Using regex to select the brackets

Question

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Goal:
If the data inside of the "(" + ")" contains data that is alphabet and included brackets, then it is true.

However if it contain data that is any number, included brackets, then it will be false.

Problem:
I don't know how to solve it in relation to including brackets.

http://regexr.com/3d0dh
By reviewing the code, the selection does not include the brackets

Thank you!

C#

sdf (ff)
answer: true

dddd (335g) ddd
answer: false

sdf(f344f) 21ff
answer: false

sdf(dd) 433dd
answer: true

What I have tried:

I have coded the regex code and I also have made some research but unfortunatly I still cannot find the answer or part of the answer.

Posted 13-Mar-16 12:03pm

Heelloo

Updated 13-Mar-16 15:50pm

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Comments

Garth J Lancaster 13-Mar-16 20:25pm

you havnt posted any relevant code - what expression(s) are you using for example ? in general, you would include brackets in your regular expression by escaping them - eg

"\(\w*\)"

would match any word character [A-Za-z0-9_] zero or more times and include brackets ... there's a nice regex cheat-sheet here http://www.mikesdotnetting.com/article/46/c-regular-expressions-cheat-sheet and there are also tools online to test regexes http://regexstorm.net/tester for one example

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Peter Leow · Answer 1 · 2016-03-13T15:50:00

Solution 1

Try this:

\([a-zA-Z]+\)

Learn: The 30 Minute Regex Tutorial[^]

Posted 13-Mar-16 15:50pm

Peter Leow

Updated 13-Mar-16 15:51pm

v2