why we made a pointer of char , double and float. ? if the pointer holds the adress.. doesnt matter it is float or char ?

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clear me plz. bcoz if pointer holds an adress so doesnot matter it is the adress of char , int or float.

Posted 11-Jan-16 20:44pm

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Afzaal Ahmad Zeeshan 12-Jan-16 3:08am

Pointer to a char, means that it is a pointer to a value of character type. Pointer are usually integer type (because address is a hexadecimal value).

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CPallini · Accepted Answer · 2016-01-11T21:02:00

Solution 2

It matters because of pointer arithmetic (see, for instance "C++ pointer arithmetic"[^]). Try:

C

#include <stdio.h>

int main()
{
  double d = 5.0;
  double * pd;
  char * pc;

  pd = &d;
  pc = (char *) &d;

  printf("pd = %p, pc = %p\n", pd, pc); // same address, here
  ++pd;
  ++pc;
  printf("pd = %p, pc = %p\n", pd, pc); // OOOPS!

  return 0;
}

Posted 11-Jan-16 21:02pm

CPallini

Updated 11-Jan-16 21:04pm

v3

Comments

Afzaal Ahmad Zeeshan 12-Jan-16 3:08am

Good point, you've raised. 5ed.

CPallini 12-Jan-16 3:12am

Thank you.

Kornfeld Eliyahu Peter · Accepted Answer · 2016-01-11T20:58:00

Solution 1

Whenever you reference a memory address, you have to decide how to interpret the data you find there, that's the meaning of the pointer-type, and type at all...
(There are languages where you do not define type and the environment will decide for you how to interpret that type - with occasional errors)
You should read here: Pointers - C++ Tutorials[^]

Posted 11-Jan-16 20:58pm

Kornfeld Eliyahu Peter

Comments

Afzaal Ahmad Zeeshan 12-Jan-16 3:08am

5ed.