/;  
  if(! nama.value.match(regex)){  
     alert("Full Name must not contain any number and symbol");
     return false;
  }
}

Isn't that very simple !

Note:
1. You are saying you are not using regex but, .match() actually match against a regular expression.

Quote:
The match() method searches a string for a match against a regular expression, and returns the matches, as an Array object.

Reference: JavaScript String match() Method[^]
2. You are saying you want to allow alphanumeric but from your alert message it looks like you want to allow only the characters.

Hope, it helps :)

Posted 9-Dec-15 8:15am

Suvendu Shekhar Giri

Updated 9-Dec-15 8:36am

v4

Comments

Sergey Alexandrovich Kryukov 9-Dec-15 14:30pm

I voted 4. The problem your code has is not entirely your fault — the inquirer did not correctly formulate the validation rule.
It's amazing how many our inquirers try Regex processing where it is totally unsuitable, even insist on using (misusing) it, and yet some deny using Regext when it's the easiest way.

So, the problem is, the inquirer's "Full Name must not contain any number and symbol" does not imply that the valid characters are letters. But even it they were letters, you listed only a-z and A-Z, but there are a lot more letters. If allowing only the letters, the right implementation should be, again, not Regex, but based on the method char.IsLetter.

—SA

Suvendu Shekhar Giri 9-Dec-15 14:41pm

(bow) Agree. Can you please post the same as a solution so that OP and others can be benefited.

Sergey Alexandrovich Kryukov 9-Dec-15 14:56pm

I would prefer to wait until the inquirer clarifies the validation criteria.
—SA

Rajdeep Debnath · Answer 2 · 2015-12-09T07:41:00

Solution 1

Please try the below...

C#

var a = '09azAZ!'
var t = '';

alert(a);

for(i=0;i<a.length;i++)
{
	t = a.charCodeAt(i);
		//alert(t);
	if((t<48) || ((t>57) && (t<65)) || ((t>90) && (t<97)) || (t>122))
	{
		alert('Not alphanumeric: ' + a.charAt(i));
		//return;
	}
}

Posted 9-Dec-15 7:41am

Rajdeep Debnath