Failure in looping a statement (Python)

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q_3 = raw_input("Choose 1 or 2 or 3") #The question leave 3 options, only one to complete the process
			if q_3 == "1":
				print ("Wrong!") #Now its wrong number, should start all over again until the user choose 3
			
			elif q_3 == "2":
					print ("Wrong") #This is also a wrong number, should start all over again until the user choose 3
			
			elif q_3 == "3":
				print ("Correct") #This is now the right number I can handle it from here ! :)

What I have tried:

I tried to "while True" loop but I had much more errors to deal with.
The idea is simple: 3 options, one right... if wrong answer picked, back all over again... if right answer picked, I call raw_input for another question

Posted 28-Aug-16 1:04am

Member 12707345

Updated 28-Aug-16 2:02am

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Patrice T 28-Aug-16 7:11am

There is no loop in this code.
what are errors you have to deal with ?

Member 12707345 28-Aug-16 7:24am

no i deleted them, correct me if i'm wrong it suppose to be like :

def question():
while True
q_3 = raw_input("Choose 1 or 2 or 3") #The question leave 3 options, only one to complete the process
if q_3 == "1":
print ("Wrong!") #Now its wrong number, should start all over again until the user choose 3
return True
elif q_3 == "2":
print ("Wrong") #This is also a wrong number, should start all over again until the user choose 3
return True
elif q_3 == "3":
print ("Correct") #This is now the right number I can handle it from here ! :)
question()
question()

[no name] 28-Aug-16 7:26am

Typecast your input first to integer then check for the condition. Adding brackets in the condition will make the code cleaner!

Patrice T 28-Aug-16 7:40am

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Richard MacCutchan · Answer 1 · 2016-08-28T02:02:00

This should work:

Python

while True:
    q_3 = raw_input("Choose 1 or 2 or 3") #The question leave 3 options, only one to complete the process
    if q_3 == "1":
        print ("Wrong!") #Now its wrong number, should start all over again until the user choose 3
			
    elif q_3 == "2":
        print ("Wrong") #This is also a wrong number, should start all over again until the user choose 3
			
    elif q_3 == "3":
        print ("Correct") #This is now the right number I can handle it from here ! :)
        break